Quant Test for IBPS PO 2018 Prelim Exam Set – 7

Directions(1-5): Find the missing term of the following series.

1. 66, 91,120, 153, 190, ?, 276
   200
   231
   209
   198
   212
   Option B
   66 + 25 = 91
   91 + 29 = 120
   120 + 33 = 153
   153 + 37 = 190
   190 + 41 = 231
   231 + 45 = 276

    

2. 13.76, 14.91, 17.21, 20.66, ?, 31.01
   30.11
   25.26
   28.30
   22.12
   20.21
   Option B
   13.76 + 1 × 1.15 = 14.91
   14.91 + 2 × 1.15 = 14 + 2.30 = 17.21
   17.21 + 3 × 1.15 = 17.21 + 3.45 = 20.66
   20.66 + 4 × 1.15 = 20.66 + 4.60 = 25.26
   25.26 + 5 × 1.15 = 25.26 + 5.75 = 31.01

    

3. ? ,16, 28, 58, 114, 204
   10
   12
   14
   20
   17
   Option C
   14 + 1 × 2 = 16
   16 + 3 × 4 = 16 + 12 = 28
   28 + 5 × 6 = 28 + 30 = 58
   58 + 7 × 8 = 58 + 56 = 114
   114 + 9 × 10 = 114 + 90 = 204

    

4. 21, 10.5, ?, 15.75, 31.5, 78.75
   10.5
   7.4
   11.8
   9.2
   8.5
   Option A
   21 × 0.5 = 10.5
   10.5 × 1 = 10.5
   10.5 × 1.5 = 15.75
   15.75 × 2 = 31.50
   31.50 × 2.5 = 78.75

    

5. 96, 94, 373, 3353, ?, 1341069
   53415
   53643
   48600
   53773
   50544
   Option B
   (× 1 − 2), (× 4 − 3), (× 9 − 4), (× 16 − 5), (× 25 − 6)
   = 3353 × 16 − 5 = 53643

    

6. A train travelling at 36 kmph completely crosses another train having half its length and travelling in the opposite direction at 54 kmph, in 12 seconds. If it also passes a railway platform in 1(1/2) minutes, find the length of the platform.
   750 m
   720 m
   685 m
   700 m
   660 m
   Option D
   Let the length of slower train be x metres and the length of faster train be x/2 meters.
   Relative speed = (36+54)km/hr. = (90×5/18) = 25 m/sec.
   3x/(2×25) = 12
   => 3x = 600
   => x = 200
   Length of slower train = 200 m
   Let the length of platform be y metres
   Then, (200+y)/36+5/18=90
   => 200 + y=900
   y = 700 m
   Length of platform = 700 m

    

7. Vidal borrows Rs. 50,000 from a bank at 5% p.a. simple interest and clears the debt in five years. If the installments paid at the end of the first, second, third and fourth years to clear the debt are Rs. 5,000, Rs. 10,000, Rs. 15,000 and Rs. 20,000 respectively, what amount should be paid at the end of the fifth year to clear the debt?
   6800
   7700
   8000
   7520
   7500
   Option E
   Simple interest for 1st yr.= P*R*T / 100
   = 50000×1×5/ 100 = 2500
   Amount after 1st instalment = 50000- 5000=45000
   Simple interest for 3rd yr.= P*R*T / 100 = 35000×1×5/ 100 = 1750
   Amount after 3rd instalment = 35000- 15000 = 20000
   Simple interest for 4th yr.=P*R*T/ 100 = 20000×1×5/ 100 = 1000
   Amount after 4th instalment = 20000- 20000 = 0
   Balance of debt for the fifth year = 2500+2250+1750+1000 =7500

    

8. A field is 90 metre long and 50 metre broad. A 25 metre long, 20 metre broad and 4 metre deep tank dug in the field and the earth taken out is spread evenly over the remaining field. How much the level of field will rise?
   1
   3
   2.5
   0.5
   2
   Option D
   Area of field = 90 x 50 = 4500 m^2
   Area of field dug out = 25 x 20 = 500 m^2
   Therefore, Area of remaining field = 4500 – 500 = 4000 m^2
   Volume of the earth dug out = 25 x 20 x 4 = 2000 m^3
   Therefore, Field will rise by 2000/4000 = 0.5 metre

    

9. A cistern has a leak which would empty the cistern in 20 minutes. A tap is turned on which admits 4 liters a minute into the cistern, and it is emptied in 24 minutes. How many liters does the cistern hold ?
   420 litres
   380 litres
   480 litres
   390 litres
   400 litres
   Option C
   1/x – 1/20 = -1/24 x = 120
   120 x 4 = 480 litres

    

10. There are 2 people who are going to take part in race. The probability that the first one will win is 2/7 and that of other winning is 3/5. What is the probability that one of them will win?
    11/34
    18/35
    17/36
    19/35
    11/35
    Option D
    Prob. of 1st winning = 2/7
    Not winning = 1 – 2/7 = 5/7
    Prob. of 2nd winning = 3/5
    Not winning = 1 – 3/5 = 2/5
    Required prob. = 2/7 * 2/5 + 3/5 * 5/7
    = 19/35