**Directions(1-5):** What approximate value will come in place of question mark ‘?’ in the following questions.

- 10.05^3 – 27.06^2 – 605.23/10.957 = ?^3
14121068Option D

10.05^3 – 27.06^2 – 605.23/10.957 = ?^3

=>?^3 = 10^3 – 27^2 – 605/11

=> ?^3 = 1000 – 729 – 55

=>?^3 = 216

=>? = 6 - 4320.16 / 15.05 + 7.79*14.15 =?^2
2810252014Option D

4320.16 / 15.05 + 7.79*14.15 =?^2

=>4320 / 15 + 8*14 =?^2

=>288 +112 = ?^2

=>?^2 = 400

=>? = 20 - 24.75% of 20.125% of 30.05% of 2196.06 = ?
3025332022Option C

24.75% of 20.125% of 30.05% of 2196.06 = ?

=>25% of 20% of 30% of 2200 = ?

=>? = 33 - 32.23^2 + 22.03*24.133 – 15.18*11.04 =?
320331300360340Option B

32.23^2 + 22.03*24.133 – 15.18*11.04 =?

=>32^2 + 22*24 – 15*11 = ?

=>1024 – 528 – 165 = ?

=>? = 331 - 64% of 549.75 + 26.05*? = 768.17
1610181214Option A

64% of 549.75 + 26.05*? = 768.17

=>64% of 550 + 26*? =768

=>352 + 26*? = 768

=>26*? = 416

=>? = 16 - Harsh borrows Rs.6375 to be paid back with compound interest at the rate of 4 % pa by the end of 2 year in two equal yearly installments. How much will each instalment will be?
32323000338031003210Option C

25x/26 + 625/676x = 6375

x = (6375 * 676)/1275 = 3380 - P and Q can do a piece of work in 20 and 25 days respectively. They began to work together but P leaves after some days and Q completed the remaining work in 12 days. Number of days after which P left the job-
3.6/8 days4.3/9 days5.7/7 days5.7/9 days2.3/9 daysOption D

(1/20 + 1/25)*T + 12/25 = 1

We will get T = 52/9 = 5.7/9 days - The average salary of the entire staff in a company is Rs 250 per month. The average salary of Engineers is Rs 520 and that of Non-Engineers is Rs. 200. If the number of Engineers is 15, then find the number of Non–Engineers in the office.
7762908152Option D

Let the required number of non–officers = x

200x + 520 x 15 = 250 ( 15 + x )

250x – 200x = 520 * 15 – 250 x 15

50x = 4050

x = 81 - In a business A and B invested amounts in the ratio 2 : 3 whereas the ratio between amount invested by A and B was 4:2. If 2,20,500 was their profit. How much amount did C recieve ?
123000102356142538110250133268Option D

A : B = 4 : 2=> B : A = 2 : 4

A : C = 2 : 3=> 4 : 6

A : B : C =4 : 2 : 6

C share = (6/12)×2,20,500 = 1,10,250 - A card is drawn from a pack of 52 cards. The card is drawn at random; find the probability that it is neither club nor queen?
8/117/129/135/147/19Option C

Required Probability = 1 – [13/52 + 4/52 – 1/52] = 9/13