# Quant Test for IBPS PO 2018 Prelim Exam Set – 28

Directions(1-5): Find the missing term of the following series.

1. 32,57,282,?,2132,4157
852
800
973
907
855
Option D
32+5^2 = 57
57+15^2 = 282
282 + 25^2 = 907
907 + 35^2 = 2132
2132 + 45^2 = 4157

2. 214,106,104,?,302,750
115
142
150
135
153
Option E
214*0.5 – 1 = 106
106*1 – 2 = 104
104*1.5 – 3 = 153
153*2 – 4 = 302
302*2.5 – 5 = 750

3. 35,?,76,111,161,224
41
50
45
35
30
Option B
35+(4^2 – 1) = 50
50+(5^2 + 1 ) = 76
76+(6^2 – 1) = 111
111+(7^2 + 1) = 161
161+(8^2 – 1) = 224

4. 26,32,44,?,94,136,192
55
60
48
64
70
Option D
26+(3*2) = 32
32+(4*3) = 44
44+(5*4) = 64
64+(6*5) = 94
94+(7*6) = 136
136+(8*7) = 192

5. 500,496,487,?,446,410
471
450
444
490
487
Option A
500 – 2^2 = 496
496 – 3^2 = 487
487 – 4^2 = 471
471 – 5^2 = 446
446 – 6^2 = 410

6. Directions(6-10): Study the data carefully and answer the questions that follow :
Number of passed student in graduation in different universities and their ratio in B.tech, MCA and PGDM : Percentage of Female students in B.tech, MCA and PGDM in different universities : 7. What is the average students passed in B.Tech in JNU and IP universities together ?
667
555
610
580
629
Option E
Total number of female students
= [2590*3/10+2400*2/10]/2
= [777+480]/2
= 629

8. What is the respective ratio of male students in B.Tech, MCA and PGDM in JNU ?
81 : 70 : 32
79 : 60 : 31
80 : 80 : 33
80 : 77 : 30
74 : 84 : 35
Option C
Required ratio = 80×3 : 60×4 : 3×33
= 240 : 240 : 99
= 80 : 80 : 33

9. What is the respective ratio between passed female students in MCA from BHU to passed male students in PGDM from IP ?
159:330
179:332
161:312
153:300
151:310
Option C
Required ratio = 2300*5/10*42% : 2400*6/10*65%
= 483:936 = 161:312

10. What is the approximate number of female students who passed in MCA discipline from JNU ?
385
415
390
400
402
Option B
Number of female students = 2590*4/90*40%
= 415

11. Number of female in PGDM in JNU is what percent of the female students in MCA in BHU ?
100%
90%
108%
112%
120%
Option C
Required% = [2590*3/10*67/100]/[2300*5/10*42/100] = 520/483*100 = 108%