**Directions(1-5):** What approximate value will come in place of question mark ‘?’ in the following questions.

- 42*5.12/2.99 + 49.89 = ?*1.99
5484605078Option C

42*5.12/2.99 + 49.89 = ?*1.99

=>42*5/3 + 50 = ?*2

=>70+50 = ?*2

=>? = 60 - 18.18*3.99 *(135.003 / 26.87) – (15.001*3.89) = ?
356378313300389Option D

18.18*3.99 *(135.003 / 26.87) – (15.001*3.89) = ?

=>18*4 *(135/27) – (15*4) = ?

=>72*5 – 60 = ?

=>? = 360 -60

=>? = 300 - 30.01*(1024)^1/2 + 196 = ?^2 – 287
3038445061Option B

30.01*(1024)^1/2 + 196 = ?^2 – 287

=>30*32 + 196 = ?^2 – 287

=>960 + 196 = ?^2 – 287

=>?^2 = 1444

=>? = 38 - 35.2% of 1599 = ? – (449.92/6.12)*2
759700647652770Option B

35.2% of 1599 = ? – (449.92/6.12)*2

=>35% of 1600 = ? – (450/6)*2

=>560 = ? – 75*2

=>560 = ? – 150

=>? = 700 - 16.12 * 15.94 + 654.92 – 344.84 = ?*5.93
8882907894Option C

16.12 * 15.94 + 654.92 – 344.84 = ?*5.93

=>16*16 + 655 – 345 = ?*6

=>256 + 655 – 345 = ?*6

=>? = 90 - A boatman goes 2 km against the current of the stream in 1 hour and goes 1 km along the current in 10 minutes. How long will it take to go 5 km in stationary water?
3.05 hrs.2.17 hrs.1.25 hrs.2.14 hrs.3.05 hrs.Option C

Downstream =(1x 60)/10 = 6 kmph

Rate upstream = 2 km/hr.

Speed in still water =(6 + 2) /2= 4 kmph

Time = 5/4 = 1.25 hrs. - In a right angled triangle smallest side of is 13 cm less than the side of a square of perimeter 72 cm. Second largest side of the right angled triangle is 2 cm less than the length of the rectangle of area 112 cm² and breadth 8 cm. What is the largest side of the right angled triangle?
17 cm10 cm13 cm12 cm19 cmOption C

Side of square = 72/4 = 18 cm

Smallest side of the right angled triangle = 18 – 13 = 5 cm

Length of rectangle = 112/8 = 14 cm

Second side of the right angled triangle = 14 – 2 = 12 cm

Hypotenuse of the right angled triangle = √(25 + 144) = 13 cm - 3 years ago, the average age of A, B, and C was 27 years. Also 5 years ago, the average age of B and C was 20 years. What is the present age of A?
2040508090Option B

Sum of ages of A+B+C 3 yrs ago = 27*3 = 81

After 3 yrs, i.e. at present their total = 81 + 3*3 = 90

Similarly sum of present age of B&C = 20*2 +5*2 = 50

Present age of A = 90-50 = 40 - If the difference between the simple interest and compound interests on some principal amount at 20% for 3 years is Rs. 48, then the principal amount is:
Rs. 327Rs. 313Rs. 320Rs. 300Rs. 375Option E

Sum = Difference x (100)^3

r^2(300 + r)

= 48 x (100)^3

20^2 (300 + 20)

= Rs. 375 - In a team of 6 boys and 8 girls, 5 students have to be selected. In how many ways it can be done so that at least 2 boys are included.
17481947137915261500Option D

No. of ways = 6c2*5c3 + 6c3*5c2 + 6c4*5c1 + 6c5 = 1526