# Quant Test for IBPS Clerk 2018 Prelim Exam Set – 35

Directions(1-5): What will come in place of question mark “?” in the following questions.

1. [12*(385-?^2)]/16 =120
18
16
10
14
15
Option E
[12*(385-?^2)]/16 =120
=> 385 – ?^2 = 160
=> ?^2 = 225
=>? = 15

2. ? = 40% of 65% of 1800 +5^2
465
484
493
444
400
Option C
? = 40% of 65% of 1800 +5^2
=> ? = 468 + 25
=> ? = 493

3. ? = [(6^3 + 8^2)/8]^2/35
30
35
25
32
28
Option B
? = [(6^3 + 8^2)/8]^2/35
=> ? = [( 216+64)/8]^2/35
=> ? = 35^2 /35
=> ? = 35

4. ? = 30% of (18^2 + 6) + 72% of 1200
920
858
890
963
900
Option D
? = 30% of (18^2 + 6) + 72% of 1200
=> ? = 0.3 * 300 + 0.72 *1200
=> ? = 99+864
=> ? = 963

5. ? = (11^3 – 31^2)/37 + 13
12
18
20
23
10
Option D
? = (11^3 – 31^2)/37 + 13
=> ? = (1331 – 961)/37 + 13
=> ? = 23

6. A boy running at uniform speed of 12 km/hr crosses a bridge in 45 seconds. Find the length of the bridge.
100
185
120
150
130
Option D
X = 12*5/18*45
=> x = 150 metres

7. Vijay can complete a work in 24 days while Arjun can complete the same work in 15 days. If both worked together , then find the time taken to complete 86(2/3)% of the work.
6 days
8 days
4 days
5days
7 days
Option B
LCM (24 and 15) = 120 units
Required time taken = 86(2/3)% of 120/13 = 8 days

8. The average of weights of x,y and z is 50 kg and the average of weights of y and z is 45 kg. If the weight of w is 30 kg, then what is the average weight of x and w ?
45 kg
33 kg
50 kg
25 kg
40 kg
Option A
(x+y+z)/3 = 50 (y+z)/2 = 45
=> y+z = 90 (x+90)/3 = 50
=> x =60 kg
Required average = (60+30)/2 = 45 kg

9. Pipe A can fill a bucket 4 times faster than another pipe B and takes 15 minutes less than pipe B to fill the bucket. If both the pipes are opened simultaneously, then find the time taken to fill the bucket.
4
8
6
7
5
Option A
Let time taken by pipe A to fill the bucket alone be x minutes. 4x-x = 15 => 3x = 15 => x = 5 Time taken by B = 20 minutes
Time taken by A = 5 minutes
Required time taken by both pipes simultaneously to fill the bucket
= 1/{1/5+1/20} = 4 minutes

10. The selling price of 25 articles is same as the cost price of x articles. Find the value of x if the profit earned is 40%.
28
20
15
35
22
Option D
Let SP of 1 article be Rs.1
SP of 25 articles = Rs. 25
CP of x articles = Rs. 25
Profit earned = 40% 40/100 = (x-25)/25
=> x = 35