# Quant Test for SBI PO 2018 Prelim Exam Set – 20

Hello Aspirants

State Bank of India (SBI) is going to conduct examination for its recruitment for the post of Probationary Officers (SBI PO 2018) for a total of 2000 vacancies.

The examination will be held in three phases i.e. Preliminary Examination, Main Examination and Group Exercise & Interview. The Preliminary Exam is scheduled on 1st, 7th & 8th of July 2018. Details of the exam are as under: Practice the questions so as to familiarize yourself with the pattern of questions to be asked in the exam.

Directions(1-5): Find the relationship between x and y and choose a correct option accordingly.

1. I. 2x2 – (2 + 2√5)x + 2√5 = 0
II. 4y2 – (6 + 2√2)y + 3√2 = 0

x>y
x>=y
y>=x
y>x
x=y or relation cannot be established.
Option E
I. 2x2 – (2 + 2√5)x + 2√5 = 0
=>2x2 – 2x – 2√5x + 2√5 = 0
=>2x (x – 1) – 2√5 (x – 1) = 0
x = 1, √5 (2.2)
II. 4y2 – (6 + 2√2)y + 3√2 = 0
=>4y2 – 6y – 2√2y + 3√2 = 0
=> 2y (2y – 3) – √2 (2y – 3) = 0
y = 3/2, 1/√2 (0.7)
x = y or relation cannot be established

2. I. 3x2 + 22x + 24 = 0
II. 3y2 – 8y – 16 = 0

y>=x
y>x
x>=y
x>y
x=y or relation cannot be established.
Option A
I. 3x2 + 22x + 24 = 0
=>3x2 + 22 x + 24 = 0
=> 3x2 + 18x + 4x + 24 = 0
x = -4/3, -6
II. 3y2 – 8y – 16 = 0
=>3y2 – 8y – 16 = 0
=> 3y2 – 12y + 4y – 16 = 0
y = -4/3, 4 x ≤ y

3. I. 20x2 – 31x + 12 = 0
II. 3y2 – 16y + 16 = 0

y>x
y>=x
x>y
x>=y
x=y or relation cannot be established.
Option A
I. 20x2 – 31x + 12 = 0
=>20x2 – 31x + 12 = 0
=>20x2 – 16x – 15x + 12 = 0
x = 3/4, 4/5
II. 3y2 – 16y + 16 = 0
=>3y2 – 16y + 16 = 0
=>3y2 – 14y – 4y + 16 = 0
y = 4, 4/3
x < y

4. I. x2 + √5x – 10 = 0
II. 2y2 + 9√5y + 50 = 0

x>=y
y>x
y>=x
x=y or relation cannot be established.
x>y
Option A
I. x2 + √5x – 10 = 0
=>x2 + √5x – 10 = 0
=>x2 + 2√5x – √5x – 10 = 0
x = -2√5, √5
II. 2y2 + 9√5y + 50 = 0
=>2y2 + 9√5y + 50 = 0
=> 2y2 + 4√5y + 5√5y + 50=0
y = -2√5, -5√5/2
x ≥ y

5. I. 8x2 + 5x – 13 = 0
II. 2y2 + 23y + 63 = 0

y>=x
x>y
x>=y
y>x
x=y or relation cannot be established.
Option B
I. 8x2 + 5x – 13 = 0
=>8x2 + 5x – 13 = 0
=>8x2 + 13x – 8x – 13 = 0
x = -1.625, 1
II. 2y2 + 23y + 63 = 0
=>2y2 + 23y + 63 = 0
=> 2y2 + 14y + 9y + 63 = 0
y = -7, -4.5
x > y

6. Directions(6-10): Following pie-chart shows the percentage distribution of total items (Item A and Item B) produced by six companies (P,Q,R,S,T and U) and the table shows the ratio of A to B and percentage sale of A and B.
Total items = 16 lakh  7. What is the average number of A items sold by all six companies together?
88500
75080
89680
69950
95000
Option C
A items sold by P = 16*(24/100)*(5/8)*(65/100)
= 1.56 lakh
Similarly,
Total A items = 1.56 + 0.896 + 0.6912 + 1.44 + 0.4096 + 0.384
= 5.3808 lakh
Average = 5.3808/6
= 0.8968 lakh
= 89680

8. The number of items sold by Company P is what percentage of the number of A items sold by Company U?
320.11%
415.02%
520.20%
406.25%
300.05%
Option D
A sold by P = 156000,
A sold by U = 38400
Reqd % = (156000/38400)*100
= 406.25%

9. What is the difference between the total items produced by Company P and Q together and the total items produced by Company S?
2.24 lakh
3.23 lakh
4.00 lakh
3.52 lakh
1.20 lakh
Option A
Total items = [(24+18) – 28]*16/100 = 2.24 lakh

10. What is the difference between the total number of A items and the total number of B items produced by Company U?
15800
34500
15500
25600
26000
Option D
Total = 16 × (8/100) = 1.28 lakh,
Item A = (1.28/5)* 3= 0.768
Item B = (1.28/5)*2 = 0.512
Diff = 0.768 – 0.512 = 0.256 lakh
= 25600

11. What is the difference between the number of A items sold and the number of B items sold by Company T?
12350 lakhs
15600 lakhs
32560 lakhs
20000 lakhs
14560 lakhs
Option E
Item A = 16*( 7/100)*( 4/7)* (64/100) = 0.4096
Similary, Item B = 0.2640
Diff = 0.4096 – 0.2640 = 0.1456 lakh
= 14560 lakhs

## One Thought to “Quant Test for SBI PO 2018 Prelim Exam Set – 20”

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