# Quant Test for IBPS PO Prelims Exam set – 22

1. Lakshya got 5000 as his share out of the total profit of 9000. Yogesh had invested 3000 rupees for 6 months while Lakshya invested for the whole year. Find the amount invested by Lakshya.
1758
1800
1875
1990
1772
Option C
Amount invested by Lakshya = x
12x : 3000*6
x:1500
Lakshya share = [x/(1500+x)]*9000 = 5000
x = 75*25 = 1875

2. The average age of a Shravan and his wife was 25 years when they were married 7 years ago. Now the average age of Shravan, wife and his son is 23 years. Find the age of son now.
4
3
5
2
6
Option C
(s+w – 14)/2 = 25
s+w = 64
Now, (s+w+son)/3 = 23
S = 69-64 = 5 years

3. Hina can do a piece of work in 16 days. Gita can do the same work in 64/5 days, while Sita can do it in 32 days. All of them started to work together but Hina leaves after 4 days. Gita leaves the job 3 days before the completion of the work. How long would the work last?
12
9
7
8
10
Option B
Let the work lasted for x days,
Hina’s 4 day’s work + Gita (x – 3) day’s work + Sita’s x day’s work = 1
⇒ (4/16) + (x – 3) / (64/5) + x/32 = 1
⇒ 5(x – 3)/64 + x/32 = 1 – 1/4
⇒ [5(x – 3) + 2x] / 64 = 3/4
⇒ 7x – 15 = 48
x = (48 + 15)/7 = 63/7 = 9 days

4. Arun takes thrice as long to row a distance against the stream as to row the same distance in favour of the stream. The ratio of the speed of the boat in still water and stream is:
2:3
4:5
2:1
5:6
3:4
Option C
Speed downstream = x kmph
Speed upstream = 3x kmph
(3x+x)/2 : (3x-x)/2
4x/2 : 2x/2 = 2:1

5. A and B are two persons sitting in a circular arrangement with 8 other persons. Find the probability that both A and B sit together.
3/7
2/9
5/8
1/4
3/8
Option B
Total outcomes = (10 -1)! = 9!
Favourable outcomes = (9 -1)!*2!
Probability = 2/9

6. Directions(6-10): Find the values of x and y, compare and choose a correct option.

7. I.x^2 – 26x + 168 = 0
II.y^2 – 30y + 209 = 0
x >= y
x > y
y >= x
No relation
y > x
Option D
I.x^2 – 26x + 168 = 0
=>x^2 – 12x – 14x + 168 = 0
=>(x-12)(x-14) = 0
=>x = 12,14
II.y^2 – 30y + 209 = 0
=>y^2 – 19y – 11y + 209 = 0
=>(y-11)(y-19) = 0
=>y = 11,19
No relation

8. I.x^2 – 3x – 40 = 0
II.y^2 – 17y + 72 = 0
x > y
x >= y
y >= x
y > x
No relation
Option C
I.x^2 – 3x – 40 = 0
=>x^2 – 8x + 5x – 40 = 0
=>(x-8)(x+5) = 0
=>x = 8,-5
II.y^2 – 17y + 72 = 0
=>y^2 – 9y – 8y + 72 = 0
=>(y – 9)(y – 8) = 0
=>y = 9,8
y >= x

9. I.x^2 + 17x + 72 = 0
II.y^2 + 19y + 90 = 0

x > y
x >= y
No relation
y >= x
y > x
Option B
I.x^2 + 17x + 72 = 0
=>x^2 + 9x + 8x + 72 =0
=>(x + 8)(x+9) = 0
=>x = -8,-9
II.y^2 + 19y + 90 = 0
=>y^2 + 10y + 9y + 90 = 0
=>(y+ 9)(y+10) = 0
=>y = -9,-10
x >= y

10. I.x^2 – 19x + 88 = 0
II.y^2 – 27y + 182 = 0
x > y
No relation
x >= y
y > x
y >= x
Option D
I.x^2 – 19x + 88 = 0
=>x^2 – 11x – 8x + 88 = 0
=>(x – 11)(x – 8 ) = 0
=>x = 11,8
II.y^2 – 27y + 182 = 0
=>y^2 – 13y – 14y + 182 = 0
=>(y – 13)(y – 14) = 0
=>y = 13,14
y > x

11. I.x^2 – 8x – 128 = 0
II.y^2 + y – 90 = 0
No relation
x > y
x >= y
y >= x
y > x
Option A
I.x^2 – 8x – 128 = 0
=>x^2 – 16x + 8x – 128 = 0
=>(x – 16)(x+8) = 0
=>x = 16,-8
II.y^2 + y – 90 = 0
=>y^2 + 10y – 9y – 90 = 0
=>(y + 10)(y – 9) = 0
=>y = -10,9
No relation