Institute of Banking Personnel Selection (IBPS) had released the official notification for the Common Recruitment Process for RRBs (CRP RRBs VII) for the recruitment of Group “A”-Officers (Scale-I, II & III) and Group “B”-Office Assistant (Multipurpose)
Click here to know the details of the Examination
The examination will be held in two phases i.e. Preliminary Examination and Main Examination. The RRB Scale I Preliminary Exam is scheduled on 11th, 12th & 18th of August 2018. And RRB Assistant Preliminary Exam is scheduled on 19th, 25th August & 1st September 2018. Details of the exam are as under:
Practice the questions so as to familiarize yourself with the pattern of questions to be asked in the exam.
Directions(1-5): Find the missing term of the series in the following questions.
- 8484, 4248, 2112, 1074, 513, ?
155.3286.5185.7106.2200.5Option B
(× 1/ 2 + 6) , (× 1/ 2 − 12) , (× 1 /2 + 18) , (× 1/ 2 − 24) , (× 1/ 2 + 30)
= 513 × 1 2 + 30 = 286.5 - 1108, 1117, 1142, 1191, ?, 1393
12001775107012721050Option D
(+3)^2 , (+5)^2 , (+7)^2 , (+9)^2 , (+11)^2
= 1191 + 9^2 = 1272 - 154, 162, 226, ?, 954, 1954
403450400442444Option D
(+2)^ 3 , (+4)^ 3 , (+6)^ 3 , (+8) 3 , (+10)^ 3
= 226 + (6)^ 3 = 442 - 96, 94, 373, 3353, ?, 1341069
5664452450536435060353005Option C
(× 1 − 2), (× 4 − 3), (× 9 − 4), (× 16 − 5), (× 25 − 6)
= 3353 × 16 − 5 = 53643 - 1, 16, 81, 256, ?, 1296
625405525605600Option A
1^ 4 , 2 ^4 , 3^ 4 , 4 ^4 , 5 ^4
= 5^ 4 = 625 - The population of City E in year 1990 was what fraction of its population in 2010?
5/710/2111/1513/1711/12Option B
Let the population of E in 1990 be 100.
E(2010) = 100* 150/100*140/100 = 210
Required fraction = 100/210 = 10/21 - If the population of City C in year 2010 and that of City D in year 2000 are equal and they are 27.2 lakh each the population of City C in year 1990 is what percentage of population of City D in the same year?
60%40%30%50%20%Option D
C(2010) = 27.2 = D(2000)
C(1990) = 27.2*100/170*100/160 = 10 lakh
D(1990) = 27.2*100/136 = 20 lakh
Required% = 10/20 × 100 = 50% - The population of City D in year 2000 was what per cent of its population in year 2010?
36.7%40.5%22.2%62.5%40.5%Option D
Suppose the population in year 2000 was x.
Its population in year 2010 x *160/100 = 8x/5
Required % = 5x/8x*100 = 62.5% - In year 1990 the population of City A and City B are equal and the population of City A in year 2010 is 37.7 lakh. What is the population of City B in year 2010
45 lakh30 lakh38 lakh40 lakh42 lakhOption E
A(2010) = 37.7 lakh
A(1990) = 37.7* 100/145* 100/130 = 20 lakh
B(1990) = A(1990) = 20 lakh
B(2010) = 20*140/100* 150/100 = 42 lakh - If the population of City F in year 1990 was 12 lakh, what will be its population in year 2010?
30.05 lakh32.23 lakh32.55 lakh30.50 lakh22.44 lakhOption C
P(1990) = 12 lakh
P (2010) = 12 * (100 + 75)/100* (100 + 55)/100
P(2010) = 12 × 1.75 × 1.55 = 32.55 lakh
Directions(6-10): The following graph shows the percentage growth in population of six
cities from 1990 to 2000 and 2000 to 2010.
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