# Quant Test for IBPS Clerk 2018 Prelim Exam Set – 09

Directions(1-5): Find the missing term of the following series.

1. 7,16,36,78,?,222
144
100
132
150
120
Option A
(2*3)+1
(3*5)+1
(5*7)+1
(7*11)+1
(11*13)+1
(13*17)+1
? == 144

2. 1,-2,-7,-14,-23,?
-45
-50
-34
-38
-40
Option C
1-3=-2
-2-5=-7
-7-7=-14
-14-9=-23
-23-11=-34

3. 729,486,324,216,144,?
66
75
80
72
96
Option E
729*2/3
486*2/3
324*2/3
216*2/3
144*2/3
? == 96

4. -1,-7,-23,-55,-109,?
-155
-191
-198
-200
-184
Option B
0^2 – 1^3
1^2 – 2^3
2^2 – 3^3
3^2 – 4^3
4^2 – 5^3
5^2 – 6^3
? == -191

5. 90,91,99,126,?,315
105
147
152
133
190
Option E
+1^3
+2^3
+3^3
+4^3
+5^3
? == 190

6. Directions(6-10): The following graph shows the percentage growth in population of six cities from 1990 to 2000 and 2000 to 2010.

7. If the population of City F in year 1990 was 12 lakh, what will be its population in year 2010?
33
25
30
22
20
Option A
P(1990) = 12 lakh
P(2010) = 12*(100+75)100* (100+55)/100
P(2010) = 12 × 1.75 × 1.55 = 32.55 lakh == 33 lakh

8. In year 1990 the population of City A and City B are equal and the population of City A in year 2010 is 37.7 lakh. What is the population of City B in year 2010?
40
44
50
42
47
Option D
A(2010) = 37.7 lakh
A(1990) = 37.7*100/145*100/130 = 20 lakh
B(1990) = A(1990) = 20 lakh
B(2010) = 20* 140/100*150/100 = 42 lakh

9. The population of City E in year 1990 was what fraction of its population in 2010?
6/23
8/21
10/21
4/21
13/22
Option C
Let the population of E in 1990 be 100.
E(2010) = 100* 150/100* 140/100 = 210
Required fraction =100/210 = 10/21

10. If the population of City C in year 2010 and that of City D in year 2000 are equal and they are 27.2 lakh each the population of City C in year 1990 is what percentage of population of City D in the same year?
40%
80%
60%
50%
70%
Option D
C(2010) = 27.2 = D(2000)
C(1990) = 27.2* 100/170* 100/160 = 10 lakh
D(1990) = 27.2* 100/136 = 20 lakh
Required% =10/20 × 100 = 50%

11. The population of City D in year 2000 was what per cent of its population in year 2010?
60%
65%
50%
57%
63%
Option E
Suppose the population in year 2000 was x.
Its population in year 2010 x *160/100 = 8x/5
Required % = x/(8x/5)*100 = x ×5/8x × 100
= 62.5% == 63%