**Directions(1-5):** Find the missing term ‘?’ of the following number series.

- 4, 11, 25, 53, 109, (?)
200202221213230Option C

4 +1 × 7 = 11

11 + 2 × 7 = 25

25 + 4 × 7 = 53

53 + 8 × 7 = 109

109 + 16 × 7 = 109 + 112 = 221 - 15, 21, 33, 51, 75, (?)
125120200105170Option D

15 + 6 × 1 = 21

21 + 6 × 2 = 33

33 + 6 × 3 = 51

51 + 6 × 4 = 75

75 + 6 × 5 = 105 - 5, 7, 13, 25, 45, (?)
6080918775Option E

5 + 1 × 2 = 7

7 + 2 × 3 = 13

13 + 3 × 4 = 25

25 + 4 × 5 = 45

45 + 5 × 6 = 75 - 483, 471,435, 375, 291, (?)
170183175189195Option B

483 – 1 × 12 = 483 – 12 = 471

471 – 3 × 12 = 471 – 36 = 435

435 – 5 × 12 = 435 – 60 = 375

375 – 7 × 12 = 375 – 84 = 291

291 – 9 × 12 = 291 – 108 = 183 - 11, 15, 31, 67, 131, (?)
220250262231250Option D

11 + 2^2 = 11 + 4 = 15

15 + 4^2 = 15 + 16 = 31

31 + 6^2 = 31 + 36 = 67

67 + 8^2 = 67 + 64 = 131

131 + 10^2 = 131 + 100 = 231 - A starts business with Rs. 7000 and after 5 months, B joins with A as his partner. After 1 year, the profit is divided in the ratio 2 : 3. What is B’s contribution in the capital?
1562017500180001520019250Option C

Let B’s capital be Rs. x. Then.

(7000 x 12) / 7x = 2/3

=>14x = 252000

=> x = 18000 - A cricketer has completed 10 innings and his average is 21.5 runs. How many runs must he make in his next innings so as to raise his average to 24?
5560454932Option D

Total of 10 innings = 21.5 x 10 = 215

Average in 11 innings =(215 + a) / 11= 24

a = 264-215 = 49 - Rohit invested 20000 rupee in fixed deposit at the rate of 10% simple interest. After every 3 rd year he added interest to principal. Find the interest earned at the end of 6th year.
62008100780077006000Option C

For the first 3 years SI will be = 20000*10/100*3 = 6000

Now he add 3000 to the principal i.e = 20000+6000 = 26000

Now interest earned at end of 6th year = 26000*10/100*3 = 7800 - P sold his scooter to Q at a loss of 20%. Q spent rupees 1500 on its repair and sold the scooter to R for 42000, thereby making a profit of 5%. Find the cost of scooter for P?
4520035200481254000051200Option C

Cost of P is CP,

Cost for Q = (80/100)*cp + 1500

Selling price of Q = 42000 = (105/100)*[(80/100)*cp + 1500] cp = 48125 - A bag contains 5 red balls and 7 blue balls. Two balls are drawn at random without replacement, and then find the probability of that one is red and other is blue.
30/6133/6835/6641/6150/67Option C

Required Probability = (5/12)*(7/11) + (7/12)*(5/11) = 35/66