Quant Test for SBI PO 2018 Prelim Exam Set – 20

Hello Aspirants

State Bank of India (SBI) is going to conduct examination for its recruitment for the post of Probationary Officers (SBI PO 2018) for a total of 2000 vacancies.

Click here to know the details of the Examination

The examination will be held in three phases i.e. Preliminary Examination, Main Examination and Group Exercise & Interview. The Preliminary Exam is scheduled on 1st, 7th & 8th of July 2018. Details of the exam are as under:

Practice the questions so as to familiarize yourself with the pattern of questions to be asked in the exam. 


 

Directions(1-5): Find the relationship between x and y and choose a correct option accordingly.

  1. I. 2x2 – (2 + 2√5)x + 2√5 = 0
    II. 4y2 – (6 + 2√2)y + 3√2 = 0

    x>y
    x>=y
    y>=x
    y>x
    x=y or relation cannot be established.
    Option E
    I. 2x2 – (2 + 2√5)x + 2√5 = 0
    =>2x2 – 2x – 2√5x + 2√5 = 0
    =>2x (x – 1) – 2√5 (x – 1) = 0
    x = 1, √5 (2.2)
    II. 4y2 – (6 + 2√2)y + 3√2 = 0
    =>4y2 – 6y – 2√2y + 3√2 = 0
    => 2y (2y – 3) – √2 (2y – 3) = 0
    y = 3/2, 1/√2 (0.7)
    x = y or relation cannot be established

     

  2. I. 3x2 + 22x + 24 = 0
    II. 3y2 – 8y – 16 = 0

    y>=x
    y>x
    x>=y
    x>y
    x=y or relation cannot be established.
    Option A
    I. 3x2 + 22x + 24 = 0
    =>3x2 + 22 x + 24 = 0
    => 3x2 + 18x + 4x + 24 = 0
    x = -4/3, -6
    II. 3y2 – 8y – 16 = 0
    =>3y2 – 8y – 16 = 0
    => 3y2 – 12y + 4y – 16 = 0
    y = -4/3, 4 x ≤ y

     

  3. I. 20x2 – 31x + 12 = 0
    II. 3y2 – 16y + 16 = 0

    y>x
    y>=x
    x>y
    x>=y
    x=y or relation cannot be established.
    Option A
    I. 20x2 – 31x + 12 = 0
    =>20x2 – 31x + 12 = 0
    =>20x2 – 16x – 15x + 12 = 0
    x = 3/4, 4/5
    II. 3y2 – 16y + 16 = 0
    =>3y2 – 16y + 16 = 0
    =>3y2 – 14y – 4y + 16 = 0
    y = 4, 4/3
    x < y

     

  4. I. x2 + √5x – 10 = 0
    II. 2y2 + 9√5y + 50 = 0

    x>=y
    y>x
    y>=x
    x=y or relation cannot be established.
    x>y
    Option A
    I. x2 + √5x – 10 = 0
    =>x2 + √5x – 10 = 0
    =>x2 + 2√5x – √5x – 10 = 0
    x = -2√5, √5
    II. 2y2 + 9√5y + 50 = 0
    =>2y2 + 9√5y + 50 = 0
    => 2y2 + 4√5y + 5√5y + 50=0
    y = -2√5, -5√5/2
    x ≥ y

     

  5. I. 8x2 + 5x – 13 = 0
    II. 2y2 + 23y + 63 = 0

    y>=x
    x>y
    x>=y
    y>x
    x=y or relation cannot be established.
    Option B
    I. 8x2 + 5x – 13 = 0
    =>8x2 + 5x – 13 = 0
    =>8x2 + 13x – 8x – 13 = 0
    x = -1.625, 1
    II. 2y2 + 23y + 63 = 0
    =>2y2 + 23y + 63 = 0
    => 2y2 + 14y + 9y + 63 = 0
    y = -7, -4.5
    x > y

     

  6. Directions(6-10): Following pie-chart shows the percentage distribution of total items (Item A and Item B) produced by six companies (P,Q,R,S,T and U) and the table shows the ratio of A to B and percentage sale of A and B.
    Total items = 16 lakh

  7. What is the average number of A items sold by all six companies together?
    88500
    75080
    89680
    69950
    95000
    Option C
    A items sold by P = 16*(24/100)*(5/8)*(65/100)
    = 1.56 lakh
    Similarly,
    Total A items = 1.56 + 0.896 + 0.6912 + 1.44 + 0.4096 + 0.384
    = 5.3808 lakh
    Average = 5.3808/6
    = 0.8968 lakh
    = 89680

     

  8. The number of items sold by Company P is what percentage of the number of A items sold by Company U?
    320.11%
    415.02%
    520.20%
    406.25%
    300.05%
    Option D
    A sold by P = 156000,
    A sold by U = 38400
    Reqd % = (156000/38400)*100
    = 406.25%

     

  9. What is the difference between the total items produced by Company P and Q together and the total items produced by Company S?
    2.24 lakh
    3.23 lakh
    4.00 lakh
    3.52 lakh
    1.20 lakh
    Option A
    Total items = [(24+18) – 28]*16/100 = 2.24 lakh

     

  10. What is the difference between the total number of A items and the total number of B items produced by Company U?
    15800
    34500
    15500
    25600
    26000
    Option D
    Total = 16 × (8/100) = 1.28 lakh,
    Item A = (1.28/5)* 3= 0.768
    Item B = (1.28/5)*2 = 0.512
    Diff = 0.768 – 0.512 = 0.256 lakh
    = 25600

     

  11. What is the difference between the number of A items sold and the number of B items sold by Company T?
    12350 lakhs
    15600 lakhs
    32560 lakhs
    20000 lakhs
    14560 lakhs
    Option E
    Item A = 16*( 7/100)*( 4/7)* (64/100) = 0.4096
    Similary, Item B = 0.2640
    Diff = 0.4096 – 0.2640 = 0.1456 lakh
    = 14560 lakhs

     


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