Quant Test for NIACL AO Prelims Exam Set – 6


Directions(1-5):
Find the missing number “?” of the following series.

  1. 7,13,25,?,67,97
    20
    40
    22
    43
    25
    Option D
    +6,+12,+18,+24,+30
    ? = 43

     

  2. 48,54,43,60,36,?
    52
    68
    55
    60
    44
    Option B
    +6,-11,+17,-24,+32
    ? = 68

     

  3. 6,7,9,13,21,?
    37
    25
    30
    21
    27
    Option A
    +2*0.5
    +2*1
    +2*2
    +2*4
    +2*8
    ? = 37

     

  4. 29,41,55,?,89,109
    66
    68
    71
    73
    77
    Option C
    5^2+4
    6^2+5
    7^2+6
    8^2+7
    9^2+8
    10^2+9
    ? = 71

     

  5. 1,0,5,24,65,?
    139
    125
    130
    142
    136
    Option E
    1+1^2 -2
    0+3^2 -4
    5+5^2 -6
    24+7^2 -8
    65+9^2 -10
    ? = 136

     

  6. In an examination, Ram got 41% marks and thus able to score 70 marks above passing marks. In the same examination Ganesh got 69% marks and thus was able to score 462 marks above passing marks. Find the passing percentage of the examination.
    33%
    28%
    25%
    36%
    30%
    Option D
    Let the maximum marks of the examination be x. 0.14x – 70 = 0.69x – 462
    => x = 1400
    Passing marks = 0.41*1400 – 70 = 504
    Passing% = 504/1400*100 = 36%

     

  7. Average age of a class having ‘6x-1’ students is 3x years. Average age of the class is increased by two years, if the age of the principal is also included. Find the total number of students in the class if the age of the principal is 90 years .
    30
    25
    26
    35
    28
    Option D
    Sum of the ages of all the students = (6x-1)*3x = (18x^2 – 3x) years
    Sum of the ages of students along with principal = (6x – 1 + 1)*(3x+2) = 18x^2 + 12x
    18x^2 – 3x + 90 = 18x^2 + 12x
    => x = 6
    So, the total number of the students in the class = 6*6 – 1 = 35

     

  8. A shopkeeper marked an article at 80% above the cost price and sold it after two consecutive discounts of 25% and 20%. Had he marked it at 60% above the cost price and sold it after a discount of 30%, he would have gained Rs. 540 more. Find the cost price of the article.
    11000
    12000
    13500
    14200
    10000
    Option C
    Let the CP be x.
    Original marked price of the article = Rs.1.8x
    Original SP of the article = 1.8x *0.75 *0.80 = Rs.1.08x
    New MP of the article = 1.60x
    New SP of the article = 1.60x*0.70 = Rs.1.12x
    Now, 1.12x – 1.08x = 540 => x = 13500

     

  9. A,B and C together started a business with initial investments in the ratio 7:5:8 resp. After one year, A,B and C made additional investments in the ratio 1:2:5 resp. Find the average profit share of A and C out of the total profit of Rs.4800 after two years.
    Rs.1600
    Rs.1500
    Rs.1200
    Rs.1800
    Rs.1000
    Option D
    Ratio of their profits = (7x+7x+y) : (5x+5x+2y) : (8x+8x+5y)
    = 14x+y : 10x+2y : 16x+5y
    Profit share of A and C together = (30x+6y)/(40x+8y)*4800 = Rs.3600
    Average profit share of A and C together = 3600/2 = Rs.1800

     

  10. A football team of 11 players is to be selected from a group of 3 goalkeepers, 8 defenders and 7 attackers. In how many ways a team having exactly one goalkeeper, atleast 4 defenders and atleast 4 attackers can be selected?
    7550
    7250
    7850
    7938
    7700
    Option D
    Required number of ways = 3C1*8C4*7C6 + 3C1*8C5*7C5 + 3C1*8C6*7C4
    = 1470 + 3528 + 2940 = 7938

     


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