**Directions(1-5):** What will be the approximate value come in place of question mark “?” in the following question.

- 29.98% of 1780.21 + ? + 19.72% of 699.23 = 64.83% of 2359.69
785800755820860Option E

29.98% of 1780.21 + ? + 19.72% of 699.23 = 64.83% of 2359.69

=> 30% of 1780 + ? + 20% of 700 = 65% of 2360

=> 534 + ? + 140 = 1534

=>? = 860 - (20.99)^2 â€“ (13.01)^2 + (291.12 + 76.92)/? = 55.92% of 499.88
4035463930Option C

(20.99)^2 â€“ (13.01)^2 + (291.12 + 76.92)/? = 55.92% of 499.88

=> 21^2 â€“ 13^2 + (291+77)/? = 56% of 500

=> 441 â€“ 169 + 368/? = 280

=> ? = 46 - (2210)^1/2 + 979.90 / 13.927 = ?^2 â€“ 5.099% of 1579.99
1412101516Option A

(2210)^1/2 + 979.90 / 13.927 = ?^2 â€“ 5.099% of 1579.99

=> (2210)^1/2 + 979/14 = ?^2 â€“ 5% of 1580

=> 47 + 70 = ?^2 â€“ 79

=> ? = 14 - 11.92% of 1199.98 – ?* 13.9*20.99 / (196)^1/2 = 43.21 â€“ 297.78
2219201416Option B

11.92% of 1199.98 – ?* 13.9*20.99 / (196)^1/2 = 43.21 â€“ 297.78

=> 12% of 1200 – ?*14*221/(196)^1/2 = 43 â€“ 298

=> 144 – ?*14*21/(196)^1/2 = – 255

=> 21 * ? = 399

=> ? = 19 - (2.197)^4 / (1.69)^2 *(1.3)^2 = (1.3)^(? – 2)
11871012Option E

(2.197)^4 / (1.69)^2 *(1.3)^2 = (1.3)^(? – 2)

=> (1.3)^12/(1.3)^4 *(1.3)^2 = (1.3)^(?-2)

=> (1.3)^10 = (1.3)^(?-2)

=> ? = 12 - Marks obtained by D in all the six subjects together are approximately how much percent more than the marks scored by A in all the six subjects together?
7%3%4%6%5%Option D

Marks obtained by A in all subjects = 485

Marks obtained by D in all subjects = 513

Difference = 513 â€“ 485 = 28

Required% = 28/485*100 = 5.77% == 6% - Marks obtained by B,C and D in Science together are approximately how much percent less than marks obtained by A,B and E in G.K. together.
22.11%31.52%18.41%32.23%30.04%Option B

Marks obtained by B,C and D in Science together = 120+105+90 = 315

Marks obtained by A,B and D in G.K. together = 180+120+160 = 460

Required% = (460-315)/460*100 = 31.52% - Ram scored 20% more marks than A in all the subjects together and Shyam scored 25% less than C in all the subjects together. Find the difference between the total marks of Ram and Shyam.
185200220231193Option D

Marks obtained by A = 485

Marks obtained by Ram = 1.2*485 = 582

Marks obtained by C = 468

Marks obtained by Shyam = 0.75*468 = 351

Difference = 582 â€“ 351 = 231 - How many number of students scored more than 65% of maximum marks.
63452Option C

Maximum marks = 100+80+150+120+75+200 = 725

65% of maximum marks = 0.65*725 = 471.75

Marks obtained by A = 485

Marks obtained by B = 480

Marks obtained by C = 468

Marks obtained by D = 513

Marks obtained by E = 545

Only 4 students = A,B,D and E. - Average percentage of marks per student scored by the five students in which subject are the highest?
ScienceEnglishHindiG.K.MathsOption E

Average percentage per student for Maths

= (70+72+73+89+91)/5*100*100 = 79%

**Directions(6-10):** The table shows the marks scored by five students in five different subjects.