**Directions(1-5):** What approximate value will come in place of question mark ‘?’ in the following questions.

- 1025.08 + 1623.13 – 1784.91 + 2564.31 – 2897.98 = ?
529500487424490Option A

1025.08 + 1623.13 – 1784.91 + 2564.31 – 2897.98

= ?

=>1025 + 1623 – 1785 + 2564 – 2898 = ?

=>? = 5212 – 4683

=>? = 529 - ? = (40.16% of 24.95% of 1479.58) + 254.33
330339450402468Option D

? = (40.16% of 24.95% of 1479.58) + 254.33

=>? = (40% of 25% of 1480) + 254

=>? = 402 - 54.97% of 620.08 + 16.13*11.11 – 829.91/5 = ?
384366351390377Option C

54.97% of 620.08 + 16.13*11.11 – 829.91/5 = ?

=>55% of 620 + 16*11 – 830/5 = ?

=>341 + 176-166 = ?

=>? = 351 - 16% of 1750 – 20% of 1150 = 25% of ?
190200150148210Option B

16% of 1750 – 20% of 1150 = 25% of ?

=>0.25 * ? = 0.16*1750 – 020*1150

=>0.25*? = 280 – 320

=>0.25*? = 50

=>? = 200 - 244 – 156 + ?^2 – 13^2 = 15*14 + 25*22
1529201824Option B

244 – 156 + ?^2 – 13^2 = 15*14 + 25*22

=>88 + ?^2 – 169 = 210 + 550

=>?^2 – 81 = 760

=>?^2 = 841

=>? = 29 - The ratio of the first and second class train fares between two stations is 3:1 and that of the numbers of passengers travelling between the two stations by first and second classes is 1:50. If on a particular day Rs.1325 are collected from passengers between the two stations then the amount collected from second class passenger is ?
Rs.1550Rs.1412Rs.1350Rs.1221Rs.1250Option E

Fare = 3:1

Passenger = 3*1 : 1* 50

Add = 3 + 50 = 53

Now, 53x = 1325

=>x = 25

Amount collected from second class = 50x

25*50 = Rs.1250 - In an examination, the average marks obtained by the students was found to be 60. After omission of computational errors, the average marks of 100 candidates had to be changed from 60 to 30 and the average with respect to all the examinees came down to 45 marks. Find the number of candidates who took the exam.
156130180200174Option D

Let the number of candidates be x.

60x – 3000 = 45x

=>x = 200 - The compound interest on a certain sum of money at a certain rate per annum for 2 years is Rs.2050 and the simple interest on the same amount of money at the same rate for 3 years is Rs.3000. What is the sum of money?
Rs.12,000Rs.20,000Rs.18,000Rs.15,000Rs.22,000Option B

SI of 3 years = Rs.3000

SI for 2 years = Rs.3000/3*2 = Rs.2000

SI for 2 years = Rs.2000

CI for 2 years = Rs.2050

Difference = (2050 – 2000) = 50

Required rate% = 50/1000*100 = 5%

5% of sum = 1000

Sum = 1000/5*100 = Rs.20,000 - A man bought an article and sold it at a loss of 5%. If he had bought it for 10% less and sold it for Rs.33 more, he would have had a profit of 30%. Find the cost price of article.
130120140150160Option D

Let the CP be 100x.

SP = 95x

New CP = 90x

New SP = 90x*130/100 = 117x

Difference between new SP and actual SP.

117x- 95x = 33

=> x = 3/2

CP of the article = 100x = 100*3/2 = 150 - A and B start simultaneously from a place P towards Q , 60 km apart. A’s speed is 4 km/hr. less than that of B. After reaching Q, B turns back and meet A at a place 12 km away from Q. Find A’s speed.
4 km/hr.8 km/hr.7 km/hr.6 km/hr.9 km/hr.Option B

Let the speed of A be x km/hr.

Then, B’s speed = (x+4) km/hr.

Total distance covered by A = 60+12 = 72 km

Total distance covered by B = 60-12 = 48 km

Now, 72/(x+4) = 48/x

=>x = 8 km/hr.

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