**Institute of Banking Personnel Selection (IBPS)** had released the official notification for the Common Recruitment Process for RRBs (CRP RRBs VII) for the recruitment of Group “A”-Officers (Scale-I, II & III) and Group “B”-Office Assistant (Multipurpose)

Click here to know the details of the Examination

The examination will be held in two phases i.e. Preliminary Examination and Main Examination. The **RRB Scale I** Preliminary Exam is scheduled on 11th, 12th & 18th of August 2018. And **RRB Assistant** Preliminary Exam is scheduled on 19th, 25th August & 1st September 2018**. **Details of the exam are as under:

Practice the questions so as to familiarize yourself with the pattern of questions to be asked in the exam.

**Directions(1-5):** Find the relation between x and y and choose a correct option.

- I. 15x² – 34x + 15 = 0

II. 15y² + 22y + 8 = 0y>xx>=yx>yy>=xx=y or relation cannot be established.Option C

I. 15x²- (9+25)x + 15 =0

15x² – 9x – 25x + 15 = 0

3x (5x-3)-5 (5x-3)=0

(3x-5) (5x-3)=0

II. 15y² +(10+12)y + 8 = 0

15y² + 10y + 12y + 8 = 0

5y (3y+2) +4 (3y+2)=0

(3y+2) (5y+4)=0

x > y - I. 4x^4 – 5x^2 + 1 = 0

II. 2y^2 + 11y + 14 = 0y>xx=y or relation cannot be established.x>=yx>yy>=xOption D

I.4x^4 – 5x^2 + 1 = 0

(x^2 – 1)(4^2 – 1) = 0

x = +1, -1, 1/2 or -1/2

II.2y^2 + 11y + 14 = 0

(y + 2)(2y + 7) = 0

y = -2, -7/2

x > y - I. x^2 – 7 √3 x + 36 = 0

II. y^2 – 11 √3 y + 84 = 0x=y or relation cannot be established.x>yy>=xy>xx>=yOption C

I. x^2 – 7 √3 x + 36 = 0

=> x^2 – 4 √3 x – 3 √3 x + 36 = 0

=> x (x – 4 √3) – 3√3 (x – 4√3) = 0

=> (x – 3√3) (x – 4√3) = 0

x = 3√3, 4√3

II. y^2 – 11√3 y + 84 = 0

=> y^2 – 4√3 y – 7√3 y + 84 = 0

=> y (y – 4√3)– 7√3 (y – 4√3) = 0

=> (y – 7 √3) (y – 4√3) = 0

y = 7 √3, 4√3

y>=x - I. x^2 = 361

II. y^3 = 7269 + 731x=y or relation cannot be established.y>xy>=xx>=yx>yOption B

I. x^2 = 361

x = ± 19

II. y^3 = 7269 + 731

y^3 = 8000

y = 20

x < y - I. x^2 – 6x + 135 = 0

II. y^2–30y+225 = 0x>yy>=xy>xx>=yx=y or relation cannot be established.Option B

I.x^ 2–6x + 135 = 0

x^2 – 15x + 9x + 135 = 0

x = +15, –9

II.y^2–30y+225 = 0

y^2–15y–15y+225 = 0

y = +15, +15

y>=x - Which of the following villages had maximum population in the year 2011?
BADCEOption C

Population in 20011 A = 3000 × 100/120 = 2500

B = 1980 × 100/110 = 1800

C = 2400 × 100/120 = 2000

D = 3000

E = 1250

F = 1200 - What was the population of village ‘F’ in 2013?
20252525202030252000Option A

F’s population in 2012 = 1620

In 2013 = 1620 × 125/100 = 2025 - Population of village ‘E’ in 2011 was approximately what per cent of its population in 2013?
63%66%70%64%60%Option D

E’s population in 2011 = 1250

2012 = 1500

2013 = 1500 × 130/100 = 1950

Required % = 1250/1950*100 = 64.1% == 64% - If the populations of villages ‘C’ and ‘D’ in 2012 are in the ratio of 2 : 3 respectively, what was the population of village ‘D’ in 2011?
40005000200030001000Option D

C’s population in 2013 = 2760

C’s population in 2012 = 2760 × 100/115 = 2400

D’s population in 2012 = 2400 × 3/2 = 3600

D’s population in 2011 = 3600 × 100/120 = 3000 - Which of the following villages had minimum population in the year 2012?(Refer previous question)
EBACDOption A

A’s population = 3750 × 100/125 = 3000

B’s population = 1980

C’s population = 2400

D’s population = 3600

E’s population = 1250 × 120/100 = 1500

F’s population = 1200 × 135/100 = 1620

In village E the population is minimum.

**
Directions(6-10):** Study the following graph carefully and answer the questions given below.

Percentage growth in the population of six villages A, B, C, D, E and F from 2011 to 2012 and 2012 to 2013.

Actual Population of these villages in three different years:

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