# Quant Test for IBPS Clerk 2018 Prelim Exam Set – 25

Directions(1-5): What will come in place of question mark in the following questions.

1. [400/5^2] *[180/3^2] = ?
415
305
320
300
404
Option C
[400/5^2] *[180/3^2] = ?
=> ? = 16*20
=> ? = 320

2. 880.03 – ? = (5.99^3 – 8.01^2)
728
720
710
690
700
Option A
880.03 – ? = (5.99^3 – 8.01^2)
=> 880 – ? = (6^3 – 8^2)
=> 880 – ? = 152
=> ? = 728

3. [8.03^2 – 11.99]- ? = 203.99
-148
-152
-125
-100
-140
Option B
[8.03^2 – 11.99]- ? = 203.99
=> 64 – 12 – ? = 204
=> 52 -? = 204
=> ? = -152

4. ? – (71.98% of 900 + 49.97) = 302.98
1015
1010
880
1001
950
Option D
? – (71.98% of 900 + 49.97) = 302.98
=> ? – (72/100*900 + 50) = 303
=> ? – (648 + 50) = 303
=> ? – 698 = 303
=> ?= 1001

5. [300+ 16% of 1900] + [41% of 1300] = ?
1125
1100
1114
1137
1133
Option D
[300+ 16% of 1900] + [41% of 1300] = ?
=> ? = [300+304]+[533] => ? = 1137

6. Ram had two laptops in his shop with marked price of Rs. 50000 and Rs. 36000 resp. He sold these laptops at 3x% and 2x% discount resp. If the sum of the selling prices was Rs. 77120 then find x.
2
5
3
4
6
Option D
50000(1-3x/100) + 36000*(1-2x/100) = 77120
=> 50000 – 1500x + 36000 – 720x = 77120
=> 2220x = 8880
=> x = 4

7. The ratio of number of males and females in a village is 7:4 resp. If the number of males is increased by x% and number of females is increased by (x+20)% , the ratio of male and female will become is 3:2 resp. Find the value of x.
25
10
15
20
22
Option D
7*(100+x)%/4(100+x+20)% = 3:2
=>7(100+x) = 6(120+x)
=> 7x-6x = 720-700
=> x = 20

8. A, B and C can complete a task in x days. While A and B together can complete the same task in (x+2) days. If C alone can complete the task in 24 days then find the value of x.
4
6
3
5
8
Option B
1/x – 1/(x+2) =1/24
=> x(x+8)-6(x+8) = 0
=> (x-6)(x+8) = 0
=> x = 6

9. Seeta and Geeta can complete a task in (x – 10) days and (x+10) days resp. While working individually. While working together, they can complete it in (4x-10)/8 days. In how many days can Seeta complete the task alone?
40
20
50
30
60
Option D
1/(x-10 ) + 1/(x+10) = 8/(4x-10)
=> x = 40
Seeta can complete the task alone in 30 days.

10. A bag contains 2 red balls, x yellow balls and 7 green balls. The probability of drawing a green ball from a bag is 0.5. If (x+3) balls are taken out from the bag at random, then find the probability that all the green balls are selected.
1/415
1/429
1/400
1/444
1/423
Option B
7/(2+x+7) = 0.5
=> x = 5 balls
Now, (x+3) = 8 balls
Required Probability = [ 7C7*2C1 + 7C7*5C1] /14C8
= 1/429

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