Quant Test for IBPS RRB 2018 Prelim Exam Set – 2

Institute of Banking Personnel Selection (IBPS) had released the official notification for the Common Recruitment Process for RRBs (CRP RRBs VII) for the recruitment of Group “A”-Officers (Scale-I, II & III) and Group “B”-Office Assistant (Multipurpose)

Click here to know the details of the Examination

The examination will be held in two phases i.e. Preliminary Examination and Main Examination. The RRB Scale I Preliminary Exam is scheduled on 11th, 12th & 18th of August 2018. And RRB Assistant Preliminary Exam is scheduled on 19th, 25th August & 1st September 2018Details of the exam are as under:

Practice the questions so as to familiarize yourself with the pattern of questions to be asked in the exam. 


 

Directions(1-5): Find the relation between p and q and choose a correct option.

  1. I. p2 – 5p + 6 = 0
    II. q2 – 3q + 2 = 0

    q>p
    p=q or no relation cannot be established.
    p>q
    q>=p
    p>=q
    Option E
    I. p2 – 3p – 2p + 6 = 0
    p(p – 3) -2(p – 3) = 0
    (p – 2)(p – 3) = 0
    p = 2, 3
    II. q2 – 2q – q + 2 = 0
    q(q – 2) -1(q – 2) = 0
    (q – 1)(q – 2) = 0
    q = 1, 2
    p >= q

     

  2. I. p2 + 11p + 30 = 0
    II. q2 – 11q + 30 = 0

    p>q
    p=q or no relation cannot be established.
    q>p
    q>=p
    p>=q
    Option C
    I.p2 + 6p + 5p + 30 = 0
    p(p + 6) +5(p + 6) = 0
    (p + 5) (p + 6) = 0
    p = -5, -6
    II. q2 – 6q – 5q + 30 = 0
    q(q – 6) -5(q – 6) = 0
    (q – 6) (q – 5) = 0
    q = 5, 6
    q>p

     

  3. I. 2p2 – 7p + 3 = 0
    II. 4q2 + 3q – 1= 0

    q>=p
    p>=q
    q>p
    p=q or no relation cannot be established.
    p>q
    Option E
    I. 2p2 – 6p – p + 3 = 0
    2p(p – 3) -1(p – 3) = 0
    (2p – 1)(p- 3) = 0
    p = 1/2,3
    II. 4q2 + 4q – q – 1 = 0
    4q(q + 1) -1(q + 1) = 0
    (4q – 1)(q + 1) = 0
    q = 1/4 ,-1
    p>q

     

  4. I. p2 – 169 = 0
    II. q2 – 28q + 195 = 0

    q>=p
    p=q or no relation cannot be established.
    p>=q
    p>q
    q>p
    Option A
    I. p2= 169
    p = -13, +13
    II. q2 – 15q – 13q + 195 = 0
    q(q – 15) – 13(q – 15) = 0
    (q – 13)(q – 15) = 0
    q = 13, 15
    q>=p

     

  5. I. 4p2 – p – 3 = 0
    II. 2q2 + q – 1 = 0

    p=q or no relation cannot be established.
    p>q
    q>p
    p>=q
    q>=p
    Option A
    I. 4p2 – 4p + 3p – 3 = 0
    4p(p -1)+ 3(p – 1) = 0
    (4p + 3) (p – 1) = 0
    p = 1, -3/4
    II. 2q2 + 2q – q – 1 = 0
    2q(q + 1) -1(q + 1) = 0
    (q + 1)(2q – 1) = 0
    q = 1/2, -1
    No relation

     

  6. There are two mixtures of honey and water, the quantity of honey in them being 25% and 75% of the mixture. If 2 gallons of the first are mixed with three gallons of the second, what will be the ratio of honey to water in the new mixture?
    5:7
    9:11
    2:3
    11:9
    7:5
    Option D
    Required ratio
    = [25/100 × 2 + 75/100 × 3]/ [75/100 × 2 + 25/100 × 3] = 11/9

     

  7. A manufacturer sells a pair of glasses to a wholesale dealer at a profit of 18%. The wholesaler sells the same to a retailer at a profit of 20%. The retailer in turn sells them to a customer for Rs. 30.09, thereby earning a profit of 25%. Find the cost price for the manufacturer.
    17
    23
    21
    15
    12
    Option A
    Cost price for retailer = 30.09 × 4/5 = 24.072
    Cost price for manufacturer = 24.072 × 100/120 × 100/118
    = 24.072 × 5/6 × 50/59
    = 17

     

  8. A contract is to be completed in 50 days and 105 men were set to work, each working 8 hr. a day. After 25 days, 2/5th of the work is finished. How many additional men be employed, so that the work may be completed on time, each man now working 9 hr. a day?
    15
    35
    22
    40
    30
    Option B
    𝑀1𝐷1𝑇1 /𝑊1 = 𝑀2𝐷2𝑇2/𝑊2
    Given 𝑀1 = 105, 𝐷1 = 25, 𝑇1 = 8, 𝑊1 = 2/5
    Now, let the additional men be x.
    Then, 𝑀2 = 105 + 𝑥, 𝑇2 = 9 𝐷2 = 25
    And 𝑊2 = 1 – 2/5 = 3/5
    On putting these values in the above formula.
    [105 × 25 × 8/ 2/5 = [(105 + 𝑥) × 25 × 9]/ 3/5
    = 105 × 8/ 2 = (105 + 𝑥) × 9/3
    = 105 × 4 = (105 + 𝑥) × 3
    = 105 × 4 = 105 × 3 + 3𝑥
    = 3x = 105
    x = 35 men

     

  9. The average monthly income of 4 earning members of a family is Rs. 7350. One member passes away and the average monthly income becomes Rs. 6500. What was the monthly income of the person, who is no more?
    Rs.9550
    Rs.9000
    Rs.9350
    Rs.8500
    Rs.9900
    Option E
    Monthly income of 4 persons = 7350 × 4
    = Rs. 29400
    Monthly income of 3 persons (excluding the dead person) = 6500 × 3
    = Rs. 19500
    Monthly income of dead person = 29400 – 19500
    = Rs.9900

     

  10. A committee of five persons is to be chosen from a group of 10 people. The probability that a certain married couple will either serve together or not at all is?
    44/127
    51/126
    61/125
    55/123
    51/121
    Option B
    Five persons is to be chosen from a group of 10 people
    = 10C5 = 252
    Couple Serve together = 8C3 * 2C2 = 56
    Couple does not serve = 8C5 = 56
    Probability = 102/252 = 51/126

     


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