**Directions(1-5): **Find the relation between x and y and choose a correct option.

- I. x² = –14x

II. y² + 18y + 80 = 0x=y or relation cannot be established.y>=xx>yx>=yy>xOption A

x = 0, – 14

y = – 8, – 10

No relation - I. x = √5329

II. y = (12167)^1/3y>xx>=yy>=xx>yx=y or relation cannot be established.Option D

x = 73

y = 23

x > y - I. 15x² – 41x + 28 = 0

II. 7y² – 29y + 30 = 0x=y or relation cannot be established.y>=xy>xx>=yx>yOption C

x = 7/5 , 4/3

y = 2, 15/7

x < y - I. 4x² – x – 3 = 0

II. y² + 4y + 4 = 0y>=xx>yx>=yy>xx=y or relation cannot be established.Option B

x = – 3/4 , 1

y = – 2

x > y - I. 3x² – 59x + 210 = 0

II. 2y² – 17y + 36 = 0x>yx>=yy>xy>=xx=y or relation cannot be established.Option A

x = 14/3 , 15

y = 4, 9/2

x > y - Ratio between speed of a Jeep and a Car is 17 : 18 and also a train covered 1080 km in 43200 seconds. If speed of Car is 3/5 th of speed of train then find distance covered by Jeep in 36000 seconds? (in km)
420 km510 km330 km450 km500 kmOption B

Speed of train = (1080/43200)*60 * 60 = 90 km/hr

Speed of Car = 90 × 5/3 = 54 km/hr

Speed of Jeep = 54 × 17/18 = 51 km/hr

Required distance = 51 × 36000/(60 × 60)

= 510 km - 30 men are supposed to do a work in 38 days. After 25 days, 5 more men were employed on work because of which the work was completed 1 day before usual time. If 5 more man were not employed, then for how many days would the work be delayed?
5 day6 day1 day2 day4 dayOption C

Total work = 30 × 25 + (30 + 5)*(37 – 25)

= 30 × 25 + 35 × 12

= 750 + 420 = 1170

Time required by 30 men to complete work = 1170/30

= 39 days

Work will be delayed by = (39 – 38) = 1 day - A took a loan at simple interest rate of 5% in the year with an increase of 0.75% in each subsequent year. He paid interest of Rs.3864 after 3 year. How much loan did he take?
Rs. 25600Rs. 23500Rs. 21000Rs. 22400Rs. 24400Option D

Total interest = Rs.3864 Rate = 5% and increasing by 0.75% every year

Let total Loan Amount = P

P = (3864 × 100)/( 5 × 1 + 5.75 × 1 + 6.5 × 1)

= 386400/17.25

= Rs. 22400 - The perimeter of a square is equal to the perimeter of a rectangle, whose length is 24 cm and breath is 66(2/3)% of its length. Find the circumference of a semicircle whose diameter is equal to the side of square ?
360/7 cm282/5 cm351/6 cm295/8 cm366/5 cmOption A

Perimeter of square = Perimeter of rectangle

= 2*(24 + 24*2/3) = 80 cm

4 * side = 80 side = 20 cm

Radius of semi-circle = 20/2 = 10 cm

circumference of semi-circle = pi*r + 2r

= 22/7*10 + 20

= 360/7 cm - There are 55 tickets in a box numbered 1 to 55. What is the probability of choosing a ticket which has a prime number on it?
13/5510/5116/5511/5315/51Option C

Prime numbers up to 55 is 16 numbers which are 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 43, 41, 47, 53.

So, probability = 16/55