**Directions(1-5)**: What will come in place of question mark “?” in the following questions.

- [(42% of 550+16)-12*(244/4-54)] =?
150111142163155Option D

[(42% of 550+16)-12*(244/4-54)] =?

=> [(231+16) – 12*(61-54)] =?

=> (247-84) = ?

=> ? = 163 - (35% of 40% of 650 – 62)+ ? *(592 /16-26) = 315
2018261015Option C

(35% of 40% of 650 – 62)+ ? *(592 /16-26) = 315

=> (91-62) + ? *11 = 315

=> 29+?*11 = 315

=> ? = 26 - (36*23+442/17)+(18*25-?) – 209 = 778
300310320311317Option E

(36*23+442/17)+(18*25-?) – 209 = 778

=> (828+26)+(450-?)-209 = 778

=> 1095 – ? = 778

=> ? = 317 - [613 – {(64+37*16)-501}*(946/86-?)] = 148
84765Option A

[613 – {(64+37*16)-501}*(946/86-?)] = 148

=> [613-(656-501)*(11-?)] = 148

=> 613 – 1705 + 155*? = 148

=> 155*? = 1240

=> ? = 8 - (559/13+19*7)-819/21of 3 = ?
154163144125110Option B

(559/13+19*7)-819/21of 3 = ?

=> (43+133) -819/63 = ?

=> 176-13 =?

=> ? = 163 - The market price of an article is 30% above the cost price of the article. If the shopkeeper sold the article at 15% discount then find the profit earned by the shopkeeper.
15%13.3%9.5%8.2%10.5%Option

Let CP be Rs.x

MP = 130% of x = Rs. 13x/10

SP = 85% of 13x/10 = 221x/200

Profit = 221x/200 – x = 21x/200

Profit% = 21x/200/x*100 = 10.5%

- The average number of articles sold by a shopkeeper in a week was 64. The average number of articles sold from Monday to Thursday was 59 while the average number of articles sold from Thursday to Sunday was 62. Find the number of articles sold on Thursday.
2530223624Option D

Total number of articles sold in a week = 64*7

= 448

Total number of articles from Monday to Thursday = 59*4

= 236

Total number of articles from Thursday to Sunday = 62*4

= 248

Now, 236+248 –x = 448

=>x = 36 - A alone can do a work in 12 days but when A works with B, the work gets completed in 60/7 days. B and C together do the work in 12 days. In how many days can A and C together do the work?
7.5 days8.2 days5 days7.5 days5.5 daysOption A

Let time taken by B alone to complete the work be x days and C be y days.

1/12+1/x = 7/60

=> 1/x = 2/60

=> x = 30

Now, 1/30+1/y = 1/12

=>1/y = 3/60

=> y = 20

Part of the work by A and C in a day = 1/12+1/20

= 8/60

Required number of days = 60/8

= 7.5 days - The ratio of the length to the breadth of a rectangular floor is 7:5. The perimeter of the floor is 96 m.Find the cost of cleaning the floor at the rate of 19 per m^2.
Rs. 11600Rs. 12300Rs. 10640Rs. 12500Rs. 10000Option C

2*(7x+5x) = 96

=> x= 4

Length of the floor = 7x = 28 m

Breadth of the floor = 5x = 20 m

Required cost = 19*20*28 = Rs. 10640 - There are 12 students in a coaching centre. One day 3 students were absent in the coaching. Find the probability that out of these 3 students at least 2 boys if total 7 girls study in the coaching.
3/115/112/117/114/11Option E

Number of boys study in the coaching = 12-7 =5

Required Probability = [7C1*5C2+5C3]/12C3 = 80/220 = 4/11

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