# Quant Test for IBPS PO 2018 Prelim Exam Set – 31

Directions(1-5): Find the missing term of the following series.

1. 38,42,50,66,98,?
145
112
162
130
125
Option C
38,42,50,66,98,?
+4
+8
+16
+32
+64
? = 162

2. 32,49,83,134,?,287
189
194
156
202
180
Option D
32,49,83,134,?,287
32+ 17*1 = 49
49+17*2 = 83
83+17*3 = 134
134+17*4 = 202
202+17*5 = 287

3. 120, 15, 105, 17.5, 87.5, ?
21.875
17.201
23.152
25.120
11.521
Option A
120, 15, 105, 17.5, 87.5, ?
120 / 8 = 7
15 × 7 = 105
105 / 6 = 17.5
17.5 × 5 = 87.5
87.5 / 4 = 21.875

4. 1, 16, 81, 256, 625, 1296, ?
2050
2401
2200
1855
1404
Option B
1, 16, 81, 256, 625, 1296, ?
1 = l^4 16 = 2^4
81 = 3^4 256 = 4^4
625 = 5^4 1296 = 6^4
? = 7^4 = 7 × 7 × 7 × 7 = 2401

5. 286, 142, ?, 34, 16, 7
60
55
62
70
68
Option D
286, 142, ?, 34, 16, 7
286/2 – 1 = 143 – 1 = 142
142/2 – l = 71 – l = 70
70/2 – 1 = 35 – 1 = 34
34/2 – 1 = 17- 1 = 16
16/2 – 1 = 7

6. An amount of Rs. 16600 is divided equally and each is invested at two different rates of interest. The difference between the interests got after 4 year is Rs. 700. What is the difference between the rates of interest?
4.2%
3.5%
3.13%
2.10%
1.5%
Option D
Let the 2 different rates be x and y respectively. Difference between the interests is Rs 700.
= [8300 × 𝑥 × 4]/100 – [8300 × 𝑦 × 4]/ 100 = 700
= 33200x-33200y =700×100
= 33200(x – y) = 70000
x-y = 2.10%

7. Mrs. Mary decided to distribute pens among A,B,C and D in the ratio 3:4:6:5 resp. But mistakenly she distributed pens among them in the ratio of 5:8:4:7 resp., So, A and B got 3 and 8 pens more resp. The number of pens received by D is what % more than the number of pens she was expected to receive ?
10%
9%
7%
8%
5%
Option E
Number of pens expected to receive by A,B,C and D = 3x,4x,6x and 5x.
Number of pens received by A,B,C and D = 5x,8x,4x and 7x.
ATQ, 8y – 4x = 8 And 5y – 3x = 3
Solving both the equations,we get x = 4 and y = 3
Number of pens expected to receive by D = 5*4 = 20
Number of pens received by D = 7*3 = 21
Required% = (21-20)/20*100% = 5%

8. In an examination, a student scores 4 marks for every correct answer and loses 1 mark for every wrong answer. If he attempts all 60 questions and secures 130 marks, find the no of questions he attempts correctly.
25
38
45
40
30
Option B
Let the number of correct answers be X.
Number of incorrect answers = (60 – X).
4x – (60 – x) = 130
=> 5x = 190
=> x = 38

9. A train travelling at a speed of 75 mph enters a tunnel 3(1/2) miles long. The train is 1/4mile long. How long does it take for the train to pass through the tunnel from the moment the front enters to the moment the rear emerges?
2 min.
3 min.
6 min.
4min.
5 min.
Option B
Total distance covered = (7/2 + 1/4) miles
= 15/4 miles
Time taken = (15/4*75)hrs. = 1/20 hrs.= (1/20*60)min. = 3 min.

10. In how many different ways can the letters of the word ‘OPTICAL’ be arranged so that the vowels always come together?
500
680
610
720
700
Option D
We have to arrange the letters PTCL (OIA).
Now, 5 letters can be arranged in 5! = 120 ways.
The vowels (OIA) can be arranged among themselves in 3! = 6 ways.
Required number of ways = (120 x 6) = 720