# Quant Test for NIACL AO Prelims Exam Set – 5

Directions(1-5): The pie-chart shows the population distribution of a village among various categories.
The total population of the village = 4350 1. Find the ratio of difference of people from General category and OBC category to the sum of people from SC and ST category taken together.
7:12
17:20
13:17
15:11
11:9
Option D
Difference of people from General category and OBC category
= 2349 – 1044 = 1305
Sum of people from SC and ST category taken together = 609 + 348 = 957
Required ratio = 1305:957 = 15:11

2. The ratio of male and female in SC and ST categories is 4:3 and 1:3 resp. Find the total number of females from both categories taken together.
489
522
440
500
495
Option B
Number of people from SC and ST category = 609 and 348
Number of females from SC category and ST category = 3/(3+4)*609 = 261 and 3/(1+3)*348 = 261
Total females from SC and ST category = 261+261 = 522

3. The difference between the people from OBC category and people from ST category is what percentage more or less than the people from SC category?
14.28%
13.30%
11.78%
12.34%
10.55%
Option A
Number of people from OBC category = 0.24*4350 = 1044
Number of people from SC category = 0.14*4350 = 609
Number of people from ST category = 0.08*4350 = 348
Required% = (1044 – 348)-609/609*100 = 14.28%

4. Find the difference between average of people from General and SC categories taken together and average of people from ST category and OBC category people taken together.
782
770
783
700
715
Option C
Average of people from General category and SC category taken together
= (2349+609)/2 = 1479
Average of people from OBC category and ST category taken together = (1044+348)/2 = 696
Required difference = 1479 – 696 = 783

5. In an election, two candidates were there. 100/9% of people from General category and 100/3% of people from OBC category didn’t cast their votes and rest all categories cast 100% votes. Winning candidate won by 967 votes. Find the number of votes secured by runner – up candidate.
1440
1250
1300
1550
1387
Option E
Votes cast by people from General category = (100-100/9)% of 54% of 4350
= 2088
Votes cast by people from OBC category = (100-100/3)% of 24% of 4350 = 696
Votes cast by people from SC category = 0.14*4350 = 609
Votes cast by people from ST category = 0.08*4350 = 348
Let the number of votes won by runner-up candidate be x.
x+x+967 = 3741
=> x = 1387

6. Directions(6-10): What will be the approximate value in place of question mark “?” in the following questions.

7. (1935.98)^1/2 * 25 + 1/23.99*5.99 * 37.5% of 1023.99 = ? * 35.98% of 11.11
222
250
200
299
280
Option D
(1935.98)^1/2 * 25 + 1/23.99*5.99 * 37.5% of 1023.99 = ? * 35.98% of 11.11
=> ? * 11.11% * 36 = (1935.98)^1/2 * 25 + 1/24 * 6*3/8 * 1024
=> ? * 4 = 44*25 + 96
=> ? * 4 = 1100 + 24
=> ? = 299

8. 74.98% of 639.74 + 35.97% + 749.99 = ?^2 * 29.99
6
4
3
5
2
Option D
74.98% of 639.74 + 35.97% + 749.99 = ?^2 * 29.99
=> ?^2 * 30 = 75% * 640 + 36% of 750
=> ?^2 * 30 = 750
=> ? = 5

9. 85% of 4540 + 36^2 = ?^2 – 11877 / 37
74
70
66
60
71
Option A
85% of 4540 + 36^2 = ?^2 – 11877 / 37
=> ?^2 – 321 = 0.85* 4540 +1296
=> ?^2 = 3859 + 1296 + 321
=> ? = 74

10. ((3136)^1/2 + 2048 / 32)% of 10.8% of 10000 = ?% of 2400
42
50
38
40
54
Option E
((3136)^1/2 + 2048 / 32)% of 10.8% of 10000 = ?% of 2400
=> ?% of 2400 = (56+64)% of 1080
=> ? = 1296/24
=> ? = 54

11. 511.98/7.99^2 * 14.97 = ?^2 – 50.99% of 399.89
11
16
18
10
14
Option C
511.98/7.99^2 * 14.97 = ?^2 – 50.99% of 399.89
=> ?^2 – 51% * 400 = 512 / 8^2 *15
=> ?^2 = 120 + 204
=> ? = 18