**Institute of Banking Personnel Selection (IBPS)** had released the official notification for the Common Recruitment Process for RRBs (CRP RRBs VII) for the recruitment of Group “A”-Officers (Scale-I, II & III) and Group “B”-Office Assistant (Multipurpose)

Click here to know the details of the Examination

The examination will be held in two phases i.e. Preliminary Examination and Main Examination. The **RRB Scale I** Preliminary Exam is scheduled on 11th, 12th & 18th of August 2018. And **RRB Assistant** Preliminary Exam is scheduled on 19th, 25th August & 1st September 2018**. **Details of the exam are as under:

Practice the questions so as to familiarize yourself with the pattern of questions to be asked in the exam.

**Directions(1-5): **What will come in place of question mark “?” in the following questions.

- 339% of 803 + 77.8% of 1107 = ?
30023578345137743770Option B

339% of 803 + 77.8% of 1107 = ?

= (340×800)/100 + (78×1100)/100

= 2720 + 858 = 3578 - 333.33 + 33.33 + 13 + 0.33 + 0.03 = ?
330.4350.5300.3380.2385.3Option D

333.33 + 33.33 + 13 + 0.33 + 0.03 = ?

= 380.2 - 525 – (13)² + 63 = (?)² + 95
1712151814Option D

525 – (13)² + 63 = (?)² + 95

(?)^2+95 = 525–169+63

(?)^2 = 419 –95

= √324

= 18 - (62.5 × 12 × 3) ÷ 9 – 34 = (?)^3
811652Option C

(62.5 × 12 × 3) ÷ 9 – 34 = (?)^3

(?)^3 = 250–34

= (216)^1/3

= 6 - √4624 + √841 +1 = 14 × ?
10137515Option C

√4624 + √841 +1 = 14 ×?

68 + 29 + 1 = 14 ×?

= 7 - Four examiners examine a certain number of answer papers in 10 days by working for five hours a day. For how many hours in a day would two examiners have to work in order to examine twice the number of answers papers in 20 days?
20 hours10 hours30 hours50 hours40 hoursOption B

Let the required hours per day are t hours.

10×4×5/n = 20×2×t/2n

=> t = 20/2

=> t = 10 hours - A man can row 40 Km upstream and 55 Km downstream in 13 h. Also, he can row 30 km upstream and 44 Km downstream in 10 h. Find the speed of the man in still water.
8 km/h6 km/h5 km/h12 km/h10km/hOption A

40/x + 55/y = 13 …. (i)

30/x + 44/y = 10 …. (ii)

Solving the equations (i) and (ii), we get x = 5 and y = 11

speed of the man in still water

= 1/2 (x + y) = 1/2 (5 + 11)

= 16/2 = 8 km/h - Arun bought a computer with 15% discount on the labelled price. He sold the computer for Rs. 2880 with 20% profit on the labelled price. At what price did he buy the computer?
35402350204020003000Option C

120% of labelled price = 2880

85% of labelled price = (2880×85)/120

= 2040 - Find the amount of debt that will be discharged by 9 equal installments of Rs. 220 each, if the debt is due in 6 years at 3 % p.a.
Rs. 1515Rs. 1005Rs. 1111Rs. 1400Rs. 1419Option E

Amount of each installment

= 100 p/[ 100n+ n(n−1)r/2] => 220 = 100p/[100 × 6 + 6(6−1)3/2] => 220 = 100p/(600 + 45)

=>p = 220/100*645

= Rs. 1419 - A committee of five persons is to be chosen from a group of 10 people. The probability that a certain married couple will either serve together or not at all is?
55/12643/12651/12651/12051/121Option C

Five persons is to be chosen from a group of 10 people

= 10C5 = 252

Couple Serve together = 8C3 * 2C2 = 56

Couple does not serve = 8C5 = 56

Probability = 102/252

= 51/126