**Directions(1-5):** What will come in place of question mark in the following questions.

- 2418.065 + 88 ÷ 14.2 × 6 = ?
28752000245622522404Option C

2418 + 88 ÷ 14 × 6 = ?

=> ? = 2418 + 6.3 × 6

=> ? = 2418 + 38

=> ? = 2456 - (19.97% of 781) + ? + (30% of 87) = 252
4070608050Option B

(19.97% of 781) + ? + (30% of 87) = 252

=> (20% of 780) + ? + (30 % of 87) = 252

=> 156 + ? + 26 = 252

=> 182 + ? = 252

=> ? = 252 – 182

=> ? = 70 - ? × 1.3 × 6.5 = 1.17 × 24.7
3.052.153.424.442.40Option C

? × 1.3 × 6.5 = 1.17 × 24.7

=> ? = (117×247)/(13×65×10) = 3.42 - 55% of 320 + 30% of 1080 = 20 × ?
1018252230Option C

55/100 × 320 + 30/100 × 1080 = 20 ×?

=> 176 + 324 = 20 × ?

=> ? = 500/20 = 25 - 72% of 420 – 22% of 270 = ?
278243255205222Option B

72% of 420 – 22% of 270 = ?

=>302.4 – 59.4 = ?

=>? = 243 - Annual salary of Arun is 7.68 lac. In a month if he spends 12000 on his children, 1/13th of rest on food and 8000 in mutual funds from his monthly salary, then find the monthly saving he is left with.
55,00048,00040,00035,00052,000Option C

Monthly salary = 7.68/12 Lacs = 64000

Saving = Income – Expenditure

= 64000 – 12000 – 4000 – 8000

= 40,000 - Two different amounts are invested in two schemes. In scheme A, amount X is invested at 8 % per annum and in scheme B amount (X+1400) is invested at 12% per annum.After 2 years difference between both interests is 880, then find value of X?
74006800540078006600Option B

In scheme A Interest = (X×8×2)/100

In scheme B Interest =[(X + 1400)×12×2]/100

ATQ, [ (X + 1400)×12×2]/100 – [X×8×2]/ 100 = 880

=>X = 6800 - Ratio of speed of boat in down stream and speed of stream is 9:1, if speed of current is 3 km per hr, then find distance travelled(in km) upstream in 5 hours.
75 km82 km98 km105 km110 kmOption D

speed of current = y = 3

Down stream speed = 9 × 3 = 27 km/h

Speed of boat = x => x + y = 27

x = 24

y= 3

Distance travelled upstream in 5 hr = speed × Time

= (x – y) ×5 = (24 – 3) × 5

= 21 × 5 = 105 km - Harshan took a loan at a rate of simple interest 7% in the year with an increase of 0.25% in each subsequent year. He paid interest of Rs. 4425 after 4 years. How much loan did he take?
Rs. 20000Rs. 15000Rs. 25000Rs. 12500Rs. 10000Option B

Total interest = Rs. 4425

Rate = 7% and increasing by 0.25% every year

Let total Loan Amount = P

P = (4425 × 100)/( 7 × 1 + 7.25 × 1 + 7.5 × 1 + 7.75 × 1)

= 442500/29.5

= Rs. 15000 - Chance that Sheela tells truth is 35% and for Ramesh is 75%. In what percent they likely to contradict each other in the same question?
21/3427/3123/4222/4323/40Option E

P(A) = 35/100 = 7/20 and P(B) = 75/100=3/4.

Now, they are contradicting means one lies and other speaks truth.

So, Probability = 7/20*1/4 + 13/20 * 3/4

= 7/80 + 39/80

= 46/80

= 23/40