**Directions(1-5):** Find the missing term of the following series.

- 66, 91,120, 153, 190, ?, 276
200231209198212Option B

66 + 25 = 91

91 + 29 = 120

120 + 33 = 153

153 + 37 = 190

190 + 41 = 231

231 + 45 = 276 - 13.76, 14.91, 17.21, 20.66, ?, 31.01
30.1125.2628.3022.1220.21Option B

13.76 + 1 × 1.15 = 14.91

14.91 + 2 × 1.15 = 14 + 2.30 = 17.21

17.21 + 3 × 1.15 = 17.21 + 3.45 = 20.66

20.66 + 4 × 1.15 = 20.66 + 4.60 = 25.26

25.26 + 5 × 1.15 = 25.26 + 5.75 = 31.01 - ? ,16, 28, 58, 114, 204
1012142017Option C

14 + 1 × 2 = 16

16 + 3 × 4 = 16 + 12 = 28

28 + 5 × 6 = 28 + 30 = 58

58 + 7 × 8 = 58 + 56 = 114

114 + 9 × 10 = 114 + 90 = 204 - 21, 10.5, ?, 15.75, 31.5, 78.75
10.57.411.89.28.5Option A

21 × 0.5 = 10.5

10.5 × 1 = 10.5

10.5 × 1.5 = 15.75

15.75 × 2 = 31.50

31.50 × 2.5 = 78.75 - 96, 94, 373, 3353, ?, 1341069
5341553643486005377350544Option B

(× 1 − 2), (× 4 − 3), (× 9 − 4), (× 16 − 5), (× 25 − 6)

= 3353 × 16 − 5 = 53643 - A train travelling at 36 kmph completely crosses another train having half its length and travelling in the opposite direction at 54 kmph, in 12 seconds. If it also passes a railway platform in 1(1/2) minutes, find the length of the platform.
750 m720 m685 m700 m660 mOption D

Let the length of slower train be x metres and the length of faster train be x/2 meters.

Relative speed = (36+54)km/hr. = (90×5/18) = 25 m/sec.

3x/(2×25) = 12

=> 3x = 600

=> x = 200

Length of slower train = 200 m

Let the length of platform be y metres

Then, (200+y)/36+5/18=90

=> 200 + y=900

y = 700 m

Length of platform = 700 m - Vidal borrows Rs. 50,000 from a bank at 5% p.a. simple interest and clears the debt in five years. If the installments paid at the end of the first, second, third and fourth years to clear the debt are Rs. 5,000, Rs. 10,000, Rs. 15,000 and Rs. 20,000 respectively, what amount should be paid at the end of the fifth year to clear the debt?
68007700800075207500Option E

Simple interest for 1st yr.= P*R*T / 100

= 50000×1×5/ 100 = 2500

Amount after 1st instalment = 50000- 5000=45000

Simple interest for 3rd yr.= P*R*T / 100 = 35000×1×5/ 100 = 1750

Amount after 3rd instalment = 35000- 15000 = 20000

Simple interest for 4th yr.=P*R*T/ 100 = 20000×1×5/ 100 = 1000

Amount after 4th instalment = 20000- 20000 = 0

Balance of debt for the fifth year = 2500+2250+1750+1000 =7500 - A field is 90 metre long and 50 metre broad. A 25 metre long, 20 metre broad and 4 metre deep tank dug in the field and the earth taken out is spread evenly over the remaining field. How much the level of field will rise?
132.50.52Option D

Area of field = 90 x 50 = 4500 m^2

Area of field dug out = 25 x 20 = 500 m^2

Therefore, Area of remaining field = 4500 – 500 = 4000 m^2

Volume of the earth dug out = 25 x 20 x 4 = 2000 m^3

Therefore, Field will rise by 2000/4000 = 0.5 metre - A cistern has a leak which would empty the cistern in 20 minutes. A tap is turned on which admits 4 liters a minute into the cistern, and it is emptied in 24 minutes. How many liters does the cistern hold ?
420 litres380 litres480 litres390 litres400 litresOption C

1/x – 1/20 = -1/24 x = 120

120 x 4 = 480 litres - There are 2 people who are going to take part in race. The probability that the first one will win is 2/7 and that of other winning is 3/5. What is the probability that one of them will win?
11/3418/3517/3619/3511/35Option D

Prob. of 1st winning = 2/7

Not winning = 1 – 2/7 = 5/7

Prob. of 2nd winning = 3/5

Not winning = 1 – 3/5 = 2/5

Required prob. = 2/7 * 2/5 + 3/5 * 5/7

= 19/35