Hello Aspirants

**State Bank of India (SBI)** is going to conduct examination for its recruitment for the post of Probationary Officers (SBI PO 2018) for a total of 2000 vacancies.

Click here to know the details of the Examination

The examination will be held in three phases i.e. Preliminary Examination, Main Examination and Group Exercise & Interview. The Preliminary Exam is scheduled onÂ **1st, 7th & 8th of July 2018. **Details of the exam are as under:

Practice the questions so as to familiarize yourself with the pattern of questions to be asked in the exam.Â

**Directions(1-5): **What is the approximate value come in place of question mark?

- (4444Ã·40)+(645Ã·25)+(3991Ã·26)=?
200.5290.4280.8220.4222.2Option B

(4444Ã·40)+(645Ã·25)+(3991Ã·26)=?

=> 111.1 + 25.8 + 153.5 = ?

=> ? = 290.4 - 456 Ã· 24 x 38 â€“ 958 + 364 =?
110120135128132Option D

456 Ã· 24 x 38 â€“ 958 + 364 =?

=> 19 * 38 â€“ 958 + 364 = ?

=> 722 â€“ 958 + 364 = ?

=> 128 - (2222.5 â€“ 1680 x 0.75) x 1.2=?
12151335105011451155Option E

(2222.5 â€“ 1680 x 0.75) x 1.2=?

=> ( 2222.5 â€“ 1260 ) * 1.2 = ?

=> 1155 - 86+34 x 79 -1512Ã·63+13 x 10 =?
28782552227528902752Option A

86+34 x 79 -1512Ã·63+13 x 10 =?

=> 86 + 2686 â€“ 24 + 13* 10 = ?

=> 86 + 2686 -24 + 130 = ?

=> 86 + 2816 â€“ 24 = ?

=> ? = 2878 - 2.002+7.9{2.8-6.3(3.6 â€“ 1.5) + 15.6} =?
45.21140.25644.11540.54042.845Option E

2.002+7.9{2.8-6.3(3.6 â€“ 1.5) + 15.6} =?

=> 2.002 + 7.9{2.8 â€“ 6.3(2.1) + 15.6 } =?

=> 2.002 + 7.9{ 2.8 â€“ 13.23 + 15.6} = ?

=> 2.002 + 7.9{5.17} = ?

=> 2.002 + 40.846 = ?

=> ? = 42.845 - 4 men and 10 women were put on a work. They completed 1/3 of the work in 4 days. After this 2 men and 2 women were increased. They completed 2/9 more of the work in 2 days. If the remaining work is to be completed in 3 days, then how many more women must be increased ?
57689Option D

Let one man takes x days to complete the work and one woman takes y days to complete the work independently.

Then, (4*4)/x + (10*4)/y = 1/3 —-(1)

(6*2)/x + (12*2)/y = 2/9 —–(2)

Solving above equations, we get

x = 108, y = 216

Let z women be added to complete the work in 3 days.

Then,

(6*3)/108 + 3(12+z)/216 = 1 â€“ [(1/3)+(2/9)] => z = 8 - A bought 4 bottles of beer and B bought one bottle of lager, lager per bottle costing twice that of the beer. C bought nothing but paid Rs 50, for his share of the drink which they mixed together and shared equally. If Câ€™s Rs 50 covered his share, then what is the cost of the lager ?
4050702060Option B

Total amount spent by them = Rs. 150

Let the cost of one beer be x,

then the cost of one lager will be 2x.

Total money spent on beer and larger = (4x + 2x)

=>6x = 150

=> x = 25

The cost of the larger = 25 Ã— 2

= 50 - Seemaâ€™s present age is four times her sonâ€™s present age and four-seventh of her fatherâ€™s present age. The average of the present ages of all three of them is 32 years. What is the difference between the Seemaâ€™s sonâ€™s present age and Seemaâ€™s fatherâ€™s present age ?
42 years40 years45 years43 years48 yearsOption E

Let Seemaâ€™s sonâ€™s present age = x years

Seemaâ€™s present age = 4x years

Seemaâ€™s husbandâ€™s present age = 4x Ã— 7/4 = 7x years

=> x + 4x + 7x = 32 Ã— 3

=> 12x = 96

=> x = 8

Required difference = 7x – x

= 6x

= 6 Ã— 8

= 48 years - X and Y entered into partnership with Rs. 700 and Rs. 600 respectively. After 3 months, X withdrew 2/7 of his stock but after 3 months, he puts back 3/5 of what he had withdrawn. The profit at the end of the year is Rs 726. How much of this should X receive ?
Rs.380Rs.300Rs.400Rs.366Rs.372Option D

Xâ€™s investment

= (700 Ã— 3) + (700 * 5/7 * 3) + (500 * 200 * 3/5) * 6

= Rs. 7320

Yâ€™s investment = 600 Ã— 12

= Rs. 7200

Xâ€™s share from profit = 7320/(7320 + 7200) Ã— 726

= Rs. 366 - Smallest side of a right angled triangle is 8 cm less than the side of a square of perimeter 56 cm. Second largest side of the right angled triangle is 4 cm less than the length of rectangle of area 96 sq. cm. and breadth 8 cm. What is the largest side of the right angled triangle ?
10 cm12 cm18 cm15 cm13 cmOption A

Side of a square = Perimeter/4

= 56/4

= 14 cm

Smallest side of the right angled triangle = 14 – 8 = 6 cm.

Length of rectangle = Area/Breadth

= 96/8 = 12 cm

Second side of the triangle = 12 – 4

= 8 cm

Hypotenuse of the right angled triangle

= 6^2 + 8^2

= 36 + 64

= 100

= 10 cm

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