Quant Test for SBI PO 2018 Prelim Exam Set – 32

Hello Aspirants

State Bank of India (SBI) is going to conduct examination for its recruitment for the post of Probationary Officers (SBI PO 2018) for a total of 2000 vacancies.

Click here to know the details of the Examination

The examination will be held in three phases i.e. Preliminary Examination, Main Examination and Group Exercise & Interview. The Preliminary Exam is scheduled on 1st, 7th & 8th of July 2018. Details of the exam are as under:

Practice the questions so as to familiarize yourself with the pattern of questions to be asked in the exam. 

Directions(1-5): Find the missing term of the series.

1. 23, 25, 53, 163, 657, 3291, ?
   17458
   16256
   11250
   14251
   19753
   Option E
   23, 25, 53, 163, 657, 3291, ?
   => 23 × 1 + 2 = 25
   => 25 × 2 + 3 = 53
   => 53 × 3 + 4 = 163
   => 163 × 4 + 5 = 657
   => 657 × 5 + 6 = 3291
   => ? = 3291 × 6 + 7 = 19746 + 7 = 19753

    

2. 3, 4, 12, ?, 196
   38
   40
   45
   35
   32
   Option C
   3, 4, 12, ?, 196
   => 3 × 1 + l^2 = 3 + 1 = 4
   => 4 × 2 + 2^2 = 8 + 4= 12
   => 12 × 3 + 3^2 = 36 + 9 = 45
   => 45 × 4 + 4^2 = 180 + 16 = 196

    

3. 0, 5, 18, 43, 84, 145, ?
   230
   202
   215
   222
   200
   Option A
   0, 5, 18, 43, 84, 145, ?
   => 0 + 5 = 5
   => 5 + 13 = 18
   => 18 + 25 = 43
   => 43 + 41 = 84
   => 84 + 61 = 145
   => ? = 145 + 85 = 230

    

4. 45, 46, 70, 141, ?, 1061.5
   300.5
   310.2
   228.5
   353.5
   202.4
   Option D
   45, 46, 70, 141, ?, 1061.5
   => 45 × 1 + 1 = 46
   => 46 × 1.5 + 1 = 70
   => 70 × 2 + 1 = 141
   => 141 × 2.5 + 1 = 352.5 + 1 = 353.5

    

5. ?, 16, 28, 58, 114, 204
   10
   8
   14
   19
   20
   Option C
   ?, 16, 28, 58, 114, 204
   => 14 + 1 × 2 = 16
   => 16 + 3 × 4 = 16 + 12 = 28
   => 28 + 5 × 6 = 28 + 30 = 58
   => 58 + 7 × 8 = 58 + 56 = 114
   => 114 + 9 × 10 = 114 + 90 = 204

    

6. Three containers, A, B and C are having mixtures of milk and water in the ratio 1 : 5, 3 : 5 and 5 : 7 respectively. If the capacities of the containers are in the ratio 5 : 4 : 5, then find the ratio of the milk to the water, if the mixtures of all the three containers are mixed together.
   35 : 151
   44 : 101
   43 : 105
   55 : 111
   53 : 115
   Option E
   By question ratio of milk and water
   = [(1/6)*5 + (3/8)*4 + (5/12)*5] : [(5/6)*5 + (5/8)*4 + (7/12)*5] = 106 : 230
   = 53 : 115

    

7. Two cars start together in the same direction from the same place. The first goes with a uniform speed of 10 km/h. The second goes at a speed of 8 km/h in the first hour and increase the speed by 1/2 km each succeeding hour. After how many hours will the second car overtaken the first if both go non stop ?
   2 h
   5 h
   7 h
   9 h
   4 h
   Option D
   Let second car overtake the first car after n h.
   Distance covered by first car = Distance covered by second car
   => 10n = 8 + [8+(1/2)] + [8+(1/2)] + [8+ (n-1)/2] => 10n = 8n + ½[1+2+………+(n-1)] => 10n = 8n +1/2[n(n-1)/2] => 2n = ¼(n^2 – n)
   => n = 9
   Hence the answer is 9 h.

    

8. Peter got 30% of the maximum marks in an examination and failed by 10 marks. However, Paul who took the same examination got 40% of the total marks and got 15 more than the passing marks in the examination. What were the passing marks in the examination ?
   80
   77
   90
   85
   74
   Option D
   Let the maximum marks be x.
   Then, x × 30% + 10 = x × 40% – 15
   => x × 10% = 25
   => x = 250
   Passing marks = 250 × 30/100 + 10
   = 85

    

9. Mr. Sarang invests 6% of his monthly salary i.e. Rs.2,100 on insurance policies. Also he invests 8% of his monthly salary on family mediclaim policies and another 9% of his salary on NSCs. What is the total annual amount invested by Mr. Sarang ?
   Rs.74520
   Rs.95200
   Rs.82000
   Rs.96600
   Rs.89500
   Option D
   6% of Sarang’s monthly income = Rs. 2100
   Sarang’s monthly income = 2100 * 100/6 = Rs. 35000
   Percentage of monthly investment = 23%
   Sarang’s annual investment = 12 × 35000 × 23/100
   = Rs. 96600

    

10. 6 men can complete a piece work in 12 days. 8 women can complete the same piece of work in 18 days whereas 18 children can complete the piece of work in 10 days. 4 men, 12 women and 20 children work together for 2 days. If only men were to complete the remaining work in 1 day how many men would be required totally ?
    20
    36
    30
    25
    33
    Option B
    72 men = 144 women = 180 children
    2 men = 4 women = 5 children
    4 men +12 women + 20 children
    = 4 men+ 6 men+ 8 men
    = 18 men
    When 6 men do 1 work in 12 days 18 men will do the same in 4 days.
    In 2 days half work will done.
    Remaining work = ½ M1*D1/W1 = M2*D2/W2
    => 1/2 × 6 × 12 = l × M2
    => M2 = 36 = Number of men