Quant Test for NIACL AO Prelims Exam Set – 12

Directions(1-5): Find the missing term ‘?’ of the following series.

  1. 8,13,26,51,92,?
    133
    153
    140
    132
    150
    Option B
    +(1^2+2^2)
    +(2^2+3^2)
    +(3^2+4^2)
    +(4^2+5^2)
    +(5^2+6^2)
    ? = 153

     

  2. 630,210,84,42,?,28,56
    15
    20
    28
    16
    13
    Option C
    /3
    /2.5
    /2
    /1.5
    /1
    /0.5
    ? = 28

     

  3. 463,453,433,403,?,313
    333
    363
    350
    344
    362
    Option B
    -10.-20,-30,-40,-50
    ? = 363

     

  4. 24,16,28,74,?,1187.5
    222
    255
    241
    263
    272
    Option D
    *0.5+4
    *1.5+4
    *2.5+4
    *3.5+4
    *4.5+4
    ? = 263

     

  5. 23,40,61,86,?,148
    95
    100
    88
    115
    90
    Option D
    +17,+21,+25,+29,+33
    ? = 115

     

  6. At what rate of simple interest must Rs.15900 be deposited for 4 years to receive the same interest that is obtained by investing Rs.15000 at 12% per annum compound interest compounded for 2 years ?
    8
    6
    7
    5
    4
    Option B
    Compound interest earned = 15000*{(1+0.12)^2 – 1} = Rs.3816
    Let rate be r%.
    Simple interest earned = 15900*4*r/100 = 3816
    => r = 6

     

  7. If the numerator of a fraction is increased by 40% and denominator in increased by 25% then the resultant fraction will become 7/5. What is the original fraction?
    3/5
    11/9
    7/2
    4/3
    5/4
    Option E
    Let the original fraction be x/y. (x*1.4)/(y*1.25) = 7/5
    => x/y = 5/4

     

  8. Find the area of the circular field having radius equal to the breadth of a room with area of four walls 840 m^2 and height 10 m if it is given that ratio of length and breadth of the room is 4:3 resp.(Take pi = 3)
    900 m^2
    818 m^2
    919 m^2
    972 m^2
    700 m^2
    Option D
    2(l+b)*h = 840
    => 2(4x+3x)*10 = 840
    => x = 6
    Breadth = 3*6 = 18 m
    Area of the circular field = pi*(18)^2 = 972 m^2

     

  9. Present ages of A and B are in the ratio of 2:3 resp. Present ages of C and D are in the ratio of 8:7 resp. Present average age of A ,B and C is 46 years. Present average age of B,C and D is 48 years. Find the difference between the present ages of B and C.
    4 years
    2 years
    5 years
    8 years
    6 years
    Option E
    Let the present ages of A,B,C and D are 2x,3x,8y and 7y resp.
    Now, 2x+3x+8y = 3*46 5x+8y = 138 —-(1)
    Also, 3x+8y+7y = 3*48 —–(2)
    On solving (1) and (2), we get
    x = 18
    y = 6
    Difference between present ages of B and C = 54 – 48 = 6 years

     

  10. A cricket team of 11 players is to be selected from a group of 8 batsmen, 5 bowlers and 3 wicketkeepers. In how many ways a team a having at least 4 bowlers and exactly 1 wicketkeeper is selected?
    500
    555
    588
    610
    585
    Option C
    Required number of ways = 3C1*5C4*8C6 + 3C1*5C5*8C5
    = 420+168 = 588

     


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