# Quant Test for IBPS Clerk 2018 Prelim Exam Set – 01

Directions(1-5): What will the approximate value of the following questions.

1. 25.05 x 123.95 + 388.999 x 15.001 = ?
8250
7770
8935
7584
8005
Option C
25.05 x 123.95 + 388.999 x 15.001 = ?
= 25*123+388*15 = 8935

2. 4376 + 3209 – 1784 +97 = 3125+?
2500
2000
2520
2033
2773
Option E
4376 + 3209 – 1784 +97 = 3125+?
=> 7682 – 1784 = 3125 + x
=> 5898 = 3125 + x
=> x = 5898 – 3125 = 2773

3. 85% of 420 + ? % of 1080 = 735
48
35
55
42
40
Option B
85% of 420 + ? % of 1080 = 735
=> 357 + 10.8 x = 735
=> 10.8x = 735 − 357 = 378
=> x = 35

4. 30% of 1225 – 64% of 555 = ?
17
12
14
18
10
Option B
30% of 1225 – 64% of 555 = ?
= 367.5 − 355.2 = 12.3

5. 7/3 of 5/4 of 3024 = ?
8520
7000
6520
8820
7220
Option D
7/3 of 5/4 of 3024 = ?
= 35 × 252 = 8820

6. Directions(6-10): The following graph shows the percentage rise in population of six
different cities from 2010 to 2011 and 2011 to 2012. 7. If the rise in the population of City A from 2010 to 2012 was 2.75 lakh, what was its population in the year 2010?
6.0
5.5
4.2
2.5
3.3
Option D
Let the population of City A in the year 2010 be x.
Then, its population in the year 2012 = x*140/100*150/100 = 2.1x
Difference = 2.1x – x = l.1x
=> 1.1x = 2.75 lakh
=> x =2.75/1.1 = 2.5 lakh

8. The population of City D in the year 2010 was approximately what per cent of its population in the year 2011?
47%
44%
50%
57%
67%
Option D
Let the population of City D in the year 2010 be x.
Then population of City D in the year 2011 = x ×175/100
Required % = x *100/175x*100 = 57.14 == 57%

9. If the population of City E in the year 2010 was 3.2 lakh, what was its population in the year 2012?
6.00 lakh
8.44 lakh
5.02 lakh
6.72 lakh
7.77 lakh
Option D
Population of E in the year 2012
= 3.2* 150/100* 140/100
= 6.72 lakh

10. In the year 2010, the population of cities B and F were equal, and the population of City F in the year 2012 was 5.4 lakh. What was the population of City B in the year 2012?
8.2
7.7
5.5
4.8
6.4
Option C
Population of City F in the year 2010
= 5.4*100/180*100/125 = 2.4 lakh
[Population of B2010 = Population of F2010] Population of B2012 = 2.4* 160/100* 145/100
= 5.568 lakh

11. If the population of City C was 4.5 lakh in the year 2010, what was its population in the year 2012?
7.26 lakh
8.06 lakh
9.36 lakh
8.25 lakh
6.66 lakh
Option C
Population of City C2012
= 4.5* 130/100* 160/100
= 9.36 lakh