# Quant Test for IBPS Clerk 2018 Prelim Exam Set – 34

Directions(1-5): Find the missing term of the following series.

1. 112,134,164,?,240,282
159
200
195
178
187
Option B
+11*2
+10*3
+9*4
+8*5
+7*6
? = 200

2. 12,25,42,?,88,117
50
44
58
63
60
Option D
4*(1+2)=12
5*(2+3)=25
6*(3+4)=42
7*(4+5)=63
8*(5+6)=88
9*(6+7)=117

3. 25,38,45,50,54,?
57.4
30.3
51.2
44.4
50.2
Option A
+13/1
+14/2
+15/3
+16/4
+17/5
? = 57.4

4. 2033,?,2054,2075,2103,2138
1920
2200
2040
2125
2040
Option E
+7*1
+7*2
+7*3
+7*4
+7*5
? = 2040

5. 19456,1216,152,38,19,?
10
19
15
13
12
Option B
/16
/8
/4
/2
/1
? = 19

6. Find the volume of a cone of slant height 25 cm whose curved surface area is same as that of a cylinder of radius 8.75 cm and height 10 cm.
1205 cm^3
1275 cm^3
1111 cm^3
1176 cm^3
1075 cm^3
Option D
CSA of cone = CSA of cylinder
25*pi*r = 2*pi*8.75*10
=> r = 7 cm
H^2 = 25^2 – 7^2
=> H = 24 cm
Volume of cone = 1/3*pi*r *r*h
= 1/3*3*7*7*24 = 1176 cm^3

7. A shopkeeper sold a book for Rs. 420 at some profit. Had he sold the book for Rs. 17.5 more, he would have earned 5% more profit. Find the profit% earned by the shopkeeper initially.
10%
40%
30%
50%
20%
Option E
Let CP be Rs. X
Initailly Profit% be y%.
x*(y+100)/100 = 420 —–(1)
x*(y+100+5)/100 = (420+17.5) ——(2)
On solving (1) and (2) , we get
x = Rs. 350
y = 20%

8. The average weight of (x+5) eggs is 10 grams. If 5 more eggs are added then the average gets doubled. Find the value of x, if the 5 eggs which are added weigh 200 grams.
3
6
5
1
2
Option C
[10(x+5)+200] /(x+10) = 2*10
=> x = 5

9. A,B and C start a business together with ratio of investment as 1:2:3 resp. After x months, A withdrew half of his investment. After a year, C received Rs. 2400 as profit out of a total profit of Rs. 4200. Find the value of x.
4
2
5
6
3
Option E
Ratio of Profit = A:B:C
= (1*12):[2x+1*(12-x)]: (3*12)
=> 36/[12+12+x+36] = 2400/4200
=> x = 3

10. There are 2400 students in a school and the ratio of girls and boys is 3:5 resp. (x+2)% of boys and (x-3)% of girls passed in their annual examination. Find the value of x, if 78.125% of students passed in the examination.
55
60
62
78
70
Option D
Girls = 3/(3+5)*2400 = 900
Boys = 2400 – 900 = 1500
(x+2)% of 1500 + (x-3)% of 900 = 78.125% of 2400
=> x = 78