Quant Test for IBPS RRB 2018 Prelim Exam Set – 24

Institute of Banking Personnel Selection (IBPS) had released the official notification for the Common Recruitment Process for RRBs (CRP RRBs VII) for the recruitment of Group “A”-Officers (Scale-I, II & III) and Group “B”-Office Assistant (Multipurpose)

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The examination will be held in two phases i.e. Preliminary Examination and Main Examination. The RRB Scale I Preliminary Exam is scheduled on 11th, 12th & 18th of August 2018. And RRB Assistant Preliminary Exam is scheduled on 19th, 25th August & 1st September 2018. Details of the exam are as under:

Practice the questions so as to familiarize yourself with the pattern of questions to be asked in the exam. 

Directions(1-5): Find the correct relation between x and y and choose a correct option.

1. I. 2x^2+x– 6 = 0
   II. 3y^2+y– 8 = 0
   x=y or relation cannot be established.
   x>y
   x>=y
   y>=x
   y>x
   Option A
   I. 2x^2+x– 6 = 0
   2x^2+4x–3x– 6 = 0
   x = -2,1.5
   II. 3y^2+y– 8 = 0
   3y^2+6y–4y– 8 = 0
   y = -2, 1.33
   Hence, no relation

    

2. I. x^3 – 375 = 3000
   II. y^3 + 600 = 769
   x=y or relation cannot be established.
   y>x
   y>=x
   x>=y
   x>y
   Option E
   x = 15
   y = 13
   x > y

    

3. I. 225x^2 – 4 = 0
   II. √225y + 2 = 0
   x=y or relation cannot be established.
   x>=y
   x>y
   y>=x
   y>x
   Option B
   225x^2 – 4 = 0
   (15x)^2 – (2)^2 = 0
   (15x + 2) (15x – 2) = 0
   x = – 2/15, 2/15
   15y + 2 = 0
   y = – 2/15
   x >= y

    

4. I. 2x^2 + x – 1 = 0
   II. 2y^2 – 3y + 1 = 0
   x>y
   x>=y
   x=y or relation cannot be established.
   y>x
   y>=x
   Option E
   2x^2 + x – 1 = 0
   2x^2 + 2x – x – 1 = 0
   2x (x + 1) – 1 (x + 1) = 0
   x = – 1, 1/2
   2y^2 – 3y + 1 = 0
   2y^2 – 2y – y + 1 = 0
   2y (y – 1) – 1 (y – 1) = 0
   y = 1, ½
   y>=x

    

5. I. x^2 + x – 2 = 0
   II. y^2 + 5y + 6 = 0
   x=y or relation cannot be established.
   y>=x
   y>x
   x>y
   x>=y
   Option E
   x ^2 + 2x – x – 2 = 0
   x (x + 2) – 1 (x + 2) = 0
   x = 1, – 2
   y^2 + 5y + 6 = 0
   y^2 + 3y + 2y + 6 = 0
   y (y + 3) + 2 (y + 3)
   y = – 2, – 3
   x>=y

    

6. 30 labourers working 7 hours a day can finish a piece of work in 18 days. If the labourers work 6 hours a day, then find the number of labourers required to finish the same piece of work in 30 days.
   30
   21
   18
   25
   17
   Option B
   Required number of labourers
   = (30*7*18)/(6*30) = 21

    

7. An amount of Rs. 400 becomes Rs. 424 in 3 years at a certain rate of simple interest, If the rate of interest increases by 8%, what amount will Rs. 400 becomes in 2 years?
   Rs. 480
   Rs. 320
   Rs. 420
   Rs. 580
   Rs. 400
   Option A
   SI = 424 – 400 = Rs. 24
   R = (24 × 100)/(400 × 3) = 2%
   New rate = 2 + 8 = 10%
   SI = (400 × 10 × 2)/100 = Rs. 80
   Amount = 400 + 80
   = Rs. 480

    

8. Average age of A and B, 2 years ago was 26. If age of A 5 years hence is 40 yrs, and B is 5 year younger to C, then find difference between age of A and C?
   8 years
   7 years
   5 years
   9 years
   6 years
   Option D
   Average age of A and B 2 year ago = 26
   Present Average age = A + B/ 2 = 28
   Present age A + B = 56
   A’s age after 5 year = 40
   Now A’s age = 40 – 5 = 35
   B’s age = 56 – 35 = 21
   C’s age = 21 + 5 = 26
   Required difference = 35 – 26 = 9 years

    

9. Ratio of speed of boat in down stream and speed of stream is 9:1, if speed of current is 3 km per hr, then find distance travelled(in km) upstream in 5 hours.
   111 km
   120 km
   113 km
   105 km
   90 km
   Option D
   speed of current = y = 3
   Downstream speed = 9 × 3 = 27 km/h
   Speed of boat = x
   x + y = 27
   x = 24
   y= 3
   Distance travelled = speed × Time
   = (x – y) × 5
   = (24 – 3) × 5
   = 21 × 5 = 105 km

    

10. How many different words can be formed with the letters of the word UNIVERSITY so that all the vowels are together?
    62400
    60480
    61460
    68440
    64480
    Option B
    Number of words = (4! * 7!)/2 = 60480