Quant Test for IBPS Clerk 2018 Main Exam Set – 5

Directions(1-5): Find the missing term “?” of the following series.

1. 7,7,?,13,19,27
   5
   7
   9
   10
   8
   Option C
   +0,+2,+4,+6,+8
   ? = 9

    

2. 7,9,15,?,87,249
   20
   28
   15
   33
   24
   Option D
   Multiple of 3.
   ? = 33

    

3. 12,17,7,?,2,27,-3
   18
   20
   15
   10
   22
   Option E
   +5*1
   -5*2
   +5*3
   -5*4
   +5*5
   -5*6
   ? =22

    

4. 9,73,241,561,1081,?
   1800
   1778
   1640
   1849
   1809
   Option D
   1^2 + 2^3
   3^2 + 4^3
   5^2 + 6^3
   7^2 + 8^3
   9^2 + 10^3
   11^2 + 12^3
   ? = 1849

    

5. 19,28,?,100,163,244
   55
   42
   59
   35
   44
   Option A
   +(9*1)
   +(9*3)
   +(9*5)
   +(9*7)
   +(9*9)
   ? = 55

    

Directions(6-10): Compare quantity I and II and choose a required option.

6. Quantity I: The respective ratio of the present age of X and Y is 6:11. After 6 years , the respective ratio of age of Y and X will become 5:3. If R who is 8 years older than X is married to a girl who is 16 years younger to Y , then find the difference between the age of R and his wife.
   Quantity II: M is 2 years older than N and the difference between the age of M and S is 3 years. If age of N is 5 years , then find the age of S.
   Quantity I = Quantity II
   Quantity I > Quantity II
   Quantity I >= Quantity II
   Quantity I < Quantity II
   Quantity I =< Quantity II
   Option
   From I:
   Let present age of X and Y be 6x and 11x resp.
   (6x+6)/(11x+6) = 3/5
   => x = 4
   Age of R = 6x+8 = 32 years
   Age of R’s wife = 11x – 16 = 28 years
   Required Difference = 4 years
   From II:
   Age of M = 7 years
   Age of S will be either 4 years or 10 years.
   Quantity I =< Quantity II

    

7. Quantity I: Find the value of x = (5*6+434/14-19)
   Quantity II: The product of two numbers is 10548 and their LCM is 252. Find the HCF of the numbers
   Quantity I > Quantity II
   Quantity I >= Quantity II
   Quantity I < Quantity II
   Quantity I = Quantity II
   Quantity I =< Quantity II
   Option D
   From I:
   x = 42
   From II:
   Product of two numbers =LCM*HCF
   => 10548 = 252*HCF
   => HCF = 42
   Quantity I = Quantity II

    

8. Quantity I: Anita was travelling from point A to B. He increased his speed by 4km/hr. after every hour. He reached his destination in 8 hours and his initial speed was 50km/hr. What was the average speed of Anita in her journey?
   Quantity II: A train of length x metre crosses a boy in 19 seconds and y metre long platform in 47 seconds. Find the speed of train if (x-y) = 180 metre.
   Quantity I >= Quantity II
   Quantity I > Quantity II
   Quantity I < Quantity II
   Quantity I =< Quantity II
   Quantity I = Quantity II
   Option C
   From I:
   (8/2)*{2*50+(8-1)*4} = 512 km
   Average speed = 512/8 = 64 km/hr.
   From II:
   (x+y)/(y/19) = 47
   => y = 28x/19
   Also, y-x = 180
   => (28x/19) – x = 180
   => x = 380
   Speed of train = 380/19 = 72 km/hr
   Quantity I < Quantity II

    

9. Quantity I: A and B together started a business with initial investment of Rs. (x+600) and Rs. (y+400). After a year , A and B increased their investments by Rs. 600 and Rs. 800 resp. At the end of 2 years, A received Rs. 840 as profit out of total profit of Rs. 1500. Find the value of x if (y+800) = 1100.
   Quantity II: Rs. 600
   Quantity I < Quantity II
   Quantity I = Quantity II
   Quantity I >= Quantity II
   Quantity I =< Quantity II
   Quantity I > Quantity II
   Option A
   From I:
   y+800 = 1100
   => y = 300
   Total investment of A and B resp.
   Rs. 2x +1800 and Rs. 2200 {2y+1600} {(2x+1800)/(2x+1800+2200)}*1500 = 840
   => x = 500
   Quantity I < Quantity II

    

10. Quantity I: A is 20% more than B while C is 30% less than A. If (A+B+C) = 608 then find the value of C.
    Quantity II: An election is held between P and Q. P got 35% of the total valid votes and 10% of the votes were invalid . Find the difference between the number of votes secured by P and Q, if the total votes cast was 600.
    Quantity I >= Quantity II
    Quantity I < Quantity II
    Quantity I =< Quantity II
    Quantity I = Quantity II
    Quantity I > Quantity II
    Option E
    From I:
    Let the value of B be x and A be 1.2x.
    Value of C = 70% of 1.2x = 0.84x
    => x+1.2x +0.84x = 608
    => x = 200
    Value of C = 0.84x = 168
    From II:
    Total valid votes = 90% of 600 = 540
    Total votes got by P and Q = 35% of 540 (189) and 65% of 540 (351)
    Required Difference = 351 – 189 = 162
    Quantity I > Qunatity II