Quant Test for IBPS RRB 2018 Prelim Exam Set – 15

Institute of Banking Personnel Selection (IBPS) had released the official notification for the Common Recruitment Process for RRBs (CRP RRBs VII) for the recruitment of Group “A”-Officers (Scale-I, II & III) and Group “B”-Office Assistant (Multipurpose)

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The examination will be held in two phases i.e. Preliminary Examination and Main Examination. The RRB Scale I Preliminary Exam is scheduled on 11th, 12th & 18th of August 2018. And RRB Assistant Preliminary Exam is scheduled on 19th, 25th August & 1st September 2018. Details of the exam are as under:

Practice the questions so as to familiarize yourself with the pattern of questions to be asked in the exam. 

Directions(1-5): Find the relation between x and y and choose a correct option.

1. I. (x–8) (2y+9) = 25
   II. (2x–16) (y–4) = 8
   x>=y
   x>y
   y>x
   y>=x
   x=y or relation cannot be established.
   Option B
   I. 2xy+9x–16y–72 = 25
   x= 9
   II. 2xy–8x–16y+64 = 8
   y = 8
   x>y

    

2. I. 6x^2–19x–36 = 0
   II. 4y^2–47y+120 = 0
   y>x
   y>=x
   x>=y
   x>y
   x=y or relation cannot be established.
   Option E
   I. 6x^2–19x–36 = 0
   6x^2–27x+8x–36 = 0
   x = 27/6 = 4.5
   x = – 8/6 = –1.33
   II. 4y2–47y+120 = 0
   4y2–32y–15y+120 = 0
   y = 32/4 = 8, 15/4 = 3.75
   No relation.

    

3. I. x^2+14x+48 = 0
   II. y^2+11y+30 = 0
   x=y or relation cannot be established.
   y>x
   y>=x
   x>=y
   x>y
   Option C
   I. x^2+14x+48 = 0
   x^2+8x+6x+48 = 0
   x = –8, –6
   II.y^2+11y+30 = 0
   y^2+5y+6y+30 = 0
   y = –5,–6
   y>=x

    

4. I. x^2 – 3481 = 0
   II.y^2 –118y +3481 = 0
   x>y
   x=y or relation cannot be established.
   x>=y
   y>=x
   y>x
   Option D
   I. x^2 – 3481=0
   x^2 = 3481
   x = ±59
   II. y^2 –118y +3481 = 0
   y ^2 –59y–59y +3481 = 0
   y = +59, +59
   y>=x

    

5. I. x^2 – 50x + 621 = 0
   II. y^2 – 42y + 437 = 0
   y>=x
   x>y
   x>=y
   y>x
   x=y or relation cannot be established.
   Option C
   I. x^2 – 50x + 621 = 0
   x^2 – 23x – 27x + 621 = 0
   x = +23, +27
   II. y^2 – 42y + 437 = 0
   y^2 – 19y – 23y + 437 = 0
   y = +19, +23
   x>=y

    

Directions(6-10): Study the table given below and answer the questions that follow:


6. The no. of men in year 2006 is what percent more or less than the no. of women in the same year?
   10% more
   20% less
   45% more
   50% more
   50% less
   Option D
   Required percentage = 1/2 × 100 = 50% more

    

7. Find the difference between total no. of men in the years 2006 and 2008 together and total no. of women in the years 2005 and 2009 together?
   40 lakhs
   50 lakhs
   42 lakhs
   35 lakhs
   30 lakhs
   Option D
   Required difference
   = (3 × 29 + 9 × 8) – (13 × 4 + 12 × 6)
   = 159 – 124 = 35 lakhs

    

8. The total no. of men in the year 2007 is approximately what percent of total no. of women in the year 2008?
   125%
   121%
   145%
   110%
   132%
   Option B
   Required percentage
   = (5 × 15.5) × 100 /( 8 × 8 )
   = 121.09% == 121%

    

9. In which year the no. of women is least?
   2005
   2007
   2008
   2004
   2009
   Option B
   No. of women in year 2005 = 4/11 × 143 = 52 lakh
   In year 2006 = 2/5 × 145 = 58 lakh
   In year 2007 = 3/8 × 124 = 46.5 lakh
   In year 2008 = 8/17 × 136 = 64 lakh
   In year 2009 = 12/25 × 150 = 72 lakh
   No. of women is min. in year 2007.

    

10. What is the approximate average no. of women in the years 2005, 2007 and 2009 together?
    63 lakhs
    50 lakhs
    42 lakhs
    57 lakhs
    29 lakhs
    Option D
    Required average
    = 1/3 × (4 × 13 + 3 × 15.5 + 12 × 6)
    = 56.833 == 57 lakhs