Hello Aspirants

**State Bank of India (SBI)** is going to conduct examination for its recruitment for the post of Probationary Officers (SBI PO 2018) for a total of 2000 vacancies.

Click here to know the details of the Examination

The examination will be held in three phases i.e. Preliminary Examination, Main Examination and Group Exercise & Interview. The Preliminary Exam is scheduled onÂ **1st, 7th & 8th of July 2018. **Details of the exam are as under:

Practice the questions so as to familiarize yourself with the pattern of questions to be asked in the exam.Â

**Directions(1-5):** What should come at the place of question mark (?) in the following question?

- (0.76 * 0.76 * 0.76 â€“ 0.008)/(0.76 * 0.76 + 0.76 * 0.2 + 0.04) = ?
0.330.450.560.810.49Option C

(0.76 * 0.76 * 0.76 â€“ 0.008)/(0.76 * 0.76 + 0.76 * 0.2 + 0.04) = ?

= (0.438 -0.008)/(0.5776 + 0.152 + 0.04)

= (0.43)/0.7696

= 0.56 - 832/24 * 84/26 /252/72 = ?
2740352232Option E

832/24 * 84/26 /252/72 = ? = 32 - (4096)^2/3/ (65536)^3/4 * (16)^? = 4^4
37542Option A

(4096)^2/3/ (65536)^3/4 * (16)^? = 4^4

=> (16)^3*(2/3) / (16)^4*(3/4) * (16)^? = 16^2

=> (16)^(2-3) * (16)^? = 16^2

=> ? = 3 - 2(17/23) + 1(15/46) â€“ 3(27/92) = ? â€“ 6(13/23)
3(33/92)2(44/90)5(11/94)7(31/92)1(33/90)Option D

2(17/23) + 1(15/46) â€“ 3(27/92) = ? â€“ 6(13/23)

=> (2+1-3+6)(68+30-27+52)/92 = ?

=> 6(123/92) = ?

=> ? = 7(31/92) - (?)^2 + (65)^2 = (160)^2 â€“ (90)^2 â€“ 7191
8078667085Option B

(?)^2 + (65)^2 = (160)^2 â€“ (90)^2 â€“ 7191

=> (?)^2 = (160)^2 â€“ (90)^2 â€“ 7191 â€“ (65)^2

=> (?)^2 = 25600 â€“ 8100 â€“ 7191 â€“ 4225

=> ? = 78 - How many approximate Bank PO books were given to each distributor by publisher D, if all distributor distributes only bank PO books.
250300420399345Option D

No. of Bank PO books distributed by publisher D

= 34236 Ã— 63% = 21568.68 âˆ¼ 21569 * 7/18 = 8388

No. of books given to each distributor by publisher D = 8388/21

= 399 - The number of books distributed by F is how much percent more or less than the number of books distributed by C?
14.44%18.49%11.25%20.22%19.51%Option B

F = 21590 Ã— 76% = 16408

C = 25480 Ã— 79% = 20,129

Required answer = (20129-16408)/20129 x 100 = 18.49% - If the number of books distributed by publishers B, D & E are increased by 25% & the number of books distributed by publishers A, C & F are decreased by 30%. What will be the new average of books distributed by all the publishers?
1798115480188121623011745Option A

B = 13200 Ã— 84% = 11088

D = 34236 Ã— 63% = 21569

E = 27300 Ã— 82% = 22386

Books distributed by B, D and E = (11088 + 21569 + 22386 ) Ã— 125% = 68804

A = 21440 Ã— 90% = 19296

C = 25480 Ã— 79% = 20129

F = 21590 Ã— 76% = 16408

Books distributed by A, C and F = ( 19296 + 20129 + 16408 ) Ã— 70% = 39083

New average = (68804 + 39083)/6 = 17981 - If the number of distributors by publisher E was increased by 40% and if each publisher gets equal number of books, then the number of books each publisher got before increase in the number of distributor is how much percent more than the number of books each publisher got after increase in number of distributors?
40%20%60%50%30%Option A

No. of distributor = 35+40% of 35 = 35 + 14 = 49

No. of books each publisher got after 40% increase in number of distributors = = 27300/49 = 557

No. of books each publisher got before increase = 27300/35 = 780

Therefore, required percent = (780-557)/557 x 100 = 40% - If 55.55% of books distributed are of SSC by Publisher A and the number of defected books of SSC by publisher A are 9.11% of total no. of books distributed by Publisher E. Then find the approximate average number of distributed books of SSC which are not defected by publisher A and the number of books which are not distributed by publisher E?
67974450575066708250Option A

Total number of SSC books = 21440 x 9/16 = 12060

No. of distributed books by publisher A = 21440 x 90% = 19296

No. of books of SSC distributed by publisher A = 19296 x 55.55 % = 10719

No. of defected books of SSC by publisher A = 27300 x 82% x 9.11% = 2039

No. of distributed SSC books which are not defected by publisher A = 10719 â€“ 2039 = 8680

No. of books which are not distributed by publisher E = 27300 Ã— 18% = 4914

Average = (8690 + 4914)/2 = 6797

**Directions(6-10):** Study the following table carefully and answers the question.