# Quant Test for IBPS RRB 2018 Prelim Exam Set – 15

Institute of Banking Personnel Selection (IBPS) had released the official notification for the Common Recruitment Process for RRBs (CRP RRBs VII) for the recruitment of Group “A”-Officers (Scale-I, II & III) and Group “B”-Office Assistant (Multipurpose)

Click here to know the details of the Examination

The examination will be held in two phases i.e. Preliminary Examination and Main Examination. The RRB Scale I Preliminary Exam is scheduled on 11th, 12th & 18th of August 2018. And RRB Assistant Preliminary Exam is scheduled on 19th, 25th August & 1st September 2018Details of the exam are as under: Practice the questions so as to familiarize yourself with the pattern of questions to be asked in the exam.

Directions(1-5): Find the relation between x and y and choose a correct option.

1. I. (x–8) (2y+9) = 25
II. (2x–16) (y–4) = 8

x>=y
x>y
y>x
y>=x
x=y or relation cannot be established.
Option B
I. 2xy+9x–16y–72 = 25
x= 9
II. 2xy–8x–16y+64 = 8
y = 8
x>y

2. I. 6x^2–19x–36 = 0
II. 4y^2–47y+120 = 0

y>x
y>=x
x>=y
x>y
x=y or relation cannot be established.
Option E
I. 6x^2–19x–36 = 0
6x^2–27x+8x–36 = 0
x = 27/6 = 4.5
x = – 8/6 = –1.33
II. 4y2–47y+120 = 0
4y2–32y–15y+120 = 0
y = 32/4 = 8, 15/4 = 3.75
No relation.

3. I. x^2+14x+48 = 0
II. y^2+11y+30 = 0

x=y or relation cannot be established.
y>x
y>=x
x>=y
x>y
Option C
I. x^2+14x+48 = 0
x^2+8x+6x+48 = 0
x = –8, –6
II.y^2+11y+30 = 0
y^2+5y+6y+30 = 0
y = –5,–6
y>=x

4. I. x^2 – 3481 = 0
II.y^2 –118y +3481 = 0

x>y
x=y or relation cannot be established.
x>=y
y>=x
y>x
Option D
I. x^2 – 3481=0
x^2 = 3481
x = ±59
II. y^2 –118y +3481 = 0
y ^2 –59y–59y +3481 = 0
y = +59, +59
y>=x

5. I. x^2 – 50x + 621 = 0
II. y^2 – 42y + 437 = 0

y>=x
x>y
x>=y
y>x
x=y or relation cannot be established.
Option C
I. x^2 – 50x + 621 = 0
x^2 – 23x – 27x + 621 = 0
x = +23, +27
II. y^2 – 42y + 437 = 0
y^2 – 19y – 23y + 437 = 0
y = +19, +23
x>=y

6. Directions(6-10): Study the table given below and answer the questions that follow: 7. The no. of men in year 2006 is what percent more or less than the no. of women in the same year?
10% more
20% less
45% more
50% more
50% less
Option D
Required percentage = 1/2 × 100 = 50% more

8. Find the difference between total no. of men in the years 2006 and 2008 together and total no. of women in the years 2005 and 2009 together?
40 lakhs
50 lakhs
42 lakhs
35 lakhs
30 lakhs
Option D
Required difference
= (3 × 29 + 9 × 8) – (13 × 4 + 12 × 6)
= 159 – 124 = 35 lakhs

9. The total no. of men in the year 2007 is approximately what percent of total no. of women in the year 2008?
125%
121%
145%
110%
132%
Option B
Required percentage
= (5 × 15.5) × 100 /( 8 × 8 )
= 121.09% == 121%

10. In which year the no. of women is least?
2005
2007
2008
2004
2009
Option B
No. of women in year 2005 = 4/11 × 143 = 52 lakh
In year 2006 = 2/5 × 145 = 58 lakh
In year 2007 = 3/8 × 124 = 46.5 lakh
In year 2008 = 8/17 × 136 = 64 lakh
In year 2009 = 12/25 × 150 = 72 lakh
No. of women is min. in year 2007.

11. What is the approximate average no. of women in the years 2005, 2007 and 2009 together?
63 lakhs
50 lakhs
42 lakhs
57 lakhs
29 lakhs
Option D
Required average
= 1/3 × (4 × 13 + 3 × 15.5 + 12 × 6)
= 56.833 == 57 lakhs