- A can do a work in 36 days and B is 25% more efficient than A. In how many days A and B together can complete the total work ?
14 days28 days15 days16 days20 daysOption D

Let efficiency of A = 4x

efficiency of B = 4x * 125/100 = 5x

Total work = 36 * 4x

Time taken by A and B to complete total work = 36 * 4x / 9x = 16 days - Two mixture of water and milk contain 36% and 40% milk respectively. Find in what respective ratio should these mixtures be mixed so that the final mixture contains 72% water.
3 : 45 : 33 : 22 : 55 : 7Option C

percentage of milk in final mixture = 100 – 72 = 28%

36% 40%

28%

12% 8%

3 2

ratio = 3 : 2 - Mohit and Rohit started a business with the capital investing rs.12000 and rs.x respectively. Mohit invested his capital for 6 months and Rohit invested his capital for 12 months. After one year total profit earned by them is rs.14000 by them and out of these profit share of Mohit is 6000, then find the value of ‘x’.
40008000380075008400Option B

Profit share of Mohit = 6000

Profit share of Rohit = 14000 – 6000 = 8000

ATQ, 12000 * 6/ x * 12 = 6000/8000

12000 * 6/ x * 12 = 3/4

x = 8000 - A train can cross a pole in 20 second and it can cross a 360m long platform in 50 seconds, then find the length of the train.
240280140320120Option A

Let, the length of the train be x.

x/20 = x + 360/50

5x = 2x + 720

3x = 720

x = 240 - The ratio of the length and breadth of a rectangular is 9 : 4 and perimeter of the rectangular is 78m. If the area of square is equal to the area of that rectangular, then what is the perimeter of the square ?
84m64m72m48m56mOption C

Let, length and breadth of the rectangular be 9x and 4x.

perimeter of rectangular = 78m

2 * (9x + 4x) = 78

26x = 78

x = 3

length = 9x = 9 * 3 = 27

breadth = 4x = 4 * 3 = 12

Area of the rectangular = 27 * 12 = 324 m^2

Area of square = 324m^2

side of square = 18

perimeter of the square = 4 * 18 = 72m - I. x^2 = 256

II. (y + 16)^2 =0

X>YX < YX≥YX≤YX=Y or no relation.Option C

I. x^2 = 256

x = 16, -16

II. y^2 + 32y + 256 = 0

y^2 + 16y + 256 = 0

y = -16, -16 - I. x^2 + 8x + 15 = 0

II. y^2 – 5x + 6 = 0X>YX < YX≥YX≤YX=Y or no relation.Option B

I. x^2 + 5x + 3x +15 = 0

x = -5, -3

II. y^2 – 3y – 2y + 6 = 0

y = 3, 2 - I. 2x^2 – 9x -18 = 0

II. 4y^2 + 4y – 24 = 0

X>YX < YX≥YX≤YX=Y or no relation.Option E

I. 2x^2 – 12y – 8y – 24 = 0

2x = 12, -3

x = 6, -1.5

II. 4y^2 + 12y – 8y – 24 = 0

4y = -12, 8

y = -3, 2 - I. x^2 – 20x + 64 = 0

II. y^2 – 24y + 108 = 0X>YX < YX≥YX≤YX=Y or no relation.Option E

I. x^2 – 16x – 4x + 64 = 0

x = 16, 4

II. y^2 – 18y – 64 + 108 = 0

y = 18, 6 - I. x^2 – 9x + 20 = 0

II. y^2 – 13y + 40 = 0X>YX < YX≥YX≤YX=Y or no relation.Option D

I. x^2 – 5x – 4x + 20 = 0

x = 5, 4

II. y^2 – 8y -5y +40 = 0

y = 8, 5