# Quant Test for IBPS PO 2018 Prelim Exam Set – 29

Directions(1-5): What will come in place of question mark “?” in the following questions.

1. ( 3/2 × 16/4 × 3/8 ) + ( 3/8 × 12/4 × 18/2 ) = ?
11(3/8)
12(1/5)
10(3/2)
12(3/8)
11(5/7)
Option D
( 3/2 × 16/4 × 3/8 ) + ( 3/8 × 12/4 × 18/2 ) = ?
= 9/4 + 81/8 = [18+81]/8
= 99/8 = 12(3/8)

2. 141 ÷ 34 + 223 × 30.02 = ?
7,120
5,000
6,250
7,000
6,700
Option E
141 ÷ 34 + 223 × 30.02 = ?
? = 140/35 + 223×30 = 6,700

3. 9898 + 1073 – 1882 × 3 ÷ 2 = ?
7800
8520
9844
6100
8148
Option E
9898 + 1073 – 1882 × 3 ÷ 2 = ?
10971 – 941*3 = ?
=> ? = 8148

4. √1225 / 3√343 * 45% of 760 = ?
1700
1010
1220
1550
1710
Option E
√1225 / 3√343 * 45% of 760 = ?
=> 35/7 * 342 = ?
=> ? = 1710

5. 3(1/7) + 2(3/5) + 7(1/5) – 5(3/7) – 18/35 = 35/?
8
5
9
7
6
Option B
3(1/7) + 2(3/5) + 7(1/5) – 5(3/7) – 18/35 = 35/?
=> 35/? = 22/7 + 13/5 + 36/5 – 38/7 – 18/35 = 245/35
=> ? = 5

6. If ratio of investment A, B and C are in the ratio 3 : 5 : 8 and the time of investment of A, B and C are 100/3 %, 80% and 25% respectively of their investment, and profit of A is 4800 then what will be the profit of C.
55000
41100
35500
25600
22100
Option D
Ratio of profit = 3×3× 1/3 : 5×5× 4/5 ∶ 8×8× 1/4
= 3 ∶ 20 ∶ 16
Profit of C = 4800/3 ×16 = 25600

7. Cost price of 3 pens is equal to the cost price of 5 pencils. If equal number of pens and pencils are sold and pens are sold at 20% profit and pencils are sold at 100/3 % profit then what is the overall profit percentage.
27%
30%
25%
15%
20%
Option C
Let 15 pens and 15 pencils are sold and cost of 1 pen is Rs.10
So, Cost of 3 pen is Rs.30 which is equal to cost of 5 pencils.
Total cost priceof 15 pens and 15 pencils = 15 × 10 + 6 × 15 = 150 + 90 = Rs.240
Total selling prices of 15 pens and 15 pencils = 150× 6/5 + 90× 4/3 = 180 + 120 = 300
Overall percentage profit = [300 – 240]/240 ×100
= 60/240 ×100 = 25%

8. If the volume and curved surface area of a cylinder 616 m3 and 352m2 respectively, what is the total surface area of the cylinder (in m^2 )?
510 m^2
321 m^2
429 m^2
525 m^2
400 m^2
Option C
𝜋𝑟^2ℎ/2𝜋𝑟ℎ = 616/352
𝑟 = 3.5 m
𝜋𝑟^2ℎ = 616
ℎ = 616/11×3.5 = 16 m
Total S.A. = 2𝜋𝑟ℎ + 2𝜋𝑟^2 = 2𝜋𝑟(ℎ + 𝑟)
= 2× 22/7 ×3.5(3.5 + 16) = 429 m^2

9. The strength of a school increases and decreases in every alternate year by 10%. It started in 2000 and increases in 2001, then the strength of the school in 2003 as compared to that in 2000 was:
Increase by 7.7%
Increase by 7.0%
Decrease by 7.7%
Increase by 8.9%
Decrease by 8.9%
Option D
Let in 2000, the strength was 100.
In 2001 strength = 110
In 2002 strength = 110 × 90/100
In 2003 strength = 110 × 90/100 × 110/100 = 108.9
Required % increment = 8.9%
Hence, strength after 3 years will increase by 8.9%

10. In how many ways can 5 different toys be packed in 3 identical boxes such that no box is empty, if any of the boxes may hold all of the toys ?
35 ways
25 ways
30 ways
15 ways
20 ways
Option B
Case 1: 5C2*3C2 = 15 ways
Case 2: 5C3 = 10 = 10 ways.
Required ways = 25 ways