**Directions(1-5):** What will come in place of question mark in the following questions.

- [400/5^2] *[180/3^2] = ?
415305320300404Option C

[400/5^2] *[180/3^2] = ?

=> ? = 16*20

=> ? = 320 - 880.03 – ? = (5.99^3 – 8.01^2)
728720710690700Option A

880.03 – ? = (5.99^3 – 8.01^2)

=> 880 – ? = (6^3 – 8^2)

=> 880 – ? = 152

=> ? = 728 - [8.03^2 – 11.99]- ? = 203.99
-148-152-125-100-140Option B

[8.03^2 – 11.99]- ? = 203.99

=> 64 – 12 – ? = 204

=> 52 -? = 204

=> ? = -152 - ? – (71.98% of 900 + 49.97) = 302.98
101510108801001950Option D

? – (71.98% of 900 + 49.97) = 302.98

=> ? – (72/100*900 + 50) = 303

=> ? – (648 + 50) = 303

=> ? – 698 = 303

=> ?= 1001 - [300+ 16% of 1900] + [41% of 1300] = ?
11251100111411371133Option D

[300+ 16% of 1900] + [41% of 1300] = ?

=> ? = [300+304]+[533] => ? = 1137 - Ram had two laptops in his shop with marked price of Rs. 50000 and Rs. 36000 resp. He sold these laptops at 3x% and 2x% discount resp. If the sum of the selling prices was Rs. 77120 then find x.
25346Option D

50000(1-3x/100) + 36000*(1-2x/100) = 77120

=> 50000 – 1500x + 36000 – 720x = 77120

=> 2220x = 8880

=> x = 4 - The ratio of number of males and females in a village is 7:4 resp. If the number of males is increased by x% and number of females is increased by (x+20)% , the ratio of male and female will become is 3:2 resp. Find the value of x.
2510152022Option D

7*(100+x)%/4(100+x+20)% = 3:2

=>7(100+x) = 6(120+x)

=> 7x-6x = 720-700

=> x = 20 - A, B and C can complete a task in x days. While A and B together can complete the same task in (x+2) days. If C alone can complete the task in 24 days then find the value of x.
46358Option B

1/x – 1/(x+2) =1/24

=> x(x+8)-6(x+8) = 0

=> (x-6)(x+8) = 0

=> x = 6 - Seeta and Geeta can complete a task in (x – 10) days and (x+10) days resp. While working individually. While working together, they can complete it in (4x-10)/8 days. In how many days can Seeta complete the task alone?
4020503060Option D

1/(x-10 ) + 1/(x+10) = 8/(4x-10)

=> x = 40

Seeta can complete the task alone in 30 days. - A bag contains 2 red balls, x yellow balls and 7 green balls. The probability of drawing a green ball from a bag is 0.5. If (x+3) balls are taken out from the bag at random, then find the probability that all the green balls are selected.
1/4151/4291/4001/4441/423Option B

7/(2+x+7) = 0.5

=> x = 5 balls

Now, (x+3) = 8 balls

Required Probability = [ 7C7*2C1 + 7C7*5C1] /14C8

= 1/429

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