Hello Aspirants

**State Bank of India (SBI)** is going to conduct examination for its recruitment for the post of Probationary Officers (SBI PO 2018) for a total of 2000 vacancies.

Click here to know the details of the Examination

The examination will be held in three phases i.e. Preliminary Examination, Main Examination and Group Exercise & Interview. The Preliminary Exam is scheduled onÂ **1st, 7th & 8th of July 2018. **Details of the exam are as under:

Practice the questions so as to familiarize yourself with the pattern of questions to be asked in the exam.Â

**Directions(1-5):** What will come in place of question mark (?) in the following question?

- 75% of 1240 = 35% of 1560 + ?
202285300384400Option D

75% of 1240 = 35% of 1560 + ?

=> 930 = 546 + ?

=> ? = 384 - (15% of 2200)% of 240 = (? Ã— 4 ) + (25% of 2450)
66.23144.87552.31140.12533.231Option B

(15% of 2200)% of 240 = (? Ã— 4 ) + (25% of 2450)

=> 330% of 240 = 4 Ã— ? + 612.5

=> 792 – 612.5 = 4 Ã— ?

=> ? = 179.5/4

=> ? = 44.875 - 15% of 2520 + 42% of 2500 – ? = (42 Ã— 22 ) Ã· 3.5 + 40% of 3420
– 204– 85– 100– 75– 66Option A

15% of 2520 + 42% of 2500 – ? = (42 Ã— 22 ) Ã· 3.5 + 40% of 3420

=> 378 + 1050 – ? = 924/3.5 + 1368

=>1428 – ? = 264 + 1368

=> 1428 – 1632 = ?

=> ? = – 204 - (61)^2 + (51)^2 – 60% of 2/3 of 40% of 13200 = ?
42103010445035002588Option A

(61)^2 + (51)^2 – 60% of 2/3 of 40% of 13200 = ?

=> 3721 + 2601 – 2112 = ?

=> ? = 4210 - 42% of 3000 + (? Ã— 14 ) – (21 Ã· 3.5 ) = (13)^2 + (21 Ã— 2.5)
– 60.06– 65.65– 33.12– 52.02-73.75Option E

42% of 3000 + (? Ã— 14 ) – (21 Ã· 3.5 ) = (13)^2 + (21 Ã— 2.5)

=> 1260 + (14 Ã— ? ) – 6 = 169 + 52.5

=> 14 Ã— ? = 221.5 + 6 – 1260

=> ? = – 1032.5/14

=> ? = – 73.75 - The amount of interest for a certain sum at 5â€¢5% annual rate of interest for one year is Rs. 676â€¢5. How much the interest will be less on the same sum at 5% annual rate of interest for one year ?
Rs.48.5Rs.68.2Rs.55.5Rs.61.5Rs.35.3Option D

Let the certain sum be Rs. P

=> 676â€¢5 = P *5â€¢5*1/100

and second interest = (P *5 *1)/100 ï€

Required sum = 676â€¢5 â€“ Second interest

= (P *5â€¢5*1)/100 â€“ (P*5*1)/100

= P (5â€¢5 â€“ 5)/100 = P*0â€¢5/100

= (676â€¢5 *100 *0â€¢5)/(5â€¢5*1*100)

= 61â€¢5

Hence, Required sum = Rs. 61â€¢5 - Village A has a population of 6800, which is decreasing at the rate of 120 per year. Village B has a population of 4200, which is increasing at the rate of 80 per year. In how many years will the population of the two villages be equal ?
11 yr.10 yr.12 yr.13 yr.15 yr.Option D

After 13 yr population of village A

= 6800 – 120 Ã— 13

= 5240

After 13 yr population of village B

= 4200 + 80 Ã— 13

= 5240 - Taps A, B and C are connected to a water tank and the rate of flow of water is 42 litres/hr., 56 litres/ hr. and 48 litres/hr. respectively. Taps A and B fill the tank while tap C empties the tank. If all the three taps are opened simultaneously, the tank gets completely filled up in 16 hours. What is the capacity of the tank ?
500 l800 l600 l900 l700 lOption B

Net amount of water filled in the tank in 1 hour

when all three taps are opened simultaneously = 42 + 56 – 48 litres = 50 litres.

The tank gets completely filled in 16 hours. Capacity of the tank = 16 Ã— 50 = 800 litres. - Anu owes Biresh Rs 1120 payable 2 year hence, Biresh owes Anu Rs 1081.50 payable 6 months. If they decide to settle their accounts forthwith by payment of ready money and the rate of interest be 6% per annum, they who should pay and how much ?
Rs. 20, AnuRs. 80 AnuRs.50 , BrijeshRs. 60 , BrijeshRs. 40 BrijeshOption C

1120 – P = (P*6*2)/100

=>P = Rs. 1000

Present worth of money for Biresh 1081.50 – P

= P*6*1/2*100

=> 108150 – 100 P = 3P

P = Rs 1050

Biresh should pay Rs 50 - A bag contains 2 white balls, 3 black balls and 4 red balls. In how many ways can 3 balls be drawn from the bag, if at least one black ball is to be included in the draw?
4855506443Option D

Number of ways to select 3 black balls = 3C3

Number of ways to select 2 black balls and 1 non-black ball = 3C2 Ã— 6C1

Number of ways to select 1 black ball and 2 non-black balls = 3C1 Ã— 6C2

Total number of ways = 3C3 + 3C2 Ã— 6C1 + 3C1 Ã— 6C2 = 3C3 + 3C1 Ã— 6C1 + 3C1 Ã— 6C2

=1+3Ã—6+3Ã—6Ã—52Ã—1

=1+18+45

=64

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