# Quant Test for IBPS PO Prelims Exam set – 23

Directions(1-5): Find the missing term ‘?’ of the following number series.

1. 4, 11, 25, 53, 109, (?)
200
202
221
213
230
Option C
4 +1 × 7 = 11
11 + 2 × 7 = 25
25 + 4 × 7 = 53
53 + 8 × 7 = 109
109 + 16 × 7 = 109 + 112 = 221

2. 15, 21, 33, 51, 75, (?)
125
120
200
105
170
Option D
15 + 6 × 1 = 21
21 + 6 × 2 = 33
33 + 6 × 3 = 51
51 + 6 × 4 = 75
75 + 6 × 5 = 105

3. 5, 7, 13, 25, 45, (?)
60
80
91
87
75
Option E
5 + 1 × 2 = 7
7 + 2 × 3 = 13
13 + 3 × 4 = 25
25 + 4 × 5 = 45
45 + 5 × 6 = 75

4. 483, 471,435, 375, 291, (?)
170
183
175
189
195
Option B
483 – 1 × 12 = 483 – 12 = 471
471 – 3 × 12 = 471 – 36 = 435
435 – 5 × 12 = 435 – 60 = 375
375 – 7 × 12 = 375 – 84 = 291
291 – 9 × 12 = 291 – 108 = 183

5. 11, 15, 31, 67, 131, (?)
220
250
262
231
250
Option D
11 + 2^2 = 11 + 4 = 15
15 + 4^2 = 15 + 16 = 31
31 + 6^2 = 31 + 36 = 67
67 + 8^2 = 67 + 64 = 131
131 + 10^2 = 131 + 100 = 231

6. A starts business with Rs. 7000 and after 5 months, B joins with A as his partner. After 1 year, the profit is divided in the ratio 2 : 3. What is B’s contribution in the capital?
15620
17500
18000
15200
19250
Option C
Let B’s capital be Rs. x. Then.
(7000 x 12) / 7x = 2/3
=>14x = 252000
=> x = 18000

7. A cricketer has completed 10 innings and his average is 21.5 runs. How many runs must he make in his next innings so as to raise his average to 24?
55
60
45
49
32
Option D
Total of 10 innings = 21.5 x 10 = 215
Average in 11 innings =(215 + a) / 11= 24
a = 264-215 = 49

8. Rohit invested 20000 rupee in fixed deposit at the rate of 10% simple interest. After every 3 rd year he added interest to principal. Find the interest earned at the end of 6th year.
6200
8100
7800
7700
6000
Option C
For the first 3 years SI will be = 20000*10/100*3 = 6000
Now he add 3000 to the principal i.e = 20000+6000 = 26000
Now interest earned at end of 6th year = 26000*10/100*3 = 7800

9. P sold his scooter to Q at a loss of 20%. Q spent rupees 1500 on its repair and sold the scooter to R for 42000, thereby making a profit of 5%. Find the cost of scooter for P?
45200
35200
48125
40000
51200
Option C
Cost of P is CP,
Cost for Q = (80/100)*cp + 1500
Selling price of Q = 42000 = (105/100)*[(80/100)*cp + 1500] cp = 48125

10. A bag contains 5 red balls and 7 blue balls. Two balls are drawn at random without replacement, and then find the probability of that one is red and other is blue.
30/61
33/68
35/66
41/61
50/67
Option C
Required Probability = (5/12)*(7/11) + (7/12)*(5/11) = 35/66