Quant Test for IBPS PO 2018 Prelim Exam Set – 23

Banya

Directions(1-5): What will come in place of question mark “?” in the following questions.

  1. (36.02)^3×(4096)^1/2×(37.44)^2 ÷ (9^3×75.98^2) = 4^?
    10
    8
    5
    6
    7
    Option C
    (36.02)^3×(4096)^1/2×(37.44)^2 ÷ (9^3×75.98^2) = 4^?
    =>? = 5

     

  2. 564.966 + 82.0091 × 44.981 – 34.111 = ?
    4545
    5125
    4750
    4105
    4221
    Option E
    564.966 + 82.0091 × 44.981 – 34.111 = ?
    =>? = 565 + 82 × 45 – 34 = 4221

     

  3. 1135 ÷ ( 7/5 × 3/7 × 2/9 ) =?
    8510
    8100
    9200
    8450
    9010
    Option A
    1135 × 5/7 × 7/3 × 9/2 = 8510

     

  4. 2/9 × 3/7 × 5/8 × 1780 =?
    150
    95
    106
    120
    100
    Option C
    2/9 × 3/7 × 5/8 × 1780 = ?
    =>? = 106

     

  5. 41% of 601 – 250.17 = ? – 77% of 910
    611
    705
    685
    690
    700
    Option D
    41% of 601 – 250.17 = ? – 77% of 910
    => 40*6 – 250 + 700 = 690

     

  6. Several litre of Acid were drawn off a 54-litre vessel full of Acid and an equal amount of water added. Again the same volume of the mixture was drawn off and replaced by water as a result the vessel contained 24 litres of pure acid. How much of the Acid was drawn off initially ?
    18 litres
    12 litres
    10 litres
    14 litres
    20 litres
    Option A
    Let initially x litres of Acid were drawn off.
    24 = 54 (1 – x/54)^2 => 24 × 54 = (54 – x)^²
    =>x² – 108x + 1620 = 0
    => x² – 90x – 18x + 1620 = 0
    => (x – 90) (x – 18) = 0
    x = 18 litres

     

  7. Four examiners examine a certain number of answer papers in 10 days by working for five hours a day. For how many hours in a day would two examiners have to work in order to examine twice the number of answers papers in 20 days?
    15 hours
    30 hours
    25 hours
    20 hours
    10 hours
    Option E
    Let the required hours per day are t hours.
    10×4×5/n = 20×2×t/2n
    Where n = No. of answer papers
    => t = 20/2
    => t = 10 hours

     

  8. My brother is 3 years elder to me. My father was 28 years of age when my sister was born while my mother was 26 years of age when I was born. If my sister was 4 years of age when my brother was born, then, what was the age of my father when my brother was born?
    33 years
    35 years
    40 years
    32 years
    28 years
    Option D
    My brother was born 3 years before I was born & after 4 years, my sister was born.
    So, father’s age when brother was born = 28 + 4 = 32 years

     

  9. Wheels of radius 7 cm and 14 cm start rolling simultaneously from X and Y, which are 1980 cm apart, towards each other in opposite directions. Both of them make same number of revolutions per second. If both of them meet after 10 seconds, the find speed of the smaller wheel.
    60 cm/sec.
    66 cm/sec.
    48 cm/sec.
    52 cm/sec.
    63 cm/sec.
    Option B
    Distance travelled by smaller wheel in one revolution
    = 2× 22/7 ×7 = 44 cm
    And by larger wheel = 2× 22/7 ×14 = 88 cm
    Now, if speed of smaller wheel is x cm/sec.
    Then, speed of larger wheel = 2x cm/sec.
    ATQ, 10x + 10 × 2x = 1980
    => x = 66 cm/sec.

     

  10. A committee of 3 members is to be made out of 6 men and 5 women. What is the probability that the committee has at least two women?
    10/31
    14/33
    16/31
    11/32
    15/33
    Option B
    Number of possible combination of 3 persons in which 2 have to be women = (5C2 × 6C1 + 5C3)
    Total possible outcomes = 11C3
    Required Probabiltiy = 14/33

     


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