# Quant Test for IBPS RRB 2018 Prelim Exam Set – 9

Institute of Banking Personnel Selection (IBPS) had released the official notification for the Common Recruitment Process for RRBs (CRP RRBs VII) for the recruitment of Group “A”-Officers (Scale-I, II & III) and Group “B”-Office Assistant (Multipurpose)

The examination will be held in two phases i.e. Preliminary Examination and Main Examination. The RRB Scale I Preliminary Exam is scheduled on 11th, 12th & 18th of August 2018. And RRB Assistant Preliminary Exam is scheduled on 19th, 25th August & 1st September 2018Details of the exam are as under:

Practice the questions so as to familiarize yourself with the pattern of questions to be asked in the exam.

Directions(1-5): Find the relation between x and y and choose a correct option.

1. I. 15x² – 34x + 15 = 0
II. 15y² + 22y + 8 = 0

y>x
x>=y
x>y
y>=x
x=y or relation cannot be established.
Option C
I. 15x²- (9+25)x + 15 =0
15x² – 9x – 25x + 15 = 0
3x (5x-3)-5 (5x-3)=0
(3x-5) (5x-3)=0
II. 15y² +(10+12)y + 8 = 0
15y² + 10y + 12y + 8 = 0
5y (3y+2) +4 (3y+2)=0
(3y+2) (5y+4)=0
x > y

2. I. 4x^4 – 5x^2 + 1 = 0
II. 2y^2 + 11y + 14 = 0

y>x
x=y or relation cannot be established.
x>=y
x>y
y>=x
Option D
I.4x^4 – 5x^2 + 1 = 0
(x^2 – 1)(4^2 – 1) = 0
x = +1, -1, 1/2 or -1/2
II.2y^2 + 11y + 14 = 0
(y + 2)(2y + 7) = 0
y = -2, -7/2
x > y

3. I. x^2 – 7 √3 x + 36 = 0
II. y^2 – 11 √3 y + 84 = 0

x=y or relation cannot be established.
x>y
y>=x
y>x
x>=y
Option C
I. x^2 – 7 √3 x + 36 = 0
=> x^2 – 4 √3 x – 3 √3 x + 36 = 0
=> x (x – 4 √3) – 3√3 (x – 4√3) = 0
=> (x – 3√3) (x – 4√3) = 0
x = 3√3, 4√3
II. y^2 – 11√3 y + 84 = 0
=> y^2 – 4√3 y – 7√3 y + 84 = 0
=> y (y – 4√3)– 7√3 (y – 4√3) = 0
=> (y – 7 √3) (y – 4√3) = 0
y = 7 √3, 4√3
y>=x

4. I. x^2 = 361
II. y^3 = 7269 + 731

x=y or relation cannot be established.
y>x
y>=x
x>=y
x>y
Option B
I. x^2 = 361
x = ± 19
II. y^3 = 7269 + 731
y^3 = 8000
y = 20
x < y

5. I. x^2 – 6x + 135 = 0
II. y^2–30y+225 = 0

x>y
y>=x
y>x
x>=y
x=y or relation cannot be established.
Option B
I.x^ 2–6x + 135 = 0
x^2 – 15x + 9x + 135 = 0
x = +15, –9
II.y^2–30y+225 = 0
y^2–15y–15y+225 = 0
y = +15, +15
y>=x

6. Directions(6-10):
Study the following graph carefully and answer the questions given below.
Percentage growth in the population of six villages A, B, C, D, E and F from 2011 to 2012 and 2012 to 2013.

Actual Population of these villages in three different years:

7. Which of the following villages had maximum population in the year 2011?
B
A
D
C
E
Option C
Population in 20011 A = 3000 × 100/120 = 2500
B = 1980 × 100/110 = 1800
C = 2400 × 100/120 = 2000
D = 3000
E = 1250
F = 1200

8. What was the population of village ‘F’ in 2013?
2025
2525
2020
3025
2000
Option A
F’s population in 2012 = 1620
In 2013 = 1620 × 125/100 = 2025

9. Population of village ‘E’ in 2011 was approximately what per cent of its population in 2013?
63%
66%
70%
64%
60%
Option D
E’s population in 2011 = 1250
2012 = 1500
2013 = 1500 × 130/100 = 1950
Required % = 1250/1950*100 = 64.1% == 64%

10. If the populations of villages ‘C’ and ‘D’ in 2012 are in the ratio of 2 : 3 respectively, what was the population of village ‘D’ in 2011?
4000
5000
2000
3000
1000
Option D
C’s population in 2013 = 2760
C’s population in 2012 = 2760 × 100/115 = 2400
D’s population in 2012 = 2400 × 3/2 = 3600
D’s population in 2011 = 3600 × 100/120 = 3000

11. Which of the following villages had minimum population in the year 2012?(Refer previous question)
E
B
A
C
D
Option A
A’s population = 3750 × 100/125 = 3000
B’s population = 1980
C’s population = 2400
D’s population = 3600
E’s population = 1250 × 120/100 = 1500
F’s population = 1200 × 135/100 = 1620
In village E the population is minimum.

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