**Directions(1-5):** Find the missing term ‘?’ of the following number series.

- 5, 11, ?, 55, 117
1215202530Option D

5 × 2 + 1 = 11

11 × 2 + 3 = 25

25 × 2 + 5 = 55

55 × 2 + 7 = 117

? = 25 - 3, 10, 21, ?, 51
3022181434Option E

Difference of difference

? = 34 - 5, 6, ?, 57, 244
1015181613Option D

5 × 1 + (1)^2 = 6

6 × 2 + (2)^2 = 16

16 × 3 + (3)^2 = 57

57 × 4 + (4)^2 = 244

? = 16 - 5, 3, 4, ?, 38
1519121017Option D

*1-2

*2-2

*3-2

*4-2

? = 10 - 3, 10, 32, 100, ?
225312308320290Option C

*3+1

*3+2

*3+4

*3+8

? = 308 - Fifteen years ago, Maya’s mother was thrice of Maya’s age and two years ago Maya’s Mother was twice of Maya’s age. What is the present age of Maya’s Mother ?
5045545948Option C

Maya’s mother age = R1

Maya’s age = M2

M1 – 15 = 3 *(M2 – 15) —(1)

M1 – 2 = 2 *(M2 – 2) —(2)

From eqn (1) and (2)

M1 = 54 years - A and B undertake to complete a piece of work for Rupees 1200. A can do it in 8 days, B can do it in 12 days and with the help of C they complete the work in 4 days. Find the share of C?
190185215200220Option D

1/8 + 1/12 + 1/C = 1/4, we get C = 24 days

now efficiency of A, B and C are in the ratio of 1/8 :1/12 : 1/24

3:2:1, so share of C is 1/6 * 1200 = 200 - A starts a business with Rs 20,000 and after 4 months B also joins with some capital. After a year, the profit is divided between them in the ratio 5 : 3. How much did B invested?
2000016000120001800010000Option D

Let B invests Rs x, then ratio of their profits

20000*12 : x*8 = 30,000 : x

So 30,000/x = 5/3

Solve, x = 18,000 - The ratio of the number of boys and girls in a school is 3:2. If 20% of the boys and 25% of the girls are scholarship holders, the percentage of the students who are not scholarship holders is:
88%72%78%81%70%Option C

Consider Total no of students = 100

Ratio is 3:2 i.e Boys=60 and Girls=40

20% of boys who get scholarship = 60*20/100=12%

25% of girls who get scholarship = 40*25/100 =10%

Therefore % of students who do not get scholarship =100-(12+10) = 78% - A and B are two friends standing in a circular arrangement with 10 more people. Find the probability that exactly 3 persons are seated between A and B.
5/113/112/116/114/11Option C

Fix P at one point then number of places where B can be seated is 11.

Now, exactly three persons can be seated between A and B, so only two places where B can be seated.

So, Probability = 2/11