A can do a work in 36 days and B is 25% more efficient than A. In how many days A and B together can complete the total work ?
14 days
28 days
15 days
16 days
20 days
Option D Let efficiency of A = 4x efficiency of B = 4x * 125/100 = 5x Total work = 36 * 4x Time taken by A and B to complete total work = 36 * 4x / 9x = 16 days
Two mixture of water and milk contain 36% and 40% milk respectively. Find in what respective ratio should these mixtures be mixed so that the final mixture contains 72% water.
3 : 4
5 : 3
3 : 2
2 : 5
5 : 7
Option C percentage of milk in final mixture = 100 – 72 = 28% 36% 40% 28% 12% 8% 3 2 ratio = 3 : 2
Mohit and Rohit started a business with the capital investing rs.12000 and rs.x respectively. Mohit invested his capital for 6 months and Rohit invested his capital for 12 months. After one year total profit earned by them is rs.14000 by them and out of these profit share of Mohit is 6000, then find the value of ‘x’.
4000
8000
3800
7500
8400
Option B Profit share of Mohit = 6000 Profit share of Rohit = 14000 – 6000 = 8000 ATQ, 12000 * 6/ x * 12 = 6000/8000 12000 * 6/ x * 12 = 3/4 x = 8000
A train can cross a pole in 20 second and it can cross a 360m long platform in 50 seconds, then find the length of the train.
240
280
140
320
120
Option A Let, the length of the train be x. x/20 = x + 360/50 5x = 2x + 720 3x = 720 x = 240
The ratio of the length and breadth of a rectangular is 9 : 4 and perimeter of the rectangular is 78m. If the area of square is equal to the area of that rectangular, then what is the perimeter of the square ?
84m
64m
72m
48m
56m
Option C Let, length and breadth of the rectangular be 9x and 4x. perimeter of rectangular = 78m 2 * (9x + 4x) = 78 26x = 78 x = 3 length = 9x = 9 * 3 = 27 breadth = 4x = 4 * 3 = 12 Area of the rectangular = 27 * 12 = 324 m^2 Area of square = 324m^2 side of square = 18 perimeter of the square = 4 * 18 = 72m
I. x^2 = 256 II. (y + 16)^2 =0
X>Y
X < Y
X≥Y
X≤Y
X=Y or no relation.
Option C I. x^2 = 256 x = 16, -16 II. y^2 + 32y + 256 = 0 y^2 + 16y + 256 = 0 y = -16, -16
I. x^2 + 8x + 15 = 0 II. y^2 – 5x + 6 = 0
X>Y
X < Y
X≥Y
X≤Y
X=Y or no relation.
Option B I. x^2 + 5x + 3x +15 = 0 x = -5, -3 II. y^2 – 3y – 2y + 6 = 0 y = 3, 2
I. 2x^2 – 9x -18 = 0 II. 4y^2 + 4y – 24 = 0
X>Y
X < Y
X≥Y
X≤Y
X=Y or no relation.
Option E I. 2x^2 – 12y – 8y – 24 = 0 2x = 12, -3 x = 6, -1.5 II. 4y^2 + 12y – 8y – 24 = 0 4y = -12, 8 y = -3, 2
I. x^2 – 20x + 64 = 0 II. y^2 – 24y + 108 = 0
X>Y
X < Y
X≥Y
X≤Y
X=Y or no relation.
Option E I. x^2 – 16x – 4x + 64 = 0 x = 16, 4 II. y^2 – 18y – 64 + 108 = 0 y = 18, 6
I. x^2 – 9x + 20 = 0 II. y^2 – 13y + 40 = 0
X>Y
X < Y
X≥Y
X≤Y
X=Y or no relation.
Option D I. x^2 – 5x – 4x + 20 = 0 x = 5, 4 II. y^2 – 8y -5y +40 = 0 y = 8, 5
I additionally believe that mesothelioma is a unusual form of many forms of cancer that is typically found in individuals previously subjected to asbestos. Cancerous tissues form within the mesothelium, which is a safety lining that covers almost all of the body’s organs. These cells normally form while in the lining of your lungs, tummy, or the sac which encircles the heart. Thanks for giving your ideas.
I additionally believe that mesothelioma is a unusual form of many forms of cancer that is typically found in individuals previously subjected to asbestos. Cancerous tissues form within the mesothelium, which is a safety lining that covers almost all of the body’s organs. These cells normally form while in the lining of your lungs, tummy, or the sac which encircles the heart. Thanks for giving your ideas.
This is a topic that is close to my heart… Best wishes!
Where are your contact details though?