# Quant Test for IBPS PO 2018 Prelim Exam Set – 3

Directions(1-5): Find the relation between x and y and choose a correct option.

1. I. 3√x– 18/ √x = √x
II. 2√y + (y−36)/ √y = –√y

x>=y
x=y or relation cannot be established.
y>=x
x>y
y>x
Option B
3√x– 18/ √x = √x
=>3x–18 = x
=>2x = 18
=>x = 9
2√y +( y−36)/ √y = –√y
=>2y+y–36 = –y
=>4y = 36
=>y = 9
x=y

2. I. 6 y^2 + 1/2 = 7/2 y
II. 12 x^2 + 2 = 10 x

y>=x
x>y
x>=y
y>x
x=y or relation cannot be established.
Option C
6y^2 + 1/2 = 7/2 y
12y^2 – 7 y + 1 = 0
12y^2 – 44y – 3y + 1 = 0
4y (3y – 1) – 1 (3y –1) = 0
(3y – 1) (4y – 1) = 0
y = 1/3, ¼
12x^2 – 10x + 2 = 0
6x^2 – 5x + 1 = 0
3x (2x –1) – 1 (2x –1)= 0
x = 1/3, ½
x>=y

3. I. x ^4 – 1000 = 296
II. y^2 + 330 = 346

x=y or relation cannot be established.
x>=y
x>y
y>x
y>=x
Option A
x = + 6,-6
y = + 6, -6
No relation

4. I. 21x^2 – 26x + 5 = 0
II. y = √0.1024

y>x
x>y
y>=x
x=y or relation cannot be established.
x>=y
Option D
x = 0.23, 1
y = + 0.32
No relation

5. I. (6^ 3+9^2)/ 11 = x^3
II. 15y^3= (36×18) + 12y^3

x>=y
y>x
x=y or relation cannot be established.
y>=x
x>y
Option B
(6^3+9^2)/ 11 = x^3
=>216+81 11 = x ^3
=>297 11 = x ^3
=>x ^3 = 27
x = +3
15y^3= (36×18) + 12y^3
=>15y^3 –12y^3 = (36×18)
=>3y^3 = (36×18)
=>3y^3 = 648
=>y ^3 = 216
y = +6
y>x

6. How many 3-letter words with or without meaning, can be formed out of the letters of the word, ‘LOGARITHMS’, if repetition of letters is not allowed?
700
660
720
656
685
Option C
The word ‘LOGARITHMS’ has 10 different letters.
=10×9×8=720

7. Compound Interest for two years at 20% per annum would fetch a sum of money Rs. 482, if the interest was payable half- yearly then it was payable annually. What is the sum?
35000
22800
33000
20000
25200
Option D
Let sum=Rs.x
C.I. when compounded half yearly = [x(1+10/100)^4−x] = 4641/10000
C.I. when compounded annually = [x(20/100)^2−x] = 11/25
4641/10000 x−11/25x = 482
=> x=20000

8. A and B can do a piece of work in 45 and 40 days respectively.They began work together but A leaves after X days and B finished the rest of the work in X+14 days. After how many days did A leave?
11
7
9
10
5
Option C
Total work in one day = (1/45+1/40) = 17/360
In X days, 17X/360
Remaining work = (1-17x/360)
Now, B can do 1 pt. work in (x+14)/(1-17x/360) days.
(x+14)/(1-17x/360) = 40
X = 9 days.

9. A train travelling at a speed of 75 mph enters a tunnel 3(1/2) miles long. The train is ¼ mile long. How long does it take for the train to pass through the tunnel from the moment the front enters to the moment the rear emerges?
5
3
7
4
2
Option B
Total distance covered = (7/2+1/4) miles
= 154 miles
Time taken = (154*75) hrs = 120 hrs.
= (1/20*60) min.= 3 min

10. In a city of an adult population, 45% of men and 25% of women are married. If no man marries more than one woman, and vice versa, What is the percentage of total population of adults who are married ?
20.25%.
32.14%.
28.15%.
25.23%.
30.12%.
Option B
Let no. of men = x & total population be 100.
Total women = (100-x)
Married man = 45x /100 —————(1)
& married women = 25/100 (100-x) ——— (2)
From (1) & (2) x = 500/14
So, Married man = 225 /14
Married woman = 225/14
Total married population = men + women = 450/14
Required % = (450/14)/100 *100
= 450/14% = 32.14%.

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