Quant Test for IBPS Clerk 2018 Prelim Exam Set – 09

Banya

Directions(1-5): Find the missing term of the following series.

  1. 7,16,36,78,?,222
    144
    100
    132
    150
    120
    Option A
    (2*3)+1
    (3*5)+1
    (5*7)+1
    (7*11)+1
    (11*13)+1
    (13*17)+1
    ? == 144

     

  2. 1,-2,-7,-14,-23,?
    -45
    -50
    -34
    -38
    -40
    Option C
    1-3=-2
    -2-5=-7
    -7-7=-14
    -14-9=-23
    -23-11=-34

     

  3. 729,486,324,216,144,?
    66
    75
    80
    72
    96
    Option E
    729*2/3
    486*2/3
    324*2/3
    216*2/3
    144*2/3
    ? == 96

     

  4. -1,-7,-23,-55,-109,?
    -155
    -191
    -198
    -200
    -184
    Option B
    0^2 – 1^3
    1^2 – 2^3
    2^2 – 3^3
    3^2 – 4^3
    4^2 – 5^3
    5^2 – 6^3
    ? == -191

     

  5. 90,91,99,126,?,315
    105
    147
    152
    133
    190
    Option E
    +1^3
    +2^3
    +3^3
    +4^3
    +5^3
    ? == 190

     

    6. Directions(6-10): The following graph shows the percentage growth in population of six cities from 1990 to 2000 and 2000 to 2010.

  6. If the population of City F in year 1990 was 12 lakh, what will be its population in year 2010?
    33
    25
    30
    22
    20
    Option A
    P(1990) = 12 lakh
    P(2010) = 12*(100+75)100* (100+55)/100
    P(2010) = 12 × 1.75 × 1.55 = 32.55 lakh == 33 lakh

     

  7. In year 1990 the population of City A and City B are equal and the population of City A in year 2010 is 37.7 lakh. What is the population of City B in year 2010?
    40
    44
    50
    42
    47
    Option D
    A(2010) = 37.7 lakh
    A(1990) = 37.7*100/145*100/130 = 20 lakh
    B(1990) = A(1990) = 20 lakh
    B(2010) = 20* 140/100*150/100 = 42 lakh

     

  8. The population of City E in year 1990 was what fraction of its population in 2010?
    6/23
    8/21
    10/21
    4/21
    13/22
    Option C
    Let the population of E in 1990 be 100.
    E(2010) = 100* 150/100* 140/100 = 210
    Required fraction =100/210 = 10/21

     

  9. If the population of City C in year 2010 and that of City D in year 2000 are equal and they are 27.2 lakh each the population of City C in year 1990 is what percentage of population of City D in the same year?
    40%
    80%
    60%
    50%
    70%
    Option D
    C(2010) = 27.2 = D(2000)
    C(1990) = 27.2* 100/170* 100/160 = 10 lakh
    D(1990) = 27.2* 100/136 = 20 lakh
    Required% =10/20 × 100 = 50%

     

  10. The population of City D in year 2000 was what per cent of its population in year 2010?
    60%
    65%
    50%
    57%
    63%
    Option E
    Suppose the population in year 2000 was x.
    Its population in year 2010 x *160/100 = 8x/5
    Required % = x/(8x/5)*100 = x ×5/8x × 100
    = 62.5% == 63%

     


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