Quant Test for NIACL 2018 Prelim Exam Set – 4

Directions(1-5): What will come in place of question mark in the following questions.

  1. 2418.065 + 88 ÷ 14.2 × 6 = ?
    2875
    2000
    2456
    2252
    2404
    Option C
    2418 + 88 ÷ 14 × 6 = ?
    => ? = 2418 + 6.3 × 6
    => ? = 2418 + 38
    => ? = 2456

     

  2. (19.97% of 781) + ? + (30% of 87) = 252
    40
    70
    60
    80
    50
    Option B
    (19.97% of 781) + ? + (30% of 87) = 252
    => (20% of 780) + ? + (30 % of 87) = 252
    => 156 + ? + 26 = 252
    => 182 + ? = 252
    => ? = 252 – 182
    => ? = 70

     

  3. ? × 1.3 × 6.5 = 1.17 × 24.7
    3.05
    2.15
    3.42
    4.44
    2.40
    Option C
    ? × 1.3 × 6.5 = 1.17 × 24.7
    => ? = (117×247)/(13×65×10) = 3.42

     

  4. 55% of 320 + 30% of 1080 = 20 × ?
    10
    18
    25
    22
    30
    Option C
    55/100 × 320 + 30/100 × 1080 = 20 ×?
    => 176 + 324 = 20 × ?
    => ? = 500/20 = 25

     

  5. 72% of 420 – 22% of 270 = ?
    278
    243
    255
    205
    222
    Option B
    72% of 420 – 22% of 270 = ?
    =>302.4 – 59.4 = ?
    =>? = 243

     

  6. Annual salary of Arun is 7.68 lac. In a month if he spends 12000 on his children, 1/13th of rest on food and 8000 in mutual funds from his monthly salary, then find the monthly saving he is left with.
    55,000
    48,000
    40,000
    35,000
    52,000
    Option C
    Monthly salary = 7.68/12 Lacs = 64000
    Saving = Income – Expenditure
    = 64000 – 12000 – 4000 – 8000
    = 40,000

     

  7. Two different amounts are invested in two schemes. In scheme A, amount X is invested at 8 % per annum and in scheme B amount (X+1400) is invested at 12% per annum.After 2 years difference between both interests is 880, then find value of X?
    7400
    6800
    5400
    7800
    6600
    Option B
    In scheme A Interest = (X×8×2)/100
    In scheme B Interest =[(X + 1400)×12×2]/100
    ATQ, [ (X + 1400)×12×2]/100 – [X×8×2]/ 100 = 880
    =>X = 6800

     

  8. Ratio of speed of boat in down stream and speed of stream is 9:1, if speed of current is 3 km per hr, then find distance travelled(in km) upstream in 5 hours.
    75 km
    82 km
    98 km
    105 km
    110 km
    Option D
    speed of current = y = 3
    Down stream speed = 9 × 3 = 27 km/h
    Speed of boat = x => x + y = 27
    x = 24
    y= 3
    Distance travelled upstream in 5 hr = speed × Time
    = (x – y) ×5 = (24 – 3) × 5
    = 21 × 5 = 105 km

     

  9. Harshan took a loan at a rate of simple interest 7% in the year with an increase of 0.25% in each subsequent year. He paid interest of Rs. 4425 after 4 years. How much loan did he take?
    Rs. 20000
    Rs. 15000
    Rs. 25000
    Rs. 12500
    Rs. 10000
    Option B
    Total interest = Rs. 4425
    Rate = 7% and increasing by 0.25% every year
    Let total Loan Amount = P
    P = (4425 × 100)/( 7 × 1 + 7.25 × 1 + 7.5 × 1 + 7.75 × 1)
    = 442500/29.5
    = Rs. 15000

     

  10. Chance that Sheela tells truth is 35% and for Ramesh is 75%. In what percent they likely to contradict each other in the same question?
    21/34
    27/31
    23/42
    22/43
    23/40
    Option E
    P(A) = 35/100 = 7/20 and P(B) = 75/100=3/4.
    Now, they are contradicting means one lies and other speaks truth.
    So, Probability = 7/20*1/4 + 13/20 * 3/4
    = 7/80 + 39/80
    = 46/80
    = 23/40

     


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