Quant Test for IBPS PO Prelims Exam set – 4

Directions(1-5): What approximate value will come in place of question mark ‘?’ in the following questions.

  1. 42*5.12/2.99 + 49.89 = ?*1.99
    54
    84
    60
    50
    78
    Option C
    42*5.12/2.99 + 49.89 = ?*1.99
    =>42*5/3 + 50 = ?*2
    =>70+50 = ?*2
    =>? = 60

     

  2. 18.18*3.99 *(135.003 / 26.87) – (15.001*3.89) = ?
    356
    378
    313
    300
    389
    Option D
    18.18*3.99 *(135.003 / 26.87) – (15.001*3.89) = ?
    =>18*4 *(135/27) – (15*4) = ?
    =>72*5 – 60 = ?
    =>? = 360 -60
    =>? = 300

     

  3. 30.01*(1024)^1/2 + 196 = ?^2 – 287
    30
    38
    44
    50
    61
    Option B
    30.01*(1024)^1/2 + 196 = ?^2 – 287
    =>30*32 + 196 = ?^2 – 287
    =>960 + 196 = ?^2 – 287
    =>?^2 = 1444
    =>? = 38

     

  4. 35.2% of 1599 = ? – (449.92/6.12)*2
    759
    700
    647
    652
    770
    Option B
    35.2% of 1599 = ? – (449.92/6.12)*2
    =>35% of 1600 = ? – (450/6)*2
    =>560 = ? – 75*2
    =>560 = ? – 150
    =>? = 700

     

  5. 16.12 * 15.94 + 654.92 – 344.84 = ?*5.93
    88
    82
    90
    78
    94
    Option C
    16.12 * 15.94 + 654.92 – 344.84 = ?*5.93
    =>16*16 + 655 – 345 = ?*6
    =>256 + 655 – 345 = ?*6
    =>? = 90

     

  6. A boatman goes 2 km against the current of the stream in 1 hour and goes 1 km along the current in 10 minutes. How long will it take to go 5 km in stationary water?
    3.05 hrs.
    2.17 hrs.
    1.25 hrs.
    2.14 hrs.
    3.05 hrs.
    Option C
    Downstream =(1x 60)/10 = 6 kmph
    Rate upstream = 2 km/hr.
    Speed in still water =(6 + 2) /2= 4 kmph
    Time = 5/4 = 1.25 hrs.

     

  7. In a right angled triangle smallest side of is 13 cm less than the side of a square of perimeter 72 cm. Second largest side of the right angled triangle is 2 cm less than the length of the rectangle of area 112 cm² and breadth 8 cm. What is the largest side of the right angled triangle?
    17 cm
    10 cm
    13 cm
    12 cm
    19 cm
    Option C
    Side of square = 72/4 = 18 cm
    Smallest side of the right angled triangle = 18 – 13 = 5 cm
    Length of rectangle = 112/8 = 14 cm
    Second side of the right angled triangle = 14 – 2 = 12 cm
    Hypotenuse of the right angled triangle = √(25 + 144) = 13 cm

     

  8. 3 years ago, the average age of A, B, and C was 27 years. Also 5 years ago, the average age of B and C was 20 years. What is the present age of A?
    20
    40
    50
    80
    90
    Option B
    Sum of ages of A+B+C 3 yrs ago = 27*3 = 81
    After 3 yrs, i.e. at present their total = 81 + 3*3 = 90
    Similarly sum of present age of B&C = 20*2 +5*2 = 50
    Present age of A = 90-50 = 40

     

  9. If the difference between the simple interest and compound interests on some principal amount at 20% for 3 years is Rs. 48, then the principal amount is:
    Rs. 327
    Rs. 313
    Rs. 320
    Rs. 300
    Rs. 375
    Option E
    Sum = Difference x (100)^3
    r^2(300 + r)
    = 48 x (100)^3
    20^2 (300 + 20)
    = Rs. 375

     

  10. In a team of 6 boys and 8 girls, 5 students have to be selected. In how many ways it can be done so that at least 2 boys are included.
    1748
    1947
    1379
    1526
    1500
    Option D
    No. of ways = 6c2*5c3 + 6c3*5c2 + 6c4*5c1 + 6c5 = 1526

     


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