Quant Test for IBPS PO Prelims Exam set – 28

Directions(1-5): What approximate value will come in place of question mark ‘?’ in the following questions.

  1. 16.12*15.94 + 654.92 – 344.83 = ?*5.95
    88
    84
    90
    80
    95
    Option C
    16.12*15.94 + 654.92 – 344.83 = ?*5.95
    =>16*16 + 655 – 345 = ?*6
    =>256 +655 – 345 = ?*6
    =>911 – 345 = ?*6
    =>566/6 =?
    =>? = 90

     

  2. 35.1% of 1599 = ? – (449.96/6.12)*2
    620
    655
    750
    815
    710
    Option E
    35.1% of 1599 = ? – (449.96/6.12)*2
    =>35% of 1600 = ? – (450/6)*2
    =>560 = ? – 75*2
    =>560 = ? – 150
    =>? = 710

     

  3. 30.11*(1025)^1/2 + 196 = ?^2 – 287
    40
    38
    25
    30
    48
    Option B
    30.11*(1025)^1/2 + 196 = ?^2 – 287
    =>30*(1024)^1/2 + 196 = ?^2 – 287
    =>30*32 + 196 = ?^2 – 287
    =>960 + 196 + 287 = ?^2
    =>?^2 = 1444
    =>? = 38

     

  4. 18.003*3.99 *(135.003 / 26.97) – ( 15.001*3.94) = ?
    289
    250
    300
    350
    324
    Option C
    18.003*3.99 *(135.003 / 26.97) – ( 15.001*3.94) = ?
    =>18*4*(135/27)- (15*4) = ?
    =>72*5 – 60 = ?
    =>? = 360 – 60
    =>? = 300

     

  5. 41.97 *5.12/2.99 + 49.89 = ?*1.99
    55
    45
    40
    52
    60
    Option E
    41.97 *5.12/2.99 + 49.89 = ?*1.99
    =>42*5 /3 + 50 = ?*2
    =>70 + 50 = ?*2
    =>? = 60

     

  6. A pipe can fill a cistern in 8 hours. After half the tank is filled, three more similar taps are opened. What is the total time taken to fill the cistern completely?
    6
    4
    5
    8
    9
    Option C
    Part filled by P and Q = In One hour pipe can fill = 1/8
    Time is taken to fill half of the tank = 1/2 * 8 = 4 hours
    Part filled by four pipes in one hour = (4*1/8) = 1/2
    Required Remaining Part = 1/2
    Total time = 4 + 1 = 5 hours

     

  7. Dhipan borrowed Rs.800 at 6% per annum and Shahrukh borrowed Rs.600 @ 10% per annum. After how much time, will they both have equal debts?
    50/3
    42/3
    51/2
    47/3
    53/3
    Option A
    800+(800*6*T)/100 = 600+(600*10*T)/100
    T=50/3 yr.

     

  8. The perimeter of a rectangular ppalyground is 210 m. Find the cost of gardening 2 m broad boundary around rectangular playground whose perimeter The cost of gardening is Rs 14 per m2.
    5210
    6200
    6104
    6000
    5480
    Option C
    Given 2(l+b) = 210
    2 m broad boundary means increase in l and b by 4 m
    So area of the boundary will be [(l+4)(b+4) – lb] = 4(l+b) + 16 = 2*[2(l+b)] + 16 = 2*210 + 16 = 436 m2
    So cost of gardening = 436*14 = Rs. 6104

     

  9. One type of liquid contains 20 percent of milk and second type of liquid contains 40 percent milk. If 4 part of the first and 6 part of the second are mix, then what is the percent of water in the mixture.
    74%
    70%
    68%
    60%
    50%
    Option C
    Let water = 80ltr and 60ltr in first and second mixture respectively
    Percent of water = [(80*4 + 60*6)/1000]100 = 68%

     

  10. A urn contains 4 red balls, 5 green balls and 6 white balls, if one ball is drawn at random, find the probability that it is neither red nor white.
    1/5
    1/7
    1/6
    1/3
    1/4
    Option D
    Probability = 5c1/15c1 = 1/3

     


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