# Quant Test for SBI PO 2018 Prelim Exam Set – 25

Hello Aspirants

State Bank of India (SBI) is going to conduct examination for its recruitment for the post of Probationary Officers (SBI PO 2018) for a total of 2000 vacancies.

Click here to know the details of the Examination

The examination will be held in three phases i.e. Preliminary Examination, Main Examination and Group Exercise & Interview. The Preliminary Exam is scheduled on 1st, 7th & 8th of July 2018. Details of the exam are as under: Practice the questions so as to familiarize yourself with the pattern of questions to be asked in the exam.

Directions(1-5): What is the approximate value come in place of question mark?

1. (4444÷40)+(645÷25)+(3991÷26)=?
200.5
290.4
280.8
220.4
222.2
Option B
(4444÷40)+(645÷25)+(3991÷26)=?
=> 111.1 + 25.8 + 153.5 = ?
=> ? = 290.4

2. 456 ÷ 24 x 38 – 958 + 364 =?
110
120
135
128
132
Option D
456 ÷ 24 x 38 – 958 + 364 =?
=> 19 * 38 – 958 + 364 = ?
=> 722 – 958 + 364 = ?
=> 128

3. (2222.5 – 1680 x 0.75) x 1.2=?
1215
1335
1050
1145
1155
Option E
(2222.5 – 1680 x 0.75) x 1.2=?
=> ( 2222.5 – 1260 ) * 1.2 = ?
=> 1155

4. 86+34 x 79 -1512÷63+13 x 10 =?
2878
2552
2275
2890
2752
Option A
86+34 x 79 -1512÷63+13 x 10 =?
=> 86 + 2686 – 24 + 13* 10 = ?
=> 86 + 2686 -24 + 130 = ?
=> 86 + 2816 – 24 = ?
=> ? = 2878

5. 2.002+7.9{2.8-6.3(3.6 – 1.5) + 15.6} =?
45.211
40.256
44.115
40.540
42.845
Option E
2.002+7.9{2.8-6.3(3.6 – 1.5) + 15.6} =?
=> 2.002 + 7.9{2.8 – 6.3(2.1) + 15.6 } =?
=> 2.002 + 7.9{ 2.8 – 13.23 + 15.6} = ?
=> 2.002 + 7.9{5.17} = ?
=> 2.002 + 40.846 = ?
=> ? = 42.845

6. 4 men and 10 women were put on a work. They completed 1/3 of the work in 4 days. After this 2 men and 2 women were increased. They completed 2/9 more of the work in 2 days. If the remaining work is to be completed in 3 days, then how many more women must be increased ?
5
7
6
8
9
Option D
Let one man takes x days to complete the work and one woman takes y days to complete the work independently.
Then, (4*4)/x + (10*4)/y = 1/3 —-(1)
(6*2)/x + (12*2)/y = 2/9 —–(2)
Solving above equations, we get
x = 108, y = 216
Let z women be added to complete the work in 3 days.
Then,
(6*3)/108 + 3(12+z)/216 = 1 – [(1/3)+(2/9)] => z = 8

7. A bought 4 bottles of beer and B bought one bottle of lager, lager per bottle costing twice that of the beer. C bought nothing but paid Rs 50, for his share of the drink which they mixed together and shared equally. If C’s Rs 50 covered his share, then what is the cost of the lager ?
40
50
70
20
60
Option B
Total amount spent by them = Rs. 150
Let the cost of one beer be x,
then the cost of one lager will be 2x.
Total money spent on beer and larger = (4x + 2x)
=>6x = 150
=> x = 25
The cost of the larger = 25 × 2
= 50

8. Seema’s present age is four times her son’s present age and four-seventh of her father’s present age. The average of the present ages of all three of them is 32 years. What is the difference between the Seema’s son’s present age and Seema’s father’s present age ?
42 years
40 years
45 years
43 years
48 years
Option E
Let Seema’s son’s present age = x years
Seema’s present age = 4x years
Seema’s husband’s present age = 4x × 7/4 = 7x years
=> x + 4x + 7x = 32 × 3
=> 12x = 96
=> x = 8
Required difference = 7x – x
= 6x
= 6 × 8
= 48 years

9. X and Y entered into partnership with Rs. 700 and Rs. 600 respectively. After 3 months, X withdrew 2/7 of his stock but after 3 months, he puts back 3/5 of what he had withdrawn. The profit at the end of the year is Rs 726. How much of this should X receive ?
Rs.380
Rs.300
Rs.400
Rs.366
Rs.372
Option D
X’s investment
= (700 × 3) + (700 * 5/7 * 3) + (500 * 200 * 3/5) * 6
= Rs. 7320
Y’s investment = 600 × 12
= Rs. 7200
X’s share from profit = 7320/(7320 + 7200) × 726
= Rs. 366

10. Smallest side of a right angled triangle is 8 cm less than the side of a square of perimeter 56 cm. Second largest side of the right angled triangle is 4 cm less than the length of rectangle of area 96 sq. cm. and breadth 8 cm. What is the largest side of the right angled triangle ?
10 cm
12 cm
18 cm
15 cm
13 cm
Option A
Side of a square = Perimeter/4
= 56/4
= 14 cm
Smallest side of the right angled triangle = 14 – 8 = 6 cm.
Length of rectangle = Area/Breadth
= 96/8 = 12 cm
Second side of the triangle = 12 – 4
= 8 cm
Hypotenuse of the right angled triangle
= 6^2 + 8^2
= 36 + 64
= 100
= 10 cm