**Institute of Banking Personnel Selection (IBPS)** had released the official notification for the Common Recruitment Process for RRBs (CRP RRBs VII) for the recruitment of Group “A”-Officers (Scale-I, II & III) and Group “B”-Office Assistant (Multipurpose)

Click here to know the details of the Examination

The examination will be held in two phases i.e. Preliminary Examination and Main Examination. The **RRB Scale I** Preliminary Exam is scheduled on 11th, 12th & 18th of August 2018. And **RRB Assistant** Preliminary Exam is scheduled on 19th, 25th August & 1st September 2018**. **Details of the exam are as under:

Practice the questions so as to familiarize yourself with the pattern of questions to be asked in the exam.

**Directions(1-5):** Find the relation between x and y and choose a correct option.

- I. (x–8) (2y+9) = 25

II. (2x–16) (y–4) = 8x>=yx>yy>xy>=xx=y or relation cannot be established.Option B

I. 2xy+9x–16y–72 = 25

x= 9

II. 2xy–8x–16y+64 = 8

y = 8

x>y - I. 6x^2–19x–36 = 0

II. 4y^2–47y+120 = 0y>xy>=xx>=yx>yx=y or relation cannot be established.Option E

I. 6x^2–19x–36 = 0

6x^2–27x+8x–36 = 0

x = 27/6 = 4.5

x = – 8/6 = –1.33

II. 4y2–47y+120 = 0

4y2–32y–15y+120 = 0

y = 32/4 = 8, 15/4 = 3.75

No relation. - I. x^2+14x+48 = 0

II. y^2+11y+30 = 0x=y or relation cannot be established.y>xy>=xx>=yx>yOption C

I. x^2+14x+48 = 0

x^2+8x+6x+48 = 0

x = –8, –6

II.y^2+11y+30 = 0

y^2+5y+6y+30 = 0

y = –5,–6

y>=x - I. x^2 – 3481 = 0

II.y^2 –118y +3481 = 0x>yx=y or relation cannot be established.x>=yy>=xy>xOption D

I. x^2 – 3481=0

x^2 = 3481

x = ±59

II. y^2 –118y +3481 = 0

y ^2 –59y–59y +3481 = 0

y = +59, +59

y>=x - I. x^2 – 50x + 621 = 0

II. y^2 – 42y + 437 = 0y>=xx>yx>=yy>xx=y or relation cannot be established.Option C

I. x^2 – 50x + 621 = 0

x^2 – 23x – 27x + 621 = 0

x = +23, +27

II. y^2 – 42y + 437 = 0

y^2 – 19y – 23y + 437 = 0

y = +19, +23

x>=y - The no. of men in year 2006 is what percent more or less than the no. of women in the same year?
10% more20% less45% more50% more50% lessOption D

Required percentage = 1/2 × 100 = 50% more - Find the difference between total no. of men in the years 2006 and 2008 together and total no. of women in the years 2005 and 2009 together?
40 lakhs50 lakhs42 lakhs35 lakhs30 lakhsOption D

Required difference

= (3 × 29 + 9 × 8) – (13 × 4 + 12 × 6)

= 159 – 124 = 35 lakhs - The total no. of men in the year 2007 is approximately what percent of total no. of women in the year 2008?
125%121%145%110%132%Option B

Required percentage

= (5 × 15.5) × 100 /( 8 × 8 )

= 121.09% == 121% - In which year the no. of women is least?
20052007200820042009Option B

No. of women in year 2005 = 4/11 × 143 = 52 lakh

In year 2006 = 2/5 × 145 = 58 lakh

In year 2007 = 3/8 × 124 = 46.5 lakh

In year 2008 = 8/17 × 136 = 64 lakh

In year 2009 = 12/25 × 150 = 72 lakh

No. of women is min. in year 2007. - What is the approximate average no. of women in the years 2005, 2007 and 2009 together?
63 lakhs50 lakhs42 lakhs57 lakhs29 lakhsOption D

Required average

= 1/3 × (4 × 13 + 3 × 15.5 + 12 × 6)

= 56.833 == 57 lakhs

**Directions(6-10):** Study the table given below and answer the questions that follow: