**Directions(1-5):** What will come in place of question mark “?” in the following questions.

- (36.02)^3×(4096)^1/2×(37.44)^2 ÷ (9^3×75.98^2) = 4^?
108567Option C

(36.02)^3×(4096)^1/2×(37.44)^2 ÷ (9^3×75.98^2) = 4^?

=>? = 5 - 564.966 + 82.0091 × 44.981 – 34.111 = ?
45455125475041054221Option E

564.966 + 82.0091 × 44.981 – 34.111 = ?

=>? = 565 + 82 × 45 – 34 = 4221 - 1135 ÷ ( 7/5 × 3/7 × 2/9 ) =?
85108100920084509010Option A

1135 × 5/7 × 7/3 × 9/2 = 8510 - 2/9 × 3/7 × 5/8 × 1780 =?
15095106120100Option C

2/9 × 3/7 × 5/8 × 1780 = ?

=>? = 106 - 41% of 601 – 250.17 = ? – 77% of 910
611705685690700Option D

41% of 601 – 250.17 = ? – 77% of 910

=> 40*6 – 250 + 700 = 690 - Several litre of Acid were drawn off a 54-litre vessel full of Acid and an equal amount of water added. Again the same volume of the mixture was drawn off and replaced by water as a result the vessel contained 24 litres of pure acid. How much of the Acid was drawn off initially ?
18 litres12 litres10 litres14 litres20 litresOption A

Let initially x litres of Acid were drawn off.

24 = 54 (1 – x/54)^2 => 24 × 54 = (54 – x)^²

=>x² – 108x + 1620 = 0

=> x² – 90x – 18x + 1620 = 0

=> (x – 90) (x – 18) = 0

x = 18 litres - Four examiners examine a certain number of answer papers in 10 days by working for five hours a day. For how many hours in a day would two examiners have to work in order to examine twice the number of answers papers in 20 days?
15 hours30 hours25 hours20 hours10 hoursOption E

Let the required hours per day are t hours.

10×4×5/n = 20×2×t/2n

Where n = No. of answer papers

=> t = 20/2

=> t = 10 hours - My brother is 3 years elder to me. My father was 28 years of age when my sister was born while my mother was 26 years of age when I was born. If my sister was 4 years of age when my brother was born, then, what was the age of my father when my brother was born?
33 years35 years40 years32 years28 yearsOption D

My brother was born 3 years before I was born & after 4 years, my sister was born.

So, father’s age when brother was born = 28 + 4 = 32 years - Wheels of radius 7 cm and 14 cm start rolling simultaneously from X and Y, which are 1980 cm apart, towards each other in opposite directions. Both of them make same number of revolutions per second. If both of them meet after 10 seconds, the find speed of the smaller wheel.
60 cm/sec.66 cm/sec.48 cm/sec.52 cm/sec.63 cm/sec.Option B

Distance travelled by smaller wheel in one revolution

= 2× 22/7 ×7 = 44 cm

And by larger wheel = 2× 22/7 ×14 = 88 cm

Now, if speed of smaller wheel is x cm/sec.

Then, speed of larger wheel = 2x cm/sec.

ATQ, 10x + 10 × 2x = 1980

=> x = 66 cm/sec. - A committee of 3 members is to be made out of 6 men and 5 women. What is the probability that the committee has at least two women?
10/3114/3316/3111/3215/33Option B

Number of possible combination of 3 persons in which 2 have to be women = (5C2 × 6C1 + 5C3)

Total possible outcomes = 11C3

Required Probabiltiy = 14/33