Quant Test for IBPS PO 2018 Prelim Exam Set – 2

Directions(1-5): What will come in pkace of question mark in the following questions.

  1. 17.99^2 – 14.05^2 + (2343.75 + 81.55) ÷ ? = 229
    24
    20
    18
    25
    30
    Option A
    17.99^2 – 14.05^2 + (2343.75 + 81.55) ÷ ? = 229
    (18)^ 2 − (14)^ 2 + (2350 + 80) ÷ ? = 230
    => 324 – 196 + (2430) ÷ ? = 230
    => 2430 ÷ ? = 230 – 130
    => 2430 ÷ ? = 100
    => ? = 2430/100 = 24.3 == 24

     

  2. 7^ 2.3 × 7^( 2×4.7) × (7 × 9)^3.4 × (9^2 )^ 5.85 = 63^?
    20
    11
    18
    15
    12
    Option D
    7^ 2.3 × 7^( 2×4.7) × (7 × 9)^3.4 × (9^2 )^ 5.85 = 63^? => 7^(2.3+9.4+3.4) × 9^(3.4+11.70) = (63)^?
    =>7^15.1 × 9^15.1 = (63)^?
    => (63)^15.1 = (63)^?
    =>? = 15.1

     

  3. √33124 * √2601 – (83)^2 = (?)^2 + (37) ^ 2
    48
    34
    40
    53
    32
    Option E
    √33124 * √2601 – (83)^2 = (?)^2 + (37) ^ 2
    =>182 * 51 – 6889 = (x)^2 + (37) ^ 2
    => 9282 – 6889 = (x)^2 + (37) ^ 2
    => 2393 = (x)^2 + (37) ^ 2
    => 2393 =(x)^2 +1369
    =>1024 =(x)^2
    => x=√1024
    =>x=32

     

  4. 5(17/37) × 4(51/52) × 11(1/7) + 2(3/4) = ?
    320.41
    310.52
    415.33
    305.75
    300.00
    Option D
    5(17/37) × 4(51/52) × 11(1/7) + 2(3/4) = ?
    = 202/37 × 259/52 × 78/7 + 11/4 = ? = (202 × 7)/52 × 78/7 + 11/4
    => ? = (101 × 6)/2 + 11/4
    => ? = (1212 + 11)/4
    = 1223/4 = 305.75

     

  5. 9/13 of 221 + 1(4/9) of 378 = 241 + ?
    458
    400
    475
    550
    444
    Option A
    9/13 of 221 + 1( 4/9) of 378 = 241 + ?
    ⇒ 9 × 17 + 13 × 42 = 241 + ?
    ⇒ 153 + 546 = 241 + ?
    ⇒ x = 458

     

  6. Directions(6-10): Study the following table carefully to answer these questions.
    Details of the seat belts produced by six different companies over the years.

  7. What percentage of total items produced by company U in 2010, 2014 and 2015 together are defective?
    2.5%
    2%
    1.6%
    2.8%
    2.5%
    Option C
    Total production in 2010, 2014 and 2015 by U = 44 + 42 + 19 = 105 lakh
    Total defective = [44*2.2/100 + 42*1.5/100 + 19*0.4/100] = 1.674 lakh
    Total production in 2010, 2014 and 2015 by U = 44 + 42 + 19 = 105 lakh
    Total defective = [44*2.2/100 + 42*1.5/100 + 19*0.4/100] = 1.674 lakh
    Required percentage = (1.674*100)/105 = 1.6%

     

  8. Number of defective seat belts produced by company Q, R and T together in year 2013, find them all ?
    1.704 lakh
    0.154 lakh
    2.993 lakh
    3.022 lakh
    2.504 lakh
    Option A
    Required answer
    = [33*14./100 + 36*1.9/100 + 31*1.8/100] = (0.462 + 0.684 + 0.558)
    = 1.704 lakh

     

  9. What is the ratio of the average production of company P to that of Q for all the given years ?
    162:173
    161:178
    161:169
    158:173
    163:170
    Option B
    Required ratio
    = (28+32+24+22+30+25)/(18+26+23+33+38+40) = 161:178

     

  10. Find the percentage increase/decrease in total production by all companies together from 2010 to 2011?
    15.57%
    10.23%
    17.52%
    13.70%
    11.77%
    Option E
    Total production in 2011 = 32 + 26 + 31 + 34 + 26 + 38
    = 187 lakh
    Total production in 2012 = 24 + 23 + 28 + 23 + 35 + 32 = 165 lakh
    % Decrement = [187 – 165]/187*100 = 11.77%

     

  11. What was the average number of perfect seat belts produced by company S in 2012, 2013 and 2014 together?
    25.03 lakh
    24.39 lakh
    21.55 lakh
    22.15 lakh
    20.35 lakh
    Option B
    Required number
    = [(23*99.2)/100 + (18*99.6)/100+ (33*98.2)/100]/3 lakh
    = 24.39 lakh

     


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