Quant Test for NIACL 2018 Prelim Exam Set – 2

Banya

Directions(1-5): Find the relation between x and y and choose a correct option.

  1. I. x² = –14x
    II. y² + 18y + 80 = 0

    x=y or relation cannot be established.
    y>=x
    x>y
    x>=y
    y>x
    Option A
    x = 0, – 14
    y = – 8, – 10
    No relation

     

  2. I. x = √5329
    II. y = (12167)^1/3

    y>x
    x>=y
    y>=x
    x>y
    x=y or relation cannot be established.
    Option D
    x = 73
    y = 23
    x > y

     

  3. I. 15x² – 41x + 28 = 0
    II. 7y² – 29y + 30 = 0

    x=y or relation cannot be established.
    y>=x
    y>x
    x>=y
    x>y
    Option C
    x = 7/5 , 4/3
    y = 2, 15/7
    x < y

     

  4. I. 4x² – x – 3 = 0
    II. y² + 4y + 4 = 0

    y>=x
    x>y
    x>=y
    y>x
    x=y or relation cannot be established.
    Option B
    x = – 3/4 , 1
    y = – 2
    x > y

     

  5. I. 3x² – 59x + 210 = 0
    II. 2y² – 17y + 36 = 0

    x>y
    x>=y
    y>x
    y>=x
    x=y or relation cannot be established.
    Option A
    x = 14/3 , 15
    y = 4, 9/2
    x > y

     

  6. Ratio between speed of a Jeep and a Car is 17 : 18 and also a train covered 1080 km in 43200 seconds. If speed of Car is 3/5 th of speed of train then find distance covered by Jeep in 36000 seconds? (in km)
    420 km
    510 km
    330 km
    450 km
    500 km
    Option B
    Speed of train = (1080/43200)*60 * 60 = 90 km/hr
    Speed of Car = 90 × 5/3 = 54 km/hr
    Speed of Jeep = 54 × 17/18 = 51 km/hr
    Required distance = 51 × 36000/(60 × 60)
    = 510 km

     

  7. 30 men are supposed to do a work in 38 days. After 25 days, 5 more men were employed on work because of which the work was completed 1 day before usual time. If 5 more man were not employed, then for how many days would the work be delayed?
    5 day
    6 day
    1 day
    2 day
    4 day
    Option C
    Total work = 30 × 25 + (30 + 5)*(37 – 25)
    = 30 × 25 + 35 × 12
    = 750 + 420 = 1170
    Time required by 30 men to complete work = 1170/30
    = 39 days
    Work will be delayed by = (39 – 38) = 1 day

     

  8. A took a loan at simple interest rate of 5% in the year with an increase of 0.75% in each subsequent year. He paid interest of Rs.3864 after 3 year. How much loan did he take?
    Rs. 25600
    Rs. 23500
    Rs. 21000
    Rs. 22400
    Rs. 24400
    Option D
    Total interest = Rs.3864 Rate = 5% and increasing by 0.75% every year
    Let total Loan Amount = P
    P = (3864 × 100)/( 5 × 1 + 5.75 × 1 + 6.5 × 1)
    = 386400/17.25
    = Rs. 22400

     

  9. The perimeter of a square is equal to the perimeter of a rectangle, whose length is 24 cm and breath is 66(2/3)% of its length. Find the circumference of a semicircle whose diameter is equal to the side of square ?
    360/7 cm
    282/5 cm
    351/6 cm
    295/8 cm
    366/5 cm
    Option A
    Perimeter of square = Perimeter of rectangle
    = 2*(24 + 24*2/3) = 80 cm
    4 * side = 80 side = 20 cm
    Radius of semi-circle = 20/2 = 10 cm
    circumference of semi-circle = pi*r + 2r
    = 22/7*10 + 20
    = 360/7 cm

     

  10. There are 55 tickets in a box numbered 1 to 55. What is the probability of choosing a ticket which has a prime number on it?
    13/55
    10/51
    16/55
    11/53
    15/51
    Option C
    Prime numbers up to 55 is 16 numbers which are 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 43, 41, 47, 53.
    So, probability = 16/55

     


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