Directions(1-5): Find the missing term of the following series.
- 32,57,282,?,2132,4157
852800973907855Option D
32+5^2 = 57
57+15^2 = 282
282 + 25^2 = 907
907 + 35^2 = 2132
2132 + 45^2 = 4157 - 214,106,104,?,302,750
115142150135153Option E
214*0.5 – 1 = 106
106*1 – 2 = 104
104*1.5 – 3 = 153
153*2 – 4 = 302
302*2.5 – 5 = 750 - 35,?,76,111,161,224
4150453530Option B
35+(4^2 – 1) = 50
50+(5^2 + 1 ) = 76
76+(6^2 – 1) = 111
111+(7^2 + 1) = 161
161+(8^2 – 1) = 224 - 26,32,44,?,94,136,192
5560486470Option D
26+(3*2) = 32
32+(4*3) = 44
44+(5*4) = 64
64+(6*5) = 94
94+(7*6) = 136
136+(8*7) = 192 - 500,496,487,?,446,410
471450444490487Option A
500 – 2^2 = 496
496 – 3^2 = 487
487 – 4^2 = 471
471 – 5^2 = 446
446 – 6^2 = 410 - What is the average students passed in B.Tech in JNU and IP universities together ?
667555610580629Option E
Total number of female students
= [2590*3/10+2400*2/10]/2
= [777+480]/2
= 629 - What is the respective ratio of male students in B.Tech, MCA and PGDM in JNU ?
81 : 70 : 3279 : 60 : 3180 : 80 : 3380 : 77 : 3074 : 84 : 35Option C
Required ratio = 80×3 : 60×4 : 3×33
= 240 : 240 : 99
= 80 : 80 : 33 - What is the respective ratio between passed female students in MCA from BHU to passed male students in PGDM from IP ?
159:330179:332161:312153:300151:310Option C
Required ratio = 2300*5/10*42% : 2400*6/10*65%
= 483:936 = 161:312 - What is the approximate number of female students who passed in MCA discipline from JNU ?
385415390400402Option B
Number of female students = 2590*4/90*40%
= 415 - Number of female in PGDM in JNU is what percent of the female students in MCA in BHU ?
100%90%108%112%120%Option C
Required% = [2590*3/10*67/100]/[2300*5/10*42/100] = 520/483*100 = 108%
Directions(6-10): Study the data carefully and answer the questions that follow :
Number of passed student in graduation in different universities and their ratio in B.tech, MCA and PGDM :
Percentage of Female students in B.tech, MCA and PGDM in different universities :
