Quant Test for SBI PO 2018 Prelim Exam Set – 19

Hello Aspirants

State Bank of India (SBI) is going to conduct examination for its recruitment for the post of Probationary Officers (SBI PO 2018) for a total of 2000 vacancies.

Click here to know the details of the Examination

The examination will be held in three phases i.e. Preliminary Examination, Main Examination and Group Exercise & Interview. The Preliminary Exam is scheduled on 1st, 7th & 8th of July 2018. Details of the exam are as under:

Practice the questions so as to familiarize yourself with the pattern of questions to be asked in the exam. 

Directions(1-5): What approximate value should come in place of the question mark (?) in the following equation (Note: You are not expected to calculate the exact value).

1. 45% of 300 + (?)^1/2 = 56% of 750 – 10% of 250
   46600
   55200
   67600
   35200
   52200
   Option C
   45% of 300 + (?)^1/2 = 56% of 750 – 10% of 250 =>135+?^1/2 = 420-25
   => 135+?^1/2 = 395
   => ?^1/2 = 395-135
   =>?^1/2= 260
   => ? = (260)^1/2
   =>? = 67600

    

2. (7569)^1/2 /12 *104 = (?)² + (23)²
   15
   20
   12
   18
   14
   Option A
   (7569)^1/2 /12 *104 = (?)²+ (23)²
   => 87/12 * 104 = (?)^1/2+ 529
   => 754 = (?)^1/2 + 529
   => (?)² = 225
   => ? = 15

    

3. [{(150% of 44) -11}% of 660]% of 25 = (?)% of 165
   66
   33
   11
   44
   55
   Option E
   [{(150% of 44) -11}% of 660]% of 25 = (?)% of 165
   => [{(150/100 × 44) -11}% of 660]% of 25 = (?)% of 165
   => [{(66) -11}% of 660]% of 25 = (?)% of 165
   => [{55}% of 660]% of 25 = (?)% of 165
   => [55/100 × 660]% of 25 = (?)% of 165
   => [363]% of 25 = (?)% of 165
   => 90.75= (?)% of 165
   => 90.75= (?)/100 × 165
   => 90.75 × 100= (?)× 165
   => 9075/165 = (?)
   => (?) = 55

    

4. 71% of 259 – 63.21 = ? – 5% of 910
   148
   185
   125
   164
   155
   Option D
   71% of 259 – 63.21 = ? – 5% of 910
   => (70/100)*260 – 63 = ? – (5/100)*900
   => (7*26) – 63 = ? – (5*9)
   => 182 – 63 = ? – 45
   => ? = 164

    

5. 73% of 550-68% of 240=?
   222.2
   238.3
   352.6
   452.8
   520.6
   Option B
   73% of 550-68% of 240=?
   => 401.5 – 163.2= ?
   =>?= 238.3

    

6. Smallest side of a right angled triangle is 8 cm less than the side of a square of perimeter 56 cm. Second largest side of the right angled triangle is 4 cm less than the length of rectangle of area 96 sq. cm. and breadth 8 cm. What is the largest side of the right angled triangle ?
   11 cm
   8 cm
   13 cm
   10 cm
   6 cm
   Option D
   Side of a square = Perimeter/4 = 56/4 = 14 cm
   Smallest side of the right angled triangle = 14 – 8 = 6 cm.
   Lenght of rectangle = Area/Breadth = 96/8 = 12 cm
   Second side of the triangle = 12 – 4 = 8 cm
   Hypotenuse of the right angled tringle
   = [(6)² + (8)²]^1/2
   = (36 + 64)^1/2
   = (100)^1/2
   = 10 cm

    

7. The simple interest accrued on an amount of Rs. 2,500 at the end of six years is Rs. 1,875. What would be the simple interest accrued on an amount of Rs. 6,875 at the same rate and same period ?
   Rs. 4231.05
   Rs. 4526.14
   Rs. 5256.21
   Rs. 5156.25
   Rs. 5000.23
   Option D
   SI on Rs. 2500 for 6 years at a certain rate = Rs. 1875 SI on Rs. 6875 for the same period at the same rate
   = (1875 * 6875)/2500
   = Rs. 5156.25

    

8. The capital of a company is made up of 50000 preferred shares with dividend of 20% and 20000 common shares, the par value of each type of share being Rs 10. The company had a total profit of Rs 180000 out of which Rs 30000 was kept in reserve fund and the remaining distributed to share-holders. Find the dividend per cent to the common shareholders.
   25%
   14%
   10%
   20%
   32%
   Option A
   Dividend for preferred share of company = 50000 × 10 × (20/100) = Rs 100000
   Rest divident amount of company = 180000 – 100000 – 30000
   = Rs 50000
   Dividend per cent for common share
   = (50000 * 100)/(20000 *10)
   = 25%

    

9. The ratio between the speed of a bus and train is 15 : 27 respectively. Also, a car covered a distance of 720 km. in 9 hours. The speed of the bus is three-fourth of the speed of the car. How much distance will the train cover in 7 hours ?
   600 km.
   854 km.
   756 km.
   630 km.
   250 km.
   Option C
   Speed of car = Distance covered/Time taken
   =720/9 = 80 kmph
   Speed of bus = (3/4) × 80 = 60 kmph
   Speed of train = (27/15) × 60 = 108 kmph
   Distance covered by train in 7 hours = 7 × 108 = 756 km.

    

10. A and B enter into a partnership with Rs 50000 and Rs 60000 respectively. C joins them after x months contribuing Rs 70000 and B leaves x months before the end of the year. If they share the profit in the ratio of 20 : 18 : 21, then find the value of x .
    3
    8
    5
    2
    4
    Option A
    Investment of A = 50000 ×12 = Rs 600000 Investment of B = 60000 × (12 – x) Investment of C = 70000 × (12 – x) Now, 600000/60000*( 12 – x) = 20/18 => 180 = 240 – 20x => x = 3