# Quant Test for SBI PO 2018 Prelim Exam Set – 31

Hello Aspirants

State Bank of India (SBI) is going to conduct examination for its recruitment for the post of Probationary Officers (SBI PO 2018) for a total of 2000 vacancies.

The examination will be held in three phases i.e. Preliminary Examination, Main Examination and Group Exercise & Interview. The Preliminary Exam is scheduled on 1st, 7th & 8th of July 2018. Details of the exam are as under: Practice the questions so as to familiarize yourself with the pattern of questions to be asked in the exam.

Directions(1-5): What will come in place of question mark “?” in the following questions.

1. (28.72 × 15.32) × 4.9 – ? = 42.33% of 1599.79 – 20.3% of 1424.9
1742
1718
1707
1788
1717
Option D
(28.72 × 15.32) × 4.9 – ? = 42.33% of 1599.79 – 20.3% of 1424.9
=> (29 × 15) × 5 – ? = 42% of 1600 – 20% of 1425
=> 435 × 5 – ? = 672 – 285
=> 2175 – ? = 387
? = 1788

2. (17.8)² + (11.022)² – ? × 5.22 + 40.11 × 49.78% of 1244.33 = 554.779
4500
4954
4980
4444
4526
Option B
(17.8)² + (11.022)² – ? × 5.22 + 40.11 × 49.78% of 1244.33 = 554.779
=> (18)² + (11)² – ? × 5 + 40 × 50% of 1244 = 555
=> 324 + 121 – ? × 5 + 24880 = 555
=> ? × 5 = 24770
? = 4954

3. 27.97 × 12.22 + 3.24% of 14200.33 =? + (37.11)² – (13.03)³
1590
1522
1500
1523
1525
Option A
27.97 × 12.22 + 3.24% of 14200.33 =? + (37.11)² – (13.03)³
=> 28 × 12 + 3% of 14200 =? + (37)² – (13)³
=> 336 + 426 =? + 1369 – 2197
=> ? = 2197 – 1369 + 336 + 426
? = 1590

4. 49.67% of 35.23% of 98320.211 = (48.3)² + 10.2% of 1729.86 +?
14552
11250
14556
13250
14729
Option E
49.67% of 35.23% of 98320.211 = (48.3)² + 10.2% of 1729.86 +?
=> 50% of 35% of 98320 = (48)² + 10% of 1730 +?
=> 17206 = 2304 + 173 +?
? = 14729

5. (48.22 × 5.33) + 20% of 1499.58 – (7.83 × 5.213) +? = 10.2% of 1790
– 155
– 302
– 321
– 245
– 99
Option C
(48.22 × 5.33) + 20% of 1499.58 – (7.83 × 5.213) +? = 10.2% of 1790
=> (48 × 5) + 20% of 1500 – (8 × 5) +? = 10% of 1790
=> 240 + 300 – 40 + ? = 179
=> 500 + ? = 179
? = -321

6. A boat can go at a speed of 7 (1/2) km/hr in still water. If it takes thrice the time to cover a distance upstream as to cover the same distance downstream, then find the speed of the stream (in km/hr) .
2.15 km/hr.
4.25 km/hr.
3.00 km/hr.
3.75 km/hr.
2.19 km/hr.
Option D
Let the speed of stream = x km/hr.
Rate of upstream = (15/2) – x
Rate of downstream = (15/2) + x
Therefore, 3/[(15/2) + x] = 1/[(15/2) – x] => x= 3.75 km/hr.

7. Mixture of milk and water has been kept in two separate containers. Ratio of milk to water in one of the containers is 5 : 1 and that in the other container is 7 : 2. In that ratio the mixture of these two containes should be added together, so that the quantity of milk in the new mixture may become 80% ?
3:5
4:7
1:3
2:5
2:3
Option E
Percentage of milk in first mixture = 5/6 ×100
= 250/3 %
Percentage of milk in second mixture = 7/9 × 100
= 700/9 %
Using Alligation method
250/3======700/9
=======80
20/9========10/3
Ratio = 2:3

8. Ruby’s monthly income is three times Gayatri’s monthly income, Gayatri’s monthly income is fifteen percent more than Priya’s monthly income, Priya’s monthly income is Rs 32,000. What is Ruby’s Annual income ?
Rs.1102550
Rs.1322560
Rs.1544500
Rs.1324800
Rs.1225500
Option
Gayatri’s monthly income = (32000 * 115)/100
= Rs. 36800
Ruby’s annual income = Rs. (12 × 3 × 36800)
= Rs. 1324800

9. Ninad, Vikas and Manav enter into a partnership. Ninad invests some amount at the beginning. Vikas invests doublé the amount after 6 months and Manav invests thrice the amount invested by Ninad after 8 months. They eam a proflt of Rs. 45,000 at the end of the year. What is Manav’s share in the profit ?
Rs.12000
Rs.15000
Rs.11000
Rs.14000
Rs.13000
Option B
Vikas’s investment = Rs.2x Manav’s investment = Rs. 3x
Ratio of the equivalent capital of Ninad, Vikas and Manav respectively
= x ×12 : 2x × 6 : 4 × 3x
= 1 : 1 : 1
Clearly, the proflt will be shared equally Manav’s share
= Rs. 1/3 × 45000
= Rs. 15000

10. In how many different ways can the letters of the word ‘DETAIL’ be arranged such that the vowels must occupy only the odd positions?
44
25
32
40
36
Option E
Number of ways to arrange these vowels = 3P3 = 3!
=3×2×1=6
Number of ways to arrange these consonants = 3P3 = 3!
=3×2×1=6
Total number of ways = number of ways to arrange the vowels × number of ways to arrange the consonants
=6×6
=36

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