**Directions(1-5): **Find the missing term of the following series.

- 7, 20, 46, 98, 202,?
4430354149Option D

7 × 2 + 6 = 20

20 × 2 + 6 = 46

46 × 2 + 6 = 98

98 × 2 + 6 = 202

202 × 2 + 6 = 404 + 6 = 41 - 435, 354, 282, 219, 165, ?
1201119810590Option A

435 – 9 × 9 = 354

354 – 9 × 8 = 282

282 – 9 × 7 = 219

219 – 9 × 6 = 165

165 – 9 × 5 = 120 - 4, 200, 369, 513, 634, ?
710725732800734Option E

4 + 142 = 4 + 196 = 200

200 + 13^2 = 200 + 169 = 369

369 + 12^2 = 369 + 144 = 513

513 + 11^2 = 513 + 121 = 634

634 + 10^2 = 634 + 100 = 734 - 16, 22, 33, 49, 70, ?
74809688100Option C

16 + 6 = 22 22 + 11 = 33

33 + 16 = 49

49 + 21 = 70

70 + 26 = 96 - 13, 27, 55, 97, 153, ?
201223115300250Option B

13 + 1 × 14 = 27

27 + 2 × 14 = 55

55 + 3 × 14 = 97

97 + 4 × 14 = 153

153 + 5 × 14 = 223 - If Rs.7452 is divided in to three parts such that their amounts after 2, 3 and 4 years respectively are equal, the simple interest being at the rate of 5% per annum. Find the difference between the greatest and smallest parts of the sum.
222250216245260Option C

Let the amount divided into three parts x y z.

According to the question,

x + (x × 2 × 5)/100 = y + (y × 3 × 5)/100 = z + (z × 4 × 5)/100

=>x + 10x/100 = y + 15y/100 = z + 20z/100

=> 104x=106y=108z

= 7452× 2/69

= 108×2 = 216 - What will be the ratio of petrol and kerosene in the final solution formed by mixing petrol and kerosene that are present in three identical vessels in the ratio 4 : 1, 5 : 2 and 6 : 1 respectively?
93 : 3285 : 2283 : 2273 : 2380 : 21Option C

4 : 1—– 5×7

5 : 2——7×5

6 : 1—— 7×5

28 : 7

Adding all these ratios 25 : 10 30 : 5 83 : 22

Required Ratio = 83 : 22 - Mrs. Sharma invests 15% of her monthly salary, i.e., Rs. 4428 in Mutual Funds. Later she invests 18% of her monthly salary on Pension Policies also she invests another 9% of her salary on Insurance Policies. What is the total monthly amount invested by Mrs. Sharma?
Rs. 11250.5Rs. 13447.7Rs. 10015.4Rs. 14250.7Rs. 12398.4Option E

ATQ,

15% → 4428 1% →4428/15

15+18+9 = 42%

= 4428/15×42 → Rs. 12398.4 - Two men can complete a piece of work in 3 days while 3 women can complete the same work in 4 days and 4 children can complete the same work in 6 days . Then find in how many days 1 men ,1 women and 2 children can complete the same work ?
6 days3 days4 days5 days8 daysOption B

2M *3 = 3W*4 = 4C*6

1M = 2W = 4C LCM=4

1 Man’s efficiency= 4units/day

2 Women’s efficiency=2units/day

4 Children’s efficiency= 1 units/day

Total work =(2*4)*3 = 24 days

(1man+1woman+2children) = 4+2+2 = 8

(1man+1woman+2children) complete the work = 24/8 = 3 days - Two cards are drawn in succession from a pack of 52 cards, without replacement. What is the probability, that the first is a Queen and the second is a Jack of a different suit?
1/2213/2172/2231/2223/223Option A

The probability of first Queen = 4/52

The probability of Second Jack of different suit = 3/51

Reqd. Probability = (4/52) x (3/51) = (1/13) x (1/17)

= (1/221)