Hello Aspirants

**State Bank of India (SBI)** is going to conduct examination for its recruitment for the post of Probationary Officers (SBI PO 2018) for a total of 2000 vacancies.

Click here to know the details of the Examination

The examination will be held in three phases i.e. Preliminary Examination, Main Examination and Group Exercise & Interview. The Preliminary Exam is scheduled onÂ **1st, 7th & 8th of July 2018. **Details of the exam are as under:

Practice the questions so as to familiarize yourself with the pattern of questions to be asked in the exam.Â

**Directions(1-5): **In the following questions, two equations numbered are given in variables x and y. You have to solve both the equations and find out the relationship between x and y.

- I. x
^{2}+ âˆš5x â€“ 10 = 0

II. 2y^{2}+ 9âˆš5y + 50 = 0x=y or relation cannot be established.x>=yx>yy>xy>=xOption

I. x^{2}+ âˆš5x â€“ 10 = 0

x^{2}+ âˆš5x â€“ 10 = 0

x^{2}+ 2âˆš5x â€“ âˆš5x â€“ 10 = 0

x = -2âˆš5, âˆš5

II. 2y^{2}+ 9âˆš5y + 50 = 0

2y^{2}+ 9âˆš5y + 50 = 0

2y^{2}+ 4âˆš5y + 5âˆš5y + 50 = 0

y = -2âˆš5, -5âˆš5/2

x â‰¥ y - I. 3x
^{2}+ 16x + 20 = 0

II. 3y^{2}â€“ 14y â€“ 5 = 0y>xx>yy>=xx>=yx=y or relation cannot be established.Option A

I. 3x^{2}+ 16x + 20 = 0

3x^{2}+ 16x + 20 = 0

3x^{2}+ 6x + 10x + 20 = 0

x = -2, -10/3

II. 3y^{2}â€“ 14y â€“ 5 = 0

3y^{2}â€“ 14y â€“ 5 = 0

3y^{2}â€“ 15y + y â€“ 5 = 0

y = -1/3, 5

x < y - I. 4x
^{2}+ 19x + 21 = 0

II. 2y^{2}â€“ 25y â€“ 27 = 0x>=yy>=xx>yy>xx=y or relation cannot be established.Option D

I. 4x^{2}+ 19x + 21 = 0

4x^{2}+ 19x + 21 = 0

4x^{2}+ 12x + 7x + 21 = 0

x = -3, â€“ 1.75

I. 4x^{2}+ 19x + 21 = 0

2y^{2}â€“ 25y â€“ 27 = 0

2y^{2}â€“ 27y + 2y â€“ 27 = 0

y = 13.5, -1

x < y - I. 2x
^{2}â€“ 9x + 4 = 0

II. 2y^{2}+ 7y â€“ 4 = 0y>=xx>=yx=y or relation cannot be established.y>xx>yOption B

I. 2x^{2}â€“ 9x + 4 = 0

2x^{2}â€“ 9x + 4 = 0

2x^{2}â€“ 8x â€“ x + 4 = 0

x = 4 , 1/2

II. 2y^{2}+ 7y â€“ 4 = 0

2y^{2}+ 7y â€“ 4 = 0

2y^{2}+ 8y â€“ y â€“ 4 = 0

y = -4, Â½

x â‰¥ y - I. 3x
^{2}+ 16x + 20 = 0

II. 3y^{2}+ 8y + 4 = 0x>yx=y or relation cannot be established.y>xy>=xx>=yOption D

I. 3x^{2}+ 16x + 20 = 0

3x^{2}+ 16x + 20 = 0

3x^{2}+ 6x + 10x + 20 = 0

x = -10/3, -2

II. 3y^{2}+ 8y + 4 = 0

3y^{2}+ 8y + 4 = 0

3y^{2}+ 6y + 2y + 4 = 0

y = -2, -2/3

x â‰¤ y - The cost of one kg of guava in Jalandhar is approximatelywhat per cent of the cost of two kg of grapes in Chandigarh?
42%25%40%30%34%Option E

Cost of one kg of guava in Jalandhar = 60

Cost of two kg of grapes in Chandigarh = 90 Ã— 2 = 180

Required % = 60/180 Ã— l00 =1/3 Ã— l00

= 33.33 = 34% (approx.) - In which city is the difference between the cost of one kg of apple and the cost of one kg of guava the second lowest?
JalandharHoshiarpurDelhiJalandharRoparOption C

Cost of one kg apple in Jalandhar = 160 Cost of one kg guava in Jalandhar = 60

Difference = 160 – 60 = 100

Similarly, in Delhi = (130 – 90) = 40

In Chandigarh = (180 – 120) = 60

In Hoshiarpur = (90 – 30) = 60

In Ropar = `(40 – 20) = 20

Hence, the second lowest difference between price of one kg apple and one kg guava is in Delhi. - What is the ratio of the cost of one kg of apples from Ropar to the cost of one kg of grapes from Chandigarh?
1:35:72:34:92:5Option D

Required ratio = 40/90 = 4/9 - What total amount will Ram pay to the shopkeeper for purchasing 3 kg of apples and 2 kg of guavas in Delhi?
440570510405400Option B

Total amount = 3 Ã— 130 + 90 Ã— 2

= 390 + 180

= 570 - Ravinder had to purchase 45 kg of grapes from Hoshiarpur. The shopkeeper gave him a discount of 4% per kg. What amount did he pay to the shopkeeper after the discount?
80008208770080088200Option B

Cost of 45 kg grapes in Hoshiarpur = 45 Ã— 190

= 8550

After 4% discount, cost price of grapes = 8550 – 8550 Ã— 4 /100

= 8550 – 342

= 8208

Hence, Ravindar had to pay 8208

**Directions(6-10):** Study the following graph carefully to answer the questions that follow: