Hello Aspirants

**State Bank of India (SBI)** is going to conduct examination for its recruitment for the post of Probationary Officers (SBI PO 2018) for a total of 2000 vacancies.

Click here to know the details of the Examination

The examination will be held in three phases i.e. Preliminary Examination, Main Examination and Group Exercise & Interview. The Preliminary Exam is scheduled on **1st, 7th & 8th of July 2018. **Details of the exam are as under:

Practice the questions so as to familiarize yourself with the pattern of questions to be asked in the exam.

**Directions(1-5):** What will come in place of question mark ‘?’ in the given expression?

- 534.596 + 61.472 – 496.708 = ? + 27.271
66807293104Option C

534.596 + 61.472 – 496.708 = ? + 27.271

=> ? = 27.271 – 534.596 – 61.472 + 496.708

=> ? = 72.089 ==72 - 56% of 958 + 67% of 1008 = ?% of 2000
5033456177Option D

56% of 958 + 67% of 1008 = ?% of 2000

=>536.48 + 675.36 = ?% of 2000

=> ? = 1211.84/20

=> ? = 60.592 == 61 - (?)² + (23)² = (106)² – (46)² – 133
66111758792Option E

(?)² + (23)² = (106)² – (46)² – 133

=>?^2 = 11236 – 2116 – 133 – 529

=> ?^2 = 8458

=> ? = 92 - 515.15 – 15.51 – 1.51 – 5.11 – 1.11 =?
491.91371.11481.91391.11291.91Option A

515.15 – 15.51 – 1.51 – 5.11 – 1.11 =?

=>? = 491.91 - 811.81 + 88.11 + 0.88 + 1.88 + 8 = ?
888911845900922Option B

811.81 + 88.11 + 0.88 + 1.88 + 8 = ?

=> ? = 910.68 == 911 - Mixture A contains milk and water in the ratio of 3:2 . Another mixture B, containing milk and water in the ratio is 5:1 , is mixed with mixture A such that the ratio of the milk and water in the resultant mixture becomes 2:1 . If the quality of mixture B is 18 litres, then find the quantity of mixture A .
40 l25 l30 l52 l45 lOption E

Let the quantity of milk and water in mixture B be 5y and 1y litres resp.

5y + y = 18

=> 6y = 18

=> y = 3

The quantity of milk in B = 15 litres

The quantity of water in B = 3 litres

Now, [3x+15]/[2x+3] = 2/1 => x = 9litres

Hence , the quantity of mixture A = 3x+2x = 27 + 18 = 45 litres - A train running at a speed of 54 km/hr. crosses a man standing on the platform in 28 seconds. What would be the length of the platform which is 33.33% more than the length of the train?
620 m500 m560 m660 m440 mOption C

Length of the train = 15 * 28 = 420 m

Length of the platform = 420 + 33.33% of 420

= 560 m - In an examination, a student scores 4 marks for every correct answer and loses 1 mark for every wrong answer. A student attempted all the 200 questions and scored in all 200 marks. Find the number of questions, he answered correctly .
10090708060Option D

Let the number of corrected answers be ‘x’.

Number of wrong answers be 200−x

4x− (200−x) =200

=>5x=400

=>x=80 - Mrs. Sharma invests 15% of her monthly salary, i.e., Rs. 4428 in Mutual Funds. Later she invests 18% of her monthly salary on Pension Policies also she invests another 9% of her salary on Insurance Policies. What is the total monthly amount invested by Mrs. Sharma?
Rs.10390.3Rs.12398.4Rs.11300.5Rs.12250.4Rs.12520.5Option B

15% → 4428

1% →4428/15

( 15+18+9) =42%

→4428/15×42 → Rs.12398.4 - A bag contains 10 coins of different values (Re.1, Rs.2 and Rs.5). If the probability of drawing a Rs.2 coin from the bag is 1/5 and the number of Re.1 coin is equal to the number of Rs.5 coins, then find the probability that each coin is of different value when three coins are drawn randomly.
7/132/111/154/154/11Option D

Number of 10 coins in the bag = 10

Number of Rs.2 coins in the bag = 1/5*10 = 2

Let the number of Re.1 coins be x.

Then, x+x+2 = 10

=> 2x = 8

=> x = 4

Number of Re.1 coin = 4

Number of Rs.5 coin = 4

Number of Rs.2 coin = 2

Required probability = (2C1+4C1+4C1)/10C3 = 4/15