**Institute of Banking Personnel Selection (IBPS)** had released the official notification for the Common Recruitment Process for RRBs (CRP RRBs VII) for the recruitment of Group “A”-Officers (Scale-I, II & III) and Group “B”-Office Assistant (Multipurpose)

Click here to know the details of the Examination

The examination will be held in two phases i.e. Preliminary Examination and Main Examination. The **RRB Scale I** Preliminary Exam is scheduled on 11th, 12th & 18th of August 2018. And **RRB Assistant** Preliminary Exam is scheduled on 19th, 25th August & 1st September 2018**. **Details of the exam are as under:

Practice the questions so as to familiarize yourself with the pattern of questions to be asked in the exam.

- 3, 52, 88, 113, 129, ?
138111125105130Option A

+7^2,+6^2,+5^2,+4^2,+3^2

? = 138 - 2, 3, 8, ?, 112, 565
1025182730Option D

*1+1 *2+2 *3+3 *4+4 *5+5

? = 27 - 8, 64, 216, 512, ?, 1728
10001200105013301500Option A

2^3,4^3,6^3,8^3,10^3,12^3

? = 1000 - 5, 11, 32, 108, 444, ?
23002030223025002110Option C

*1+1*6

*2+2*5

*3+3*4

*4+4*3

*5+5*2

? = 2230 - 6, 4, 8, 23, ?, 385.25
74.384.560.475.581.5Option B

*0.5+1

*1.5+2

*2.5+3

*3.5+4

*4.5+5

? = 84.5 - If 2/3 part of an article is sold at 30% profit, 1/4 part at 16% profit and remaining part at 12% profit and finally, there is a profit of Rs.75, then find the cost price of the article.
500600400100300Option E

Here a = 2/3

b =1/4

x = 30 %

y = 16 %

z = 12 % and R = Rs. 75

Required CP of article

= (75*100)/(2/3*30+1/4*16+1/12*12)

= 7500/25

= 300 - Two pipes can fill a tank in 20 and 24 minutes respectively and a waste pipe can empty 3 gallons per minute. All the three pipes working together can fill the tank in 15 minutes. What is the capacity of the tank?
150 gallons120 gallons130 gallons100 gallons80 gallonsOption B

Work done by the waste pipe in 1 minute

= 1/15 − ( 1/20 + 1/24 ) = 1/15 − 11/120 = −1/40

Volume of 1/40 part = 3 gallons

Volume of whole = (3 x 40) gallons

= 120 gallons. - Raju got married 8 years ago. His present age is 6/5 times his age at the time of his marriage. Raju’s sister was 10years younger to him at the time of his marriage. Find the present age of Raju’s sister.
40 years18 years20 years38 years35 yearsOption D

Let Raju’s age at the time of his marriage = x years

Then from given data => x + 8 = 6x/5

x = 40.

Since got married 8 years ago, his present age = 48

His sister is 10 years younger

=> 48 – 10 = 38 years. - A sum of money at simple interest amounts to Rs. 14160 in 3 year. If the rate of interest is increased by 25%, the same sum amount to Rs. 14700 in the same time. Find the rate of interest.
7%3%5%6%4%Option D

14160 = P + (P × R × 3)/ 100

=> 3PR/ 100 = 14160 – P

=> 14700 = P + (P ×1.25R × 3)/ 100

=> P + 5/4 × 3PR/100 = 14700

=> P + 5/4(14160 − P) = 14700

=> 4P + 70800 – 5P = 58800

=> P = 12000

=> 14160 = 12000 + (12000 × R × 3)/100

=> 14160 = 12000 + (120 × R × 3)

=> 14160 – 12000 = 360R

=> 2160 = 360R

=> R = 2160/360 = 6% - Twelve persons are seated at a circular table. Find the probability that 3 particular persons always seated together.
3/504/552/513/553/53Option D

Total probability = (12-1)! = 11!

Desired probability = (10 – 1)! = 9!

Required Probability = (9! *3!) /11!

= 3/55