Quant Test for LIC AAO Prelims Exam Set – 4

Directions(1-5): Solve each equations individually and compare the values of x and y and choose accordingly.

1. I.3x + 7y = 25
   II.7x + 6y = 48
   y>=x
   y>x
   x>=y
   x>y
   Relation cannot be established.
   Option D
   On solving both the equations, we get
   x = 6
   y = 1
   x>y

    

2. I.16x^2 – 88x + 117 = 0
   II.25y^2 – 125y + 156 = 0
   y>x
   x>y
   Relation cannot be established.
   y>=x
   x>=y
   Option C
   I.16x^2 – 88x + 117 = 0
   =>16x^2 – 36x – 52x + 117 = 0
   =>(4x – 9)((4x – 13) = 0 =>x = 13/4,9/4
   II.25y^2 – 125y + 156 = 0
   =>25y^2 – 65y – 60y + 156 = 0
   =>(5y – 12)(5y – 13) =0
   =>y = 12/5,13/5
   Relation cannot be established.

    

3. I.3x + 4y = 24
   II.2x + 3y = 17
   Relation cannot be established.
   y>=x
   x>=y
   y>x
   x>y
   Option E
   On solving both the equations, we get
   x =4
   y = 3
   x>y

    

4. I.2x^2 + 11x – 195 = 0
   II.3y^2 + 10y – 125 =0
   x>y
   x>=y
   Relation cannot be established.
   y>=x
   y>x
   Option C
   I.2x^2 + 11x – 195 = 0
   =>2x^2 + 26x – 15x – 195 = 0
   =>(x+13)(2x – 15) =0
   =>x = -13,15/2
   II.3y^2 + 10y – 125 =0
   =>3y^2 + 25y – 15y – 125 = 0
   =>(3y + 25)(y – 5) = 0
   =>y = -25/3,5
   Relation cannot be established.

    

5. I.x^2 + 17x + 52 = 0
   II.y^2 +27y +182 = 0
   y>=x
   Relation cannot be established.
   x>y
   y>x
   x>=y
   Option E
   I.x^2 + 17x + 52 = 0
   =>x^2 + 13x + 4x + 52 = 0
   =>(x+4)(x+13) = 0
   => x = -4, – 13
   II. y^2 +27y +182 = 0
   =>y^2 + 14y + 13y + 182 = 0
   =>(y+14)(y+13) = 0
   =>y = -14, – 13
   x>=y

    

Directions(6-10): Study the following graph and answer the questions.



6. What is the ratio of 2/5 of students enrolled college A and C together to 5/3 of students enrolled in college D and E together.
   41:224
   49:220
   51:222
   47:225
   43:221
   Option D
   Students enrolled in college A and C together = 350+ 400+300+ 450+400+450 = 2350
   Students enrolled in college D and E together = 500+400+350+400+600+450 = 2700
   Required ratio = 47:225

    

7. If 76/5% of students enrolled in college D leaved the college and number of students from all three disciplines (BA,BSC and BCOM) who leave college D are in the ratio 8:6:5, then the remaining student from BCOM in college D are what percent of students from BSC discipline from college E.
   80%
   70%
   40%
   60%
   50%
   Option E
   Student leaves college D = 76/5% of (500+400+350)
   = 190
   Remaining students in BCOM from D = 350 – 5/19*190 = 300
   Required% = 300/600*100 = 50%

    

8. Total students from BA discipline from all colleges together what percent more or less than the total students from BSC discipline from all colleges together?
   10% more
   9% less
   7% less
   5% less
   7% more
   Option C
   Total students in BA from all colleges together = 350+300+450+500+400 = 2000
   Total students enrolled in BSC from all colleges = 400+350+400+400+600 = 2150
   Required% = (2150-2000)/2150*100 = 7% less

    

9. If 140/9% of students enrolled for BA disciplines in college C are females then number of males in BA disciplines in college are what percent of females in college D for BA discipline if females in BA discipline of college D are 2000/7% more than females in BA discipline of college C.
   150%
   140%
   120%
   100%
   90%
   Option B
   Number of female students in BA discipline from college C = 140*150/9*100 = 70
   Number of male in BA from college C = 450 – 70 = 380
   Female in BA from college D = (1+20/7)*70 = 270
   Required% = 380/270*100 = 140%

    

10. Number of students enrolled in BSC from C and E together are what percent of the total number of students BCOM from all colleges together?
    44%
    37%
    40%
    49%
    38%
    Option D
    Number of students enrolled in BSC from college C and E together = 400+600 = 1000
    Total number of students enrolled in BCOM from all college together = 2050
    Required% = 1000/2050*100 = 49%