Quant Test for IBPS PO 2018 Prelim Exam Set – 18

Directions(1-5): Find the relation between x and y and choose a correct option.

1. I. x^2 − 6x + 9 = 0
II. y^2 − 11y + 24 = 0

y>x
x>y
y>=x
x=y or relation cannot be established.
x>=y
Option C
I. x^2 − 6x + 9 = 0
=> x = 3, 3
II. y^2 − 11y + 24 = 0
=> y = 8, 3
y ≥ x

2. I. 18x² + 18x + 4 = 0
II. 12y² + 29y + 14 = 0

x>y
x>=y
y>x
y>=x
x=y or relation cannot be established.
Option B
I.18x² + 18x + 4 = 0
=> 18x² + 12x + 6x + 4 = 0
=>6x (3x + 2) +2 (3x + 2) = 0
=> (3x + 2) (6x + 2) = 0
x = −2/3, −1/3
II. 12y² + 29y + 14 = 0
=>12y² + 21y + 8y + 14 = 0
=>3y(4y + 7) +2 (4y + 7) = 0
=> (4y+ 7) (3y +2) = 0
y = −7/4, −2/3
x ≥ y

3. I. y² + 2y – 3 = 0
II. 2x² – 7x + 6 = 0

y>=x
y>x
x>y
x=y or relation cannot be established.
x>=y
Option C
I. y² + 2y – 3 = 0
=>y² +3y – y – 3 = 0
=> (y + 3) (y- 1) = 0
y = -3, 1
II. 2x² -7x + 6 = 0
=> 2x² – 4x -3x + 6= 0
=>2x(x – 2) – 3 (x- 2) = 0
=> (x – 2) (2x – 3) = 0
x = 2, 3/2
x > y

4. I. x^2−5x−14 = 0
II.y^2+7y+10 = 0

x>y
y>=x
x=y or relation cannot be established.
x>=y
y>x
Option D
I. x^2 − 7x + 2x − 14 = 0
=> x(x − 7) + 2(x − 7) = 0
x = 7, −2
II.y^2 + 5y + 2y + 10 = 0
y = −2, −5
x ≥ y

5. I. 7x^2 – 21x – 33x + 99 = 0
II. 4y^2 – 10y – 6y + 15 = 0

x=y or relation cannot be established.
x>=y
y>x
y>=x
x>y
Option E
I. 7x^2 – 21x – 33x + 99 = 0
=> 7x(x − 3) − 33(x − 3) = 0
=> x = 3, 33/7
II. 4y^2 – 10y – 6y + 15 = 0
=> 2y(2y − 5) − 3(2y − 5) = 0
=> y = 3/2 , 5/2
x>y

6. Directions(6-10):
Study the following table shows the percentage of marks scored by 6 students in different subjects :

7. What is the ratio of marks obtained by students B and C in Maths together to marks obtained by D and E together in History ?
13:28
14:29
14:27
11:29
15:22
Option B
Required ratio = (72+68)*3/4 : (85+60)*3/2 = 14:29

8. What is the total marks obtained by B in all subjects together ?
590
578
620
581
500
Option D
Total Marks
= 44*3/4 + 72*3/4 + 58 + 80*3/2 + 95*200% + 72*7/4
= 33 + 54 + 58 + 120 + 190 + 126
= 581

9. The marks obtained by student C in Chemistry is what per cent of the total marks obtained by C in Maths ?
140%
160%
150%
100%
120%
Option A
Required% = 72/51*100 == 140%

10. What is the average marks obtained by E in all subjects together ?
66%
84%
77%
95%
88%
Option D
Required average marks = (108* 75% + 82* 100% + 60* 150% + 88 * 200% + 80 *175%) = 95%

11. The marks obtained by student D in Science is approximately what percent of the mark obtained by the students B in Maths ?
250%
222%
308%
200%
278%
Option E
Required% = (200%*75)/(72*75%)*100 = 150/54*100 == 278%