Directions(1-5): What will come in place of question mark in the following questions.
- [400/5^2] *[180/3^2] = ?
415305320300404Option C
[400/5^2] *[180/3^2] = ?
=> ? = 16*20
=> ? = 320 - 880.03 – ? = (5.99^3 – 8.01^2)
728720710690700Option A
880.03 – ? = (5.99^3 – 8.01^2)
=> 880 – ? = (6^3 – 8^2)
=> 880 – ? = 152
=> ? = 728 - [8.03^2 – 11.99]- ? = 203.99
-148-152-125-100-140Option B
[8.03^2 – 11.99]- ? = 203.99
=> 64 – 12 – ? = 204
=> 52 -? = 204
=> ? = -152 - ? – (71.98% of 900 + 49.97) = 302.98
101510108801001950Option D
? – (71.98% of 900 + 49.97) = 302.98
=> ? – (72/100*900 + 50) = 303
=> ? – (648 + 50) = 303
=> ? – 698 = 303
=> ?= 1001 - [300+ 16% of 1900] + [41% of 1300] = ?
11251100111411371133Option D
[300+ 16% of 1900] + [41% of 1300] = ?
=> ? = [300+304]+[533] => ? = 1137 - Ram had two laptops in his shop with marked price of Rs. 50000 and Rs. 36000 resp. He sold these laptops at 3x% and 2x% discount resp. If the sum of the selling prices was Rs. 77120 then find x.
25346Option D
50000(1-3x/100) + 36000*(1-2x/100) = 77120
=> 50000 – 1500x + 36000 – 720x = 77120
=> 2220x = 8880
=> x = 4 - The ratio of number of males and females in a village is 7:4 resp. If the number of males is increased by x% and number of females is increased by (x+20)% , the ratio of male and female will become is 3:2 resp. Find the value of x.
2510152022Option D
7*(100+x)%/4(100+x+20)% = 3:2
=>7(100+x) = 6(120+x)
=> 7x-6x = 720-700
=> x = 20 - A, B and C can complete a task in x days. While A and B together can complete the same task in (x+2) days. If C alone can complete the task in 24 days then find the value of x.
46358Option B
1/x – 1/(x+2) =1/24
=> x(x+8)-6(x+8) = 0
=> (x-6)(x+8) = 0
=> x = 6 - Seeta and Geeta can complete a task in (x – 10) days and (x+10) days resp. While working individually. While working together, they can complete it in (4x-10)/8 days. In how many days can Seeta complete the task alone?
4020503060Option D
1/(x-10 ) + 1/(x+10) = 8/(4x-10)
=> x = 40
Seeta can complete the task alone in 30 days. - A bag contains 2 red balls, x yellow balls and 7 green balls. The probability of drawing a green ball from a bag is 0.5. If (x+3) balls are taken out from the bag at random, then find the probability that all the green balls are selected.
1/4151/4291/4001/4441/423Option B
7/(2+x+7) = 0.5
=> x = 5 balls
Now, (x+3) = 8 balls
Required Probability = [ 7C7*2C1 + 7C7*5C1] /14C8
= 1/429
Thanks for your posting on this weblog. From my own personal experience, there are occassions when softening upward a photograph might provide the photo shooter with a little an artsy flare. Oftentimes however, the soft blur isn’t what exactly you had at heart and can frequently spoil an otherwise good snapshot, especially if you intend on enlarging this.