# Quant Test for SBI PO 2018 Prelim Exam Set – 25

Hello Aspirants

State Bank of India (SBI) is going to conduct examination for its recruitment for the post of Probationary Officers (SBI PO 2018) for a total of 2000 vacancies.

The examination will be held in three phases i.e. Preliminary Examination, Main Examination and Group Exercise & Interview. The Preliminary Exam is scheduled onÂ 1st, 7th & 8th of July 2018. Details of the exam are as under:

Practice the questions so as to familiarize yourself with the pattern of questions to be asked in the exam.Â

Directions(1-5): What is the approximate value come in place of question mark?

1. (4444Ã·40)+(645Ã·25)+(3991Ã·26)=?
200.5
290.4
280.8
220.4
222.2
Option B
(4444Ã·40)+(645Ã·25)+(3991Ã·26)=?
=> 111.1 + 25.8 + 153.5 = ?
=> ? = 290.4

2. 456 Ã· 24 x 38 â€“ 958 + 364 =?
110
120
135
128
132
Option D
456 Ã· 24 x 38 â€“ 958 + 364 =?
=> 19 * 38 â€“ 958 + 364 = ?
=> 722 â€“ 958 + 364 = ?
=> 128

3. (2222.5 â€“ 1680 x 0.75) x 1.2=?
1215
1335
1050
1145
1155
Option E
(2222.5 â€“ 1680 x 0.75) x 1.2=?
=> ( 2222.5 â€“ 1260 ) * 1.2 = ?
=> 1155

4. 86+34 x 79 -1512Ã·63+13 x 10 =?
2878
2552
2275
2890
2752
Option A
86+34 x 79 -1512Ã·63+13 x 10 =?
=> 86 + 2686 â€“ 24 + 13* 10 = ?
=> 86 + 2686 -24 + 130 = ?
=> 86 + 2816 â€“ 24 = ?
=> ? = 2878

5. 2.002+7.9{2.8-6.3(3.6 â€“ 1.5) + 15.6} =?
45.211
40.256
44.115
40.540
42.845
Option E
2.002+7.9{2.8-6.3(3.6 â€“ 1.5) + 15.6} =?
=> 2.002 + 7.9{2.8 â€“ 6.3(2.1) + 15.6 } =?
=> 2.002 + 7.9{ 2.8 â€“ 13.23 + 15.6} = ?
=> 2.002 + 7.9{5.17} = ?
=> 2.002 + 40.846 = ?
=> ? = 42.845

6. 4 men and 10 women were put on a work. They completed 1/3 of the work in 4 days. After this 2 men and 2 women were increased. They completed 2/9 more of the work in 2 days. If the remaining work is to be completed in 3 days, then how many more women must be increased ?
5
7
6
8
9
Option D
Let one man takes x days to complete the work and one woman takes y days to complete the work independently.
Then, (4*4)/x + (10*4)/y = 1/3 —-(1)
(6*2)/x + (12*2)/y = 2/9 —–(2)
Solving above equations, we get
x = 108, y = 216
Let z women be added to complete the work in 3 days.
Then,
(6*3)/108 + 3(12+z)/216 = 1 â€“ [(1/3)+(2/9)] => z = 8

7. A bought 4 bottles of beer and B bought one bottle of lager, lager per bottle costing twice that of the beer. C bought nothing but paid Rs 50, for his share of the drink which they mixed together and shared equally. If Câ€™s Rs 50 covered his share, then what is the cost of the lager ?
40
50
70
20
60
Option B
Total amount spent by them = Rs. 150
Let the cost of one beer be x,
then the cost of one lager will be 2x.
Total money spent on beer and larger = (4x + 2x)
=>6x = 150
=> x = 25
The cost of the larger = 25 Ã— 2
= 50

8. Seemaâ€™s present age is four times her sonâ€™s present age and four-seventh of her fatherâ€™s present age. The average of the present ages of all three of them is 32 years. What is the difference between the Seemaâ€™s sonâ€™s present age and Seemaâ€™s fatherâ€™s present age ?
42 years
40 years
45 years
43 years
48 years
Option E
Let Seemaâ€™s sonâ€™s present age = x years
Seemaâ€™s present age = 4x years
Seemaâ€™s husbandâ€™s present age = 4x Ã— 7/4 = 7x years
=> x + 4x + 7x = 32 Ã— 3
=> 12x = 96
=> x = 8
Required difference = 7x – x
= 6x
= 6 Ã— 8
= 48 years

9. X and Y entered into partnership with Rs. 700 and Rs. 600 respectively. After 3 months, X withdrew 2/7 of his stock but after 3 months, he puts back 3/5 of what he had withdrawn. The profit at the end of the year is Rs 726. How much of this should X receive ?
Rs.380
Rs.300
Rs.400
Rs.366
Rs.372
Option D
Xâ€™s investment
= (700 Ã— 3) + (700 * 5/7 * 3) + (500 * 200 * 3/5) * 6
= Rs. 7320
Yâ€™s investment = 600 Ã— 12
= Rs. 7200
Xâ€™s share from profit = 7320/(7320 + 7200) Ã— 726
= Rs. 366

10. Smallest side of a right angled triangle is 8 cm less than the side of a square of perimeter 56 cm. Second largest side of the right angled triangle is 4 cm less than the length of rectangle of area 96 sq. cm. and breadth 8 cm. What is the largest side of the right angled triangle ?
10 cm
12 cm
18 cm
15 cm
13 cm
Option A
Side of a square = Perimeter/4
= 56/4
= 14 cm
Smallest side of the right angled triangle = 14 – 8 = 6 cm.
= 96/8 = 12 cm
Second side of the triangle = 12 – 4
= 8 cm
Hypotenuse of the right angled triangle
= 6^2 + 8^2
= 36 + 64
= 100
= 10 cm

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